similar to: [Fwd: Re: Adding and Multiplying two Unevaluated Expressions]

HI, As I'm trying to compute Taylor series, I'm having problems in adding and multiplying unevaluated expressions. I searched for a solution but found none. my Taylor function works fine for evaluating functions as you can see here: rTaylorVal=function(exp,x0,dx,n) { ls=list(x=x0) newexp=eval(exp,ls) exp0=exp for (i in 1:n){ exp0=D(exp0,"x")

Dear Rhelpers I have the problem with initial values, could you please tell me how to solve it? Thank you June > p = summary(maxLik(fr,start=c(0,0,0,1,0,-25,-0.2))) Error in maxRoutine(fn = logLik, grad = grad, hess = hess, start = start, : NA in the initial gradient > p = summary(maxLik(fr,start=c(0,0,0,1,0,-25,-0.2),method="BFGS")) Error in optim(start, func, gr =

Greetings, I have a nagging problem with contrasts and I can't seem to resolve it. A factor exists with four levels (lib1, lib2, con1, con2) and when I check the contrasts or set the contrasts to any of the prespecified ones, I do not get the exact contrasts necessary to test the theoretically relevant ones. I need orthogonal contrasts that look just like this matrix: con1 con2

Dear r helpers I run the following code for nested logit and got a message that Error in optim(c(0, 0, 0, 0, 0.1, -2, -0.2), fr, hessian = TRUE, method = "BFGS") : initial value in 'vmmin' is not finite What does this mean? and how can I correct it? Thank you June > yogurt = read.table("yogurtnp.csv", header=F,sep=",")> attach(yogurt)>

My decision tree grows only with one split and based on what I see in E-Miner it should split on more variables. How can I adjust splitting criteria in R? Also is there way to indicate that some variables are binary, like variable Info_G is binary so in the results would be nice to see "2) Info_G=0" instead of "2) Info_G<0.5". Thank you in advance! And thanks for Eric who

below is a code to compute hessian matrix , which i need to generate 29 number of different matrices for example first element in x1 and x2 is use to generate let say matrix (M1) and second element in x1 and x2 give matrix (M2) upto  matrix (M29) corresponding to the total number of observations and b1 and b2 are constant.  can some one guide me or help to implement this please. I did not

Hi, I am trying to backup data from a distributed replicated volume. The volume was built from 6 units of 2 TB hard disks: gluster> volume info Volume Name: 6TB-Vol Type: Distributed-Replicate Status: Started Number of Bricks: 3 x 2 = 6 Transport-type: tcp Bricks: Brick1: c107:/exp0 Brick2: c108:/exp0 Brick3: c109:/exp0 Brick4: c110:/exp0 Brick5: c111:/exp0 Brick6: c112:/exp0 Options

Hi @all, I've created a Distributed-Replicated Volume consisting of 4 bricks on 2 servers. # gluster volume create glusterfs replica 2 transport tcp \ gluster0{0..1}:/srv/gluster/exp0 gluster0{0..1}:/srv/gluster/exp1 Now I have the following very nice replication schema: +-------------+ +-------------+ | gluster00 | | gluster01 | +-------------+ +-------------+ | exp0 | exp1 |

Many thanks to the R core team for their work on R connections. I was delighted to discover that it is now possible to remote-control R-1.3.0 via a socket connection - something which Brian Ripley noted was not yet possible with R-1.2.0 back in January 2001 in the first R News newsletter. How? Just substitute source() for readLines() in last few lines of the example for a socket connection given

The `gzcon` function both modifies and copies a connection object: # compressed text con1 <- url("http://www.stats.ox.ac.uk/pub/datasets/csb/ch12.dat.gz") con2 <- gzcon(con1) # almost indistinguishable con1==con2 identical(summary(con2), summary(con1)) # both support gzip readLines(con1, n = 3) readLines(con2, n = 3) # opening one opens both isOpen(con2)

Dear R-SIG-Debian, while trying to query data from an SQLite database through RODBC on Debian testing, R crashes with the following message: library(RODBC) con3 <- odbcConnect("test3") # 'test3' being an ODBC datasource configured with SQLite3 driver, # but the same happens with SQLite driver sqlQuery(con3, "select * from test") # 'test' being any table

This is what I get on R 3.3.1 on Linux: > con1 <- textConnection("foo1", open = "w") > print(con1) description class mode text "foo1" "textConnection" "w" "text" opened can read can write "opened"

Hi all, I used `gzfile` and `gzcon` to read a compressed file but I found that `gzcon` gave me a different result than `gzfile`. It seems like the `gzcon` does not handle the data correctly. I have posted an example below. In the example, a portion of a compressed file is downloaded from Google Cloud as a raw vector, and the data is saved into a temp file. If I use ` gzfile` to read the file, it

... is on SourceForge, http://tcng.sourceforge.net/#src Besides a bunch of bug fixes, this release also contains a greatly improved version of the comtc utility that copies comments from the tcng source to tcc''s "tc" output. There are a few infrastructure changes to make comtc work smoothly: - tcc''s -E option is now called -Wexperror or -Wexppostopt, respectively

On Oct 23, 2013, at 3:10 PM, Renato Golin <renato.golin at linaro.org> wrote: > On 23 October 2013 16:05, Arnold Schwaighofer <aschwaighofer at apple.com> wrote: > In the examples you gave there are no reduction variables in the loop vectorizer’s sense. But, they all have memory accesses that are strided. > > This is what I don't get. As far as I understood, a

I'm doing some string manipulation on a vector of file names, and noticed something curious. When I strsplit the vector, I get a list of character vectors. The list is numbered, as lists are. When I cast that list as a data frame with 'as.data.frame()', the resulting columns have names derived from the original filenames. Example code is below. My question is, where are these names

Hello, x<- "something(a+b) + c" is there any function F such that F(x) gives me the unevaluated value of x, i.e. something(a+b)+c I would appreciate any help on this thanks --------------------------------- [[alternative HTML version deleted]]

Hi there, Suppose the cmd is "a<-3", I can parse the cmd sexp with R_ParseVector and eval it. My question is - is it possible to parse a cmd like "a <- ?", afterwards evaluation will give corresponding result depend on different argument? In other words, '?' is just a placeholder. Thanks. Xin [[alternative HTML version deleted]]

Given the extremely simple package at https://github.com/jimhester/testUnload, which includes only one S3 method 'print.object' the following code produces a lazy load error from a new R session (R-devel r69801) install.packages("testUnload", repos = NULL) library("testUnload") unloadNamespace("testUnload") install.packages("testUnload", repos =

Hi, I'm trying to get ...as a list of unevaluated arguments, ie. substitute(list(...)) gives me an unevaluated list of the arguments, but I want a list of the unevaluated arguments. My attempts so far: (function(...) substitute(...))(a=1, b=a) # Only returns first (function(...) substitute(list(...)))(a=1, b=a) # Unevaluated list, not list of unevaluated (function(...)