similar to: need a solution to an R-problem: consultant available?

note: whole function is below- I am sure I am doing something silly. when I use it like USGS(input="precipitation") it is choking on the precip.1 <- subset(DF, precipitation!="NA") b <- ddply(precip.1$precipitation, .(precip.1$gauge_name), cumsum) DF.precip <- precip.1 DF.precip$precipitation <- b$.data part, but runs fine outside of the function: days=7

Look at the bottom of the message for my question #here is a little function that I wrote USGS <- function(input="discharge", days=7){ library(chron) library(gsubfn) #021973269 is the Waynesboro Gauge on the Savannah River Proper (SRS) #02102908 is the Flat Creek Gauge (ftbrfcms) #02133500 is the Drowning Creek (ftbrbmcm) #02341800 is the Upatoi Creek Near Columbus (ftbn) #02342500 is

Hi, I am having trouble with the function process.AP in the ActivPALProcessing package. Based on the detailed instruction attached by the author, it is my understanding that process.AP will use the information provided in the log of subjects to batch process AP events files saved in the working directory. Results of the batch processing will be summarized in three files: 1) Sleep Wake Wear

Dear R Users,i am very new to R. I want your help on an issue regarding distance matrix and cluster analysis i had discharge data of 4 rivers(a,b,c,d) in 4 vectors each having 364 values > dput(qmu)structure(list(a = c(0.26, 0.25, 0.25, 0.25, 0.24, 0.23, 0.22, 0.21, 0.21, 0.21, 0.2, 0.19, 0.19, 0.19, 0.19, 0.18, 0.18, 0.18, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17,

i have the following constructed and running very well,, thanks to Gabor Grothendieck for his help. >data.info <- c("station.id", "year", "date", "max.discharge") > > for(i in 1:num.files) { + station.id <- substring(data[i], 1,8) + DF <- read.table(data[i], sep=",", blank.lines.skip = TRUE) + z <- zoo(DF[,4],

I'm trying to make sure my R package will install properly (build help files, etc) and when I try to run the rcmd check (or any rcmd option) I get the following error. Does dcf.pm stand for perl module? If not, why do I get this message? C:\systemfit\r_code>rcmd check --help Can't locate R/Dcf.pm in @INC (@INC contains: c \PROGRA~1\r\rw1041\share\perl; /usr/lib/perl5/5.6.1/cygwin-multi

I'm getting an error that I don't understand when trying to rearrange my data columns with cbind. My data is in 27 columns, like so: > data <- read.table("CalledFeatsNimblegen.csv", header=T, sep=",") > names(data) [1] "MF_not_mC" "MF_promoter" "MF_genebody" "FF_not_mC" [5]

Hi, Try this: el<- read.csv("el.csv",header=TRUE,sep="\t",stringsAsFactors=FALSE) ?elsplit<- split(el,el$st) ? datetrial<-data.frame(date1=seq.Date(as.Date("1930.1.1",format="%Y.%m.%d"),as.Date("2010.12.31",format="%Y.%m.%d"),by="day")) elsplit1<- lapply(elsplit,function(x)

Hi Elisa, You need to check your data.? For some 'st', the data is repeated/duplicated (I am assuming, didn't check it) especially for a particular year. dat1<-read.csv("elisa.csv",sep="\t") dat1$st<- as.character(dat1$st) ?str(dat1) #'data.frame':??? 506953 obs. of? 5 variables: # $ st?????? : chr? "AGOMO" "AGOMO"

I have a data set of mean velocity, discharge, and mean depth. I need to find out which model best fits them out of log linear, linear, some other kind of model... Using excel I have found that linear is not that bad and log10(discharge) vs. the other two variables (I am trying to predict velocity and depth from discharge) is not that bad either. How do I test and see which one of these models

Hi Y'all, I am using the text mining package (tm). I am trying to filter out all of the words in a Term Document Matrix that are not in a list of words that I am interested in. I am using the following code: z<-tm_intersect(txt.dtm, c("communications", "safety", "climate", "blood", "surface", "cleanliness",

hi everyone! hope you can help me here. i am a new R user. what i am trying to do is to find the maximum annual discharge from a daily record. i have a data.frame which includes date and the discharge. somewhat like this.. 10/1/1989 2410 10/2/1989 2460 10/3/1989 2890 ... ... ... 12/31/2005 5730 i have been browsing through the archives and fount out about the aggregate

Hi, I am trying to create a loess smooth from hydrologic data. My goal is to create a smooth line that describes discharge at a certain point in time. I have done this using the 'lowess' function and had no problem, but I'm having some difficulty with loess. I am inputting the date ('date') and discharge ('q') values using the 'scan' function, then inputting

On Thu, May 28, 2015 4:25 pm, Gordon Messmer wrote: > On 05/28/2015 11:13 AM, Valeri Galtsev wrote: >> >> I do not want to start "software" vs "hardware" RAID wars here > > I'm not saying that hardware RAID is bad, entirely. Software RAID does > have some advantages over hardware RAID, but my point has been that > 3ware cards, specifically, are

On Dec 18, 2014, at 9:16 AM, Frantz de Germain <frantz at info.univ-angers.fr> wrote: > What is the difference between "test.battery.start.deep" and > "test.battery.start.quick" command (upscmd) ? The intent for the quick test is to only discharge the battery a little bit, whereas the deep test would discharge until the low battery threshold is reached (or the

Hi, I am new to lattice graphics and have the following question. I have a dataframe d2: cat PointsInTime MeanScore 1 Parent Intake 26.25000 2 Youth Intake 9.75000 3 Worker Intake 20.63636 4 Parent Discharge 24.00000 5 Youth Discharge 15.60000 6 Worker Discharge 23.90909 and to produce a plot I am using the following code print(xyplot(MeanScore ~

OK. I'll try it, but it really puzzles me how the battery could have gone bad for just 15 months. The online power is pretty stable, so the battery hasn't gone through many charge/discharge cycles... Regards, -- Georgi On 11.1.2020 at 14:24, Manuel Wolfshant wrote: > > indicates that the UPS thought that battery was close to depleted and decided to shutdown. I suggest to fully

Dear all, I'm using the curve() function to plot discharge Q against water depth a. However, I would like to have a graph of water depth a plotted against discharge Q. How can this be done? Minimal working example: S0 = 0.004 n = 0.04 tanalpha = 1.4/1.5 par(mar = c(5,5,1,1)) # b, l, t, r

Hello, In R I am trying to use Kalman filtering to find a solution for an hydrological problem. With Kalman Filtering I want to estimate the discharge comming from three storage bassins. I have programmed a function in R which can run KalmanSmooth. When I'm asking for the function and putting in values, R detects the following error: "Error in as.vector(data) : Argument "S1" is

I have trying to figure this out all day so hopefully the answer isn't too obvious. I am able to view a graph in the viewer window. However, I need to export graph outside of the viewer window. Here is the script I am using: > png("Compare.png") > plot(compare$DepthSLI, compare$DischargeSLI, col="blue", xlab = "Average Water Depth (cm)", ylab =