similar to: evaluating expressions with sub expressions

Consider the following example: # substitute a with b in the indicated function. Seems to work. > z <- substitute( function()a+1, list(a=quote(b)) ) > z function() b + 1 # z is an object of class call so use eval # to turn it into an object of class expression; however, # when z is evaluated, the variable a returns. > eval(z) function()a+1 Why did a suddenly reappear again

I have a 'named expression' like expr <- expression(rep(1,d)) and would like to replace the argument d with say 5 without actually evaluating the expression. So I try substitute(expr, list(d=5)) in which case R simply returns expr which when I 'evaluate' it gives eval(expr) Error in rep.default(1, d) : invalid number of copies in rep() I've looked at ?substitute and

Hello R Community, I don't post to these things often so excuse me if I stumble on my forum etiquette. This is a complex problem for me, which may require two forum entries, but I will try my best to be concise. Also, I am a self taught coder, so if my code is not to convention, your constructive criticism is always welcome. I need to split up a data frame by participant (gpsarc -

Hello, I'm am in the process of trying to port a RATS functions to R and have the problem, that RATS allows for the creation of submatrixes that are linked to their basematrix. Basically it should work like this: a = matrix(1:(4*3),4,3) a # [,1] [,2] [,3] # [1,] 1 5 9 # [2,] 2 6 10 # [3,] 3 7 11 # [4,] 4 8 12 # This of course doesnt work :) b =

Hello, I have the following data.frame structure(list(Study = structure(c(1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 13L, 14L, 15L, 16L, 17L, 18L, 19L, 1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 13L, 14L, 15L, 16L, 17L, 18L, 19L, 1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 13L, 14L, 15L, 16L, 17L, 18L, 19L, 1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 13L, 14L,

We were looking at conducting a pilot program with Dell to virtualize our lab environments. We are specifically looking at Dell/Citrix provisioning servers. The OS in this setup is streamed from the server on every boot. I was curious if the R Project had any licensing stipulations in this type of setup. This is in the beginning phases and we wanted to answer some questions about licensing.

Dear useRs, I am using the gamm function in the mgcv package to model a smooth relationship between a covariate and my dependent variable, while allowing for quantification of the subjectwise variability in the smooths. What I would like to do is to make subjectwise predictions for plotting purposes which account for the random smooth components of the fit. An example. (sessionInfo() is at

I'm studying lists and I came to an example where > L $name [1] "Fred" $wife [1] "Mary" $no.children [1] 4 $child.ages [1] 4 7 9 then following the instructions to extend the list with a new component, I executed: > L[5] <-list(NewName="something") and the new list I got was: > L $name [1] "Fred" $wife [1] "Mary"

Hi, We wrote an optimization that eliminates common sub-expressions in a group of similar GEPs for the NVPTX backend. It speeds up some of our benchmarks by up to 20%, which convinces us to try to upstream it. Here's a brief description of why we wrote this optimization, what we did, and how we did it. Loops in CUDA programs are often extensively unrolled by programmers and compilers,

There was a BioConductor thread today where the poster wanted to find pairwise difference between columns of a matrix. I suggested the slow solution below, hoping that someone might suggest a faster and/or more elegant solution, but no other response. I tried unsuccessfully with the apply() family. Searching the mailing list was not very fruitful either. The closest I got to was a cryptic chunk

Hi, I am trying to use quantile regression to perform weighted-comparisons of the median across groups. This works most of the time, however I am seeing some odd output in summary(rq()): Call: rq(formula = sand ~ method, tau = 0.5, data = x, weights = area_fraction) Coefficients: Value Std. Error t value Pr(>|t|) (Intercept) 45.44262 3.64706 12.46007

What is the simplest way to extract a matched subexpression? Eg. in perl you can do "hello world" =~ m/hello (.*)/ which would return 1(true) and set $1 to the matched subexpression "world". -- View this message in context: http://n4.nabble.com/regular-expression-submatch-tp1459146p1459146.html Sent from the R help mailing list archive at Nabble.com.

Hello. I'm trying to find a way in R to calculate between and within subject variances and confidence intervals for some analytical method development data. I've found a reference to a method in Burdick, R. K. & Graybill, F. A. 1992, Confidence Intervals on variance components, CRC Press. This example is for Balanced Data confidence interval calculation from Pg 62. The data are

Hi I have 3 vectors, say g1, g2 and f, where g1 and g2 contain the row and column indices of a matrix, with corresponding elements in f. How can I create a matrix containing the values in f ? For example: g1 g2 f 3 4 10 2 1 30 4 4 50 How can then get a matrix that looks as follows: 0 0 0 0 30 0 0 0 0 0 0 10 0 0 0 50 I am still learning R. I think reshape will

Sub and gsub treat \\ replacement pattern incorrectly I expect sub("a","\\", "a", perl=T) to produce [1] "\" instead it generates [1] "" On the other hand, if I run sub("a","\\\\", "a", perl=T) it correctly outputs [1] "\\" The same issue applies to gsub. --please do not edit the information

Hi Hal, Thanks for your comments! I'm inlining my responses below. Jingyue On Sat, Apr 19, 2014 at 6:38 AM, Hal Finkel <hfinkel at anl.gov> wrote: > Jingyue, > > I can't speak for the NVPTX backend, but I think this looks useful as an > (optional) target-independent pass. A few thoughts: > > - Running GVN tends to be pretty expensive; have you tried EarlyCSE

Dear all, I am trying to construct 25x31 different matrices of 2x2 dimension. Here is the problem: we have the following matrix matrix(c(54+s0, 43+s1, 56-s0, 67-s1), nrow=2, ncol=2, byrow=T) the values for s0 and s1 are c(0:24) and c(0:31), respectively. I wrote the following code without the desired results

I need to apply a yearly inflation factor to some wages and supply some simple sums by work category. I have gone at it with a brute force "for" loop approach which seems okay as it is a small dataset. It looks a bit inelegant and given all the warnings in the Intro to R, etc, about using loops I wondered if anyone could suggest something a bit simpler or more efficent? Example:

If I have a dataframe which is organized like this: name color likes? 1 sally red 0 2 sally blue 1 3 sally green 1 4 jake red 0 5 jake blue 1 6 jake green 1 7 tom red 1 8 tom blue 0 9 tom green 0 And I want to create a matrix in the form: red blue green sally 0 1 1 jake 0 1 1 tom 1 0 0 Are there any built-in

Hello R guru's I am a newbie to R, In my research work I usually generate a lot of ELISA data in form of absorbance values. I ususally use Excel to calculate the concentrations of unknown, but it is too tedious and manual especially when I have 100's of files to process. I would appreciate some help in creating a R script to do this with minimal manual input. s A1-G1 and A2-G2 are