similar to: remove a row from a dataframe, row names disappear

Thank you Sarah.I'm glad it was a quick fix: On Fri, Feb 5, 2010 at 8:50 AM, Sarah Goslee <> wrote: > You're not only removing a row of data, you are invoking the default > behavior of subset, which is to collapse the subsetted result to the > smallest possible type, which in this case is a vector. Vectors have > no rows, and thus no row names. > > You need the

I'm a week-old R user, and have become stuck trying to create usable CSV outputs for post-processing. I am using the package Rioja, which provides small datasets of results. I am running several analyses in a loop and iteratively adding the results to a *list* ("combined"). Within each iteration I use the following: > combined[[i]] <- performance(fit) With two iterations I

I have the following small dataset: > stardata NS HE EB CW RW PW 1 0 0.000 0.000 0.042 0.006 0 2 0 0.006 0.000 0.013 0.005 0 3 0 0.000 0.011 0.000 0.000 0 I have plotted the star diagrams as follows: stars(stardata, key.labels = dimnames(stardata)[[2]], labels = NULL, key.loc = NULL, draw.segments=TRUE, col.segments="gray", lty="blank") I am

Using the maptools function "map2poly" I have created a map/polylist object - a map of the Great Lakes. My goal is to passively plot additional data on this map. Unfortunately I am not able to change (distort) the relative scale of the axes for the map, and so the sample points do not line up correctly on the map. In the code below, notice that I have set the same axis ranges on each

I would like to revisit a problem that was discussed previously (see quoted discussion below). I am trying to do the same thing, using a string to indicate a column with the same name. I am making "foo" a string taken from a list of names. It matches the row where "item" = 5, and picks the corresponding "taxon" > foo <- list$taxon[match(5,list$item)] Let's

I have the following data frame: > algaedata = year DIV cellsperml 2001 BAC 72.808 2001 CHL 3.273 2002 BAC 14.002 2002 CYA 220.896 2002 UNI 464.699 2003 BAP 0 2003 BAC 1.782 2004 CYA 315.799 2005 UNI 222.532 2005 BAP 0.2 2005 CYA 163.627 2005 BAC 324.949 2006 CHL 1.636 2006 BAC 199.145 2007 CHL 19.635 2007 CYA 134.174 2007 BAC 485.405 2007 CHL 11.454 2007 CYA 104.721 ...which makes a fine

I''m looking for a way to backup my entire system, the rpool zfs pool to an external HDD so that it can be recovered in full if the internal HDD fails. Previously with Solaris 10 using UFS I would use ufsdump and ufsrestore, which worked so well, I was very confident with it. Now ZFS doesn''t have an exact replacement of this so I need to find a best practice to replace it.

On 10/09/13 14:09, Thomas Goirand wrote: > On 09/10/2013 03:17 PM, St?phane Glondu wrote: >> Le 06/09/2013 10:14, Thomas Goirand a ?crit : >>> I wrote it many time to many people. Please don't just read 1.6 as "new >>> upstream release" for XCP. That's unfortunately not the way it works. >>> Upstream version for Debian and the one they do for

Hi All, I am looking for the Rsync binary for NT as mentioned on the Mike McHenry postings. Unfortunatley the ftp mentioned in the article wont accept anonymous login. TIA, Euan Clark -------------- next part -------------- HTML attachment scrubbed and removed

I am trying to produce rather mundane output of the form e.g. pi, e = 3.14 2.718 The closest result I achieved so far with print() is: > print (c(pi, exp(1)), digits = 3) [1] 3.14 2.72 > print(c("pi, e =", pi, exp(1)), digits = 3) [1] "pi, e =" "3.14159265358979" "2.71828182845905" I understand that c() promotes floats to strings and

On 09/10/2013 03:17 PM, St?phane Glondu wrote: > Le 06/09/2013 10:14, Thomas Goirand a ?crit : >> I wrote it many time to many people. Please don't just read 1.6 as "new >> upstream release" for XCP. That's unfortunately not the way it works. >> Upstream version for Debian and the one they do for CentOS are >> different, and just using upstream 1.6

Le 06/09/2013 10:14, Thomas Goirand a ?crit : > I wrote it many time to many people. Please don't just read 1.6 as "new > upstream release" for XCP. That's unfortunately not the way it works. > Upstream version for Debian and the one they do for CentOS are > different, and just using upstream 1.6 doesn't cut it. It needs to be > ported to Debian, and that's

Seth Forshee noticed a performance degradation with some workloads. This turns out to be due to packet drops. Euan Kemp noticed that this is because we drop all packets where length exceeds the truesize, but for some packets we add in extra memory without updating the truesize. This in turn was kept around unchanged from ab7db91705e95 ("virtio-net: auto-tune mergeable rx buffer size for

Seth Forshee noticed a performance degradation with some workloads. This turns out to be due to packet drops. Euan Kemp noticed that this is because we drop all packets where length exceeds the truesize, but for some packets we add in extra memory without updating the truesize. This in turn was kept around unchanged from ab7db91705e95 ("virtio-net: auto-tune mergeable rx buffer size for

Hi, how can I print "<=" (I mean the symbol of just one character) in the main title of a plot? for example: plot(1:10, main=paste("x <=", x)) where variable x is some number generated on the fly. Thanks John

# I have a question about how factanal is calculating the regression factor # scores based on an oblique rotation (promax) of the factors. # # As is explained in the help file, regression factor scores are # obtained as # # hat f = Lambda' Sigma^-1 x # # However, according to Harman's "Modern Factor Analysis" (e.g. second # edition, pp. 351-352) the formula is # # hat f = Phi

Package: ftp.debian.org Severity: normal Hi, Writting this message saddens me, but no choice... Because upstream authors (eg: Citrix) have explained that they cannot maintain the current version of XenAPI, or upgrade it to a newer version, we have no choice but to remove completely XenAPI from both Unstable and Testing. Quoting Euan Harris from Citrix (it's not needed for the FTP masters

Dear all, Does any one knows why should I get the following error message, when trying to do a simple data.frame?? DataF<-data.frame(Subject,BiomR,Spp,Capas,Litter,Herbs,LitterD,MaxCanH,DDifS p,DSSp,Slope, CanDens,NearestSp) Erro em data.frame(Subject, BiomR, Spp, Capas, Litter, Herbs, LitterD, : arguments imply differing number of rows: 202, 0 The data I am using

I have some time series data like 01/02/1990 0.531 0.479 01/03/1990 0.510 0.522 01/06/1990 0.602 0.604 there is no weekends and holidays. how do I graph them in a single plot that the x-axis is the dates and the y-axis is the time series? Thank you Regards, Jincai Jiang (Office) 212-761-3984 -------------------------------------------------------- This is not an offer (or solicitation

This command cdmoutcome<- glm(log(value)~factor(year) > +log(gdppcpppconst)+log(gdppcpppconstAII) > +log(co2eemisspc)+log(co2eemisspcAII) > +log(dist) > +fdiboth > +odapartnertohost > +corrupt > +log(infraindex) > +litrate > +africa >