similar to: Two-way/Three-way sum.

Ok so I see the problem that I'm having creating a new variable (LAG1DBC) in the example data transformation below is that tapply() is creating a list that is not dimensionally consistent with the data frame (data). So how do I go from the list output of tapply() to create a dimensionally consistent vector that can create the new variable in my original data frame? I've been trying

I HAVE BEEN ASKED TO BE REMOVED FROM THIS LIST OVER 20 TIMES, PLEASE CAN I BE REMOVED!!!!!!!!!!!!! --- On Thu, 3/12/09, Peng Cai <pengcaimaillist@gmail.com> wrote: From: Peng Cai <pengcaimaillist@gmail.com> Subject: Re: [R] Help: barchart() {Lattice} To: "Felix Andrews" <felix@nfrac.org> Cc: r-help@r-project.org Received: Thursday, 3 December, 2009, 10:17 AM Got it

Hi R Users, I'm trying to plot a stacked barplot. Here is data: Sample Col1 Col2 Col3 Row1 -2 4 -1 Row2 3 -2 4 Row3 3 5 -2 Row4 4 1 -1 I'm using following R code: library(lattice) dta<-read.table("data.txt", header=TRUE, row.names="Sample") barchart(data.matrix(dta), horizontal=FALSE, stack=TRUE, col=2:4,

Hello I have a dataframe that looks like this MSA CITY HIVEST YEAR YR CAT 1 0200 Albuquerque 0.50 1996 1996 5 2 0520 Atlanta 13.00 1997 1997 5 3 0720 Baltimore 29.10 1994 1994 1 4 0720 Baltimore 13.00 1995 1995 5 5 0720 Baltimore 3.68

Hi All, I'm trying to use expression() for y-label in plot(). I'm not able to write Average(space)PM(subscript)10. I'm trying: ylab=expression(Average PM[10]) and its not working, because of a space between "Average" and "PM". Thanks, Peng [[alternative HTML version deleted]]

Hi All, I'm trying to write "ug/m3" as y-label, with greek letter "mu" replacing "u" AND "3" going as a power. These commands works in general: plot.new() text(0.5, 0.5, expression(symbol("m"))) But, I'm sure about how to do it using barchart() from "Lattice". Can anyone help please? Thanks, Peng Cai [[alternative HTML

Hi All, I'm trying to get following but not successfully: # this works okay ylab=expression("PM2.5 Concentration ("*mu*g/m^3*")") # But I need "2.5" as a subscript to PM and below this an additional line saying some text, like. ylab=expression("PM[2.5] Concentration ("*mu*g/m^3*")"\n(random text in brackets)) Square brackets doesn't

Hi all, I have the folowing frame(there are more columns than shown), 1 2 3 4 5 Year Total Tus Whi Norw 1994 1.00 1830 0 355 1995 1.00 0 0 0 1995 1.00 0 0 0 1995 1.00 4910 4280 695 1997 1.00 0 0

Hi useRs! I would like to know how to make aggregated data.frame with aggregate() tabulated. For example, I run the following command to aggregate re with respect to group1 and group2. > (aggr <- with(final, aggregate(re, group1, group2, mean))) Group.1 Group.2 x 1 1992 15 0.16392 2 1993 15 0.15467 3 1994 15 0.15456 4 1995 15 0.15391

Dear all I'm a newbie regarding netcdf data. Today I realized that I maybe do not understand some basics of the netcdf. I want to create a *.nc file containing three variables for Switzerland. All data outside of the country are NAs. The third variable is calculated from the first two variables. Basically there is no problem to do that. I copy the file with the data of the first variable,

Hello R For expierienced user, the following problem will be easy to solve: a<-c(0,1,0,1,0,2,3,4,3,2) b<-c(3,3,3,4,4,4,7,7,7,10) c<-data.frame(a,b) Data Frame c contains tow colums. I would like to sum up all values in a as long as b stays the same: sum(a[which(b==1)]) does this, but i have to manually put in b then i tryied st like this, but i canno't save it properly for (i

I have the following list of observations of calendar time: [1] 03-Nov-1997 09-Oct-1991 27-Aug-1992 01-Jul-1994 19-Jan-1990 12-Nov-1993 [7] 08-Oct-1993 10-Nov-1982 08-Dec-1986 23-Dec-1987 02-Aug-1995 20-Oct-1998 [13] 29-Apr-1991 16-Mar-1994 20-May-1991 28-Dec-1987 14-Jul-1999 27-Nov-1998 [19] 09-Sep-1999 26-Aug-1999 20-Jun-1997 05-May-1995 26-Mar-1998 15-Aug-1994 [25] 24-Jun-1996 02-Oct-1996

What's the neat way to create a dummy from a list? The code below is not replicable, but hopefully self-explanatory... d$treatment<-rep(1,length(d)) notreat<-c("AR", "DE", "MS", "NY", "TN", "AK", "LA", "MD", "NC", "OK", "UT", "VA") #i would really like this to work:

Hi, I can use the following code to generate a matrix, each column of which is 'x'. But I have to specify '5' twice in the second command. I am wondering if there is a better way to do it. > x=1:10 > matrix(rep(x,5),nc=5) > t(matrix(rep(x,5),nc=5)) Regards, Peng

Hi Everyone, I would like to do sequential subtractions within a group so that I know the time between separate observations for a group of individuals. My data: data <- structure(list(group = c("IND1", "IND1", "IND2", "IND2", "IND2", "IND3", "IND4", "IND5", "IND6", "IND6"), date_obs =

I have a really long functions, and at the end of the function, I am using a if statement to tag certain keywords based on whether they have certain values contained in them. However, the if statement doesn't seem to work. When I had split up the commands into various functions, it worked fine, but I'm not sure what going on now that it's combined into a single function. myfunc

Hi, I have a data set similar to the following State Gender Quantity TX Male 1 NY Female 2 TX Male 3 NY Female 4 I need to calculate cumulative sum of the quantity by State and Gender. The expected output is State Gender Quantity CumQuantity TX Male 1 1 TX Male 3 4 NY Female 2 2 NY Female 4 6 I highly appreciate if someone can give me some hints on solving that in R. Hao -- View this

Hello, I have a problem writing a variable to an existing file. Below is a part of my script and how it fails. I can't find "create.var.ncdf" in help Thanks for any help. Mark nc <- open.ncdf(ncname, readunlim=FALSE, write=TRUE ) missing <- 1.e+30 xdim <- nc$dim[["west_east"]] ydim <- nc$dim[["south_north"]] tdim <- nc$dim[["Time"]]

On Mon, Aug 14, 2017 at 5:29 AM, <raphael.felber at agroscope.admin.ch> wrote: Dear all > > I'm a newbie regarding netcdf data. Today I realized that I maybe do not > understand some basics of the netcdf. I want to create a *.nc file > containing three variables for Switzerland. All data outside of the country > are NAs. The third variable is calculated from the first two

I think I must be missing something obvious, but I'm having trouble getting a data transformation to work on groupings of data within a data frame (csss3) as defined by 2 factors (population, locid). The data are sorted by year within locid within population and I want to lag another variable (dbc), i.e, shift them down by 1 row replacing the first row with NA, within groups defined by