similar to: a question about deleting rows

hello: I have 3 data.frame objects. First df object: Of dim (149,31). Columns 2:31 are marked as T1..T14 and N1..N16. Name T1 T2 N1 T3 N2 N3 N4 T4 mu1 10 10 9 10 9 9 8 10 mu2 11 11 9 11 9 9 9 11 ... muN 12 12 9 11 9 9 8 12 Second df object: of Dim (50000,31). Columns 2:31 are maked as T1...T14 and N1..N16.

Hi all, I'm working on a target whose registers have equal-sized subregisters and all of those subregisters can be named (or the other way round: registers can be grouped into super registers). So for instance we've got 16 registers W (as in wide) W0..W15 and 32 registers N (as in narrow) N0..N31. This way, W0 is made by grouping N0 and N1, W1 is N2 and N3, W2 is N4 and N5, ..., W15 is

Hello R-Group I found how to fill the data.frame -> http://finzi.psych.upenn.edu/R/Rhelp02a/archive/70843.html N1 <- rnorm(4) N2 <- rnorm(4) N3 <- rnorm(4) N4 <- rnorm(4) X1 <- LETTERS[1:4] ################### nams <- c(paste("N", 1:4, sep = ""), "X1") dat <- data.frame(lapply(nams, get)) names(dat) <- nams dat But I need also to create

Hi, I have a data.frame as following: var1 var2 1 ab_c_(ok) 2 okf789(db)_c 3 jojfiod(90).gt 4 "ij"_(78)__op 5 (iojfodjfo)_ab what I want is to create a new variable called "var3". the value of var3 is the content in the Parentheses. so var3 would be: var3 ok db 90 78 iojfodjfo how to do this? thanks, karena --

I need to create 10 matrices. say matrix 1-10. matrix_1 is 1 by 1 matrix_2 is 2 by 2 matrix_3 is 3 by 3 . . . matrix_10 is 10 by 10 I am just wondering if there are some functions in R that are similar to the macro variables in SAS. so I can create these 10 matrices by doing: for (i in 1: 10) { matrix_$i <- matrix(nrow=i, ncol=i) } rather thank creating these matrices one by one

Hi, I've got a quite tricky question. I have a txt file, named 'temp.txt', as the following: snp1 snp2 snp3 AA 00 00 GG GG 00 00 AA 00 I want to read the file into R. 1) when I use 'read.table' without 'header=T' option, > temp <- read.table('temp.txt') # I got > temp V1

I have a data.frame as the following: var1 var2 9G/G09 abd89C/T90 10A/T9 32C/C 90G/G A/A . . . . . . 10T/C 00G/G90 What I want is to get the letters which are on the left and right of '/'. for example, for "9G/G09", I only want "G", "G", and for "abd89C/T90", I only want "C" and

Greeting R helpers J I am not familiar with R but I have to use it to analyze data set that I have (30,000 20,000) I want to change the structure of the dataset and I am wondering how that might be possible in R A main data looks like this: some entities are empty Age No. Age No. Age No. Center1 5 2 8 7

Following is a function that I wrote (It is working well). It's a simple one, nothing complicated. The only question that I have is a qutation mark issue, I guess. ############################################# funcname <- function(trait.file){ #line1 setwd('/root/subroot') # line 2 load('imge.RData')

Hi all, I am working on my Master's project in security and I am trying to iterate over the argument list of the function. Basically I need to do following things : 1. Check data type of each argument of the argument list of the function. 2. Based on its data type like character array or integer array, pointer, int, char, take different action. 3. I have added following code to check its

Hi Dear all, I am making Venn Diagram plots in R. I attached an example: http://r.789695.n4.nabble.com/file/n3919206/venn.jpeg I want to get rid of the black boarder line, is there any way to do it? Thank you very much, Karena -- View this message in context: http://r.789695.n4.nabble.com/A-questions-regarding-R-plots-tp3919206p3919206.html Sent from the R help mailing list archive at

I have a question about the "write.table" I have 100 data.frames, loci1, loci2, loci3.............,loci100. now, I want to print these data.frames to 100 separate files, and the names of the files are also loci1, loci2, loci3,......., loci100. how to perform this under a "for" loop? say, for (i in 1:100) { write.table(...., file='...', ........) } thank you,

Hi, I have a question about the data handling. I have a dataset as following: ID snp1 snp2 snp3 1001 0/0 1/1 1/1 1002 2/2 3/3 1/1 1003 4/4 3/3 2/2 I want to convert the dataset to the following format: ID snp1 snp2 snp3 1001 00 AA AA 1002 GG

Hi, I want to generate multiple sets of random numbers. The requirement is that: 1) each set have 3 random numbers; 2) the sum of the three number is always 1. how to do this? thank you, karena -- View this message in context: http://r.789695.n4.nabble.com/Random-number-generation-tp3685463p3685463.html Sent from the R help mailing list archive at Nabble.com.

Dear Bert, thank you for your response. here it is the piece of R code : given 3 data frames below --- N <- data.frame(N=c("n1","n2","n3","n4")) M <- data.frame(M=c("m1","m2","m3","m4","m5")) C <- data.frame(n=c("n1","n2","n3"),

hi, I have a question about importing data in R. I want to import a file which has missing value in it, and the missing values are denoted as ".", I want to first read in the file, and then change the "." into the number zero "0". how can I do that? thank you, karena -- View this message in context:

Hi Bogdan, Kinda messy, but: N <- data.frame(N=c("n1","n2","n3","n4")) M <- data.frame(M=c("m1","m2","m3","m4","m5")) C <- data.frame(n=c("n1","n2","n3"), m=c("m1","m1","m3"), I=c(100,300,400))

> On Jun 6, 2017, at 4:01 AM, Jim Lemon <drjimlemon at gmail.com> wrote: > > Hi Bogdan, > Kinda messy, but: > > N <- data.frame(N=c("n1","n2","n3","n4")) > M <- data.frame(M=c("m1","m2","m3","m4","m5")) > C <-

I have a data.frame as follows: v1 v2 v3 v4 v5.....v100 1 1 0 0 1 2 2 1 2 1 0 1 1 1 1 2 1 0 . . . . . . . . . . . . 1 2 2 1 1 0 so for this data set, what I wanna do is to replace all the

Hi, how can I create an array of lists of three components? This approach does not work: n1 <- 2 n2 <- 4 n3 <- 5 res <- array(rep(vector("list",3), n1*n2*n3), dim = c(n1,n2,n3)) res[1,1,1] # is not a list with three components... The goal is that res[1,1,1] is a list with three components. Also, appending the components didn't work. For example, I tried: component