similar to: Rd files, \itemize in \value

Dear All, I would like to do run R without having write permissions to any directory on the system. It seems that I need to modify the R source code for this, to make R start without creating a temporary directory. So far, so good. But should I expect any more complications? Does R really need the temporary directory that much? Thanks, Gabor -- Gabor Csardi <Gabor.Csardi at unil.ch>

Dear all, "Writing R Extensions" explicitly says that A method must have all the arguments of the generic, including ... if the generic does. A method must have arguments in exactly the same order as the generic. If the generic specifies defaults, all methods should use the same defaults. This is clear. R CMD check even checks for this. But then how is it possible that

Dear Luke and others, I have many R versions on my machine and want to start a particular one when snow builds its cluster. (The same version I start snow from.) It seems that everything is set up correctly in defaultClusterOptions: > mget(ls(defaultClusterOptions), defaultClusterOptions) $homogeneous [1] TRUE $manual [1] FALSE $master nodename "maya.unil.ch" $outfile [1]

Dear all, I would like to write some tests for my R package, and the usual 'tests' directory seemed like a good solution, but there is something I cannot understand. It is possible to supply .Rout.save files with the expected output for the tests, which is great. But since the tests are not run with R --slave, the expected output needs to contain all the extra output from R, e.g. the

Dear All, I have the following in a .Rd file: ... human readable (not binary) format. The format itself is like the following: \preformatted{ \# vertex1name vertex2name [optionalWeight] vertex3name [optionalWeight] } Here, the first vertex of an edge is preceded with a pound sign ... and it is fine with R 2.9.2, but fails on R-devel, when building the PDF version

Dear All, maybe this is something obvious, I seem to be incapable of understanding how S4 works. So, in package 'A' I defined a "summary" method for my class: setMethod("summary", signature(object="ListHyperGResult"), function(object, pvalue=pvalueCutoff(object), categorySize=NULL) { "whatever" })

igraph is a package for graphs/networks. It has a C core and uses a simple and fast graph representation allowing millions of vertices and edges. LINKS Release notes for the 0.5.2 version: http://igraph.sourceforge.net/relnotes-0.5.2.html Release notes for the 0.5.1 version: http://igraph.sourceforge.net/relnotes-0.5.1.html Complete list of changes: http://igraph.sourceforge.net/news.html The

igraph is a package for graphs/networks. It has a C core and uses a simple and fast graph representation allowing millions of vertices and edges. LINKS Release notes for the 0.5.2 version: http://igraph.sourceforge.net/relnotes-0.5.2.html Release notes for the 0.5.1 version: http://igraph.sourceforge.net/relnotes-0.5.1.html Complete list of changes: http://igraph.sourceforge.net/news.html The

Dear R developers, I am seeking advice on some $subject matter. My package will have an update soon, that is not backward compatible with the current version. It will likely break much of the existing code. Many (~50) packages depend on 'igraph' and they, too, will most probably break with the new version. My intended solution is, that I create a snapshot of the current package, under

Dear All, in some functions of my package, I use the Matrix S4 class, as defined in the Matrix package. I don't want to depend on Matrix, however, because my package is perfectly fine without Matrix, most of the functionality does not need Matrix. Matrix is so included in the 'Suggests' line. I load Matrix via require(), from the functions that really need it. This mostly works

Dear List, i know there are some solutions for this in the archive, but they're not very good for numeric matrices, since they usually convert rows/columns to character strings. Is there an easy way to do $subject for numeric matrices properly, or i need to do it by hand? Thanks, Gabor

Dear List, do you know a way for subsetting an R object from C code? I would need the equivalent of x[s]. I've found that the do_subset internal function does this, but don't really know how to call it properly. I've two SEXP's, one for the object and one for the index. I'm thinking of creating an enviroment, place the two SEXP's in it and then just parse and run the

Hi, Given a simple example, test <- matrix(c(0.1, 0.2, 0.1, 0.2, 0.1, 0.1, 0.3, 0.1, 0.1), 3, 3) How to generate row indexes for which their corresponding row values are less than or equal to 0.2 ? For this example, row 2 and 3 are the correct ones. Thanks [[alternative HTML version deleted]]

igraph is a package for graphs and networks. It has a C core and uses a simple and fast graph representation allowing millions of vertices and edges. NEW FEATURES: - We use the ARPACK library for graph related eigenvalue problems, like Page Rank calculation, Kleinberg's hub and authority scores, eigenvector centrality, etc. There is also a generic interface if someone wants to use

igraph is a package for graphs and networks. It has a C core and uses a simple and fast graph representation allowing millions of vertices and edges. NEW FEATURES: - We use the ARPACK library for graph related eigenvalue problems, like Page Rank calculation, Kleinberg's hub and authority scores, eigenvector centrality, etc. There is also a generic interface if someone wants to use

Hello I am a relatively new user of R and am struggling to use the 'network' package. I have a correlation matrix (produced using 'cor'), and want to draw a network where each item showing correlation above a threshold (say 0.5) is joined by a green line, and each item showing correlation below a threshold (say -0.5) is joined by a red line. Does anyone have any hints of how to

useR's, Consider: y <- c(20, 25, 30) > m <- matrix(c(0.0,1,NA,0.5,1.25,0.75, 0.5, NA, > NA),byrow=TRUE,nrow=3,ncol=3) > m [,1] [,2] [,3] [1,] 0.0 1.00 NA [2,] 0.5 1.25 0.75 [3,] 0.5 NA NA For each numeric value, I want to replace them with their corresponding y-value. The result should look like (here, each row represents a variable rather than the columns):

Greetings, R-ians: I would like to know which version or R was used to create a given package. I think I remember seeing that topic discussed recently but cannot find it among my notes. Can anyone tell me how to determine which version of R created a package? Thanks. Charles Annis, P.E. <mailto:Charles.Annis@StatisticalEngineering.com> Charles.Annis@StatisticalEngineering.com

In an earlier post, a person wanted to divide each of the rows of rawdata by the row vector sens so he did below but didn't like it and asked if there was a better solution. rawdata <- data.frame(rbind(c(1,2,2), c(4,5,6))) sens <- c(2,4,6) temp <- t(rawdata)/sens temp <- t(temp) print(temp) Gabor sent three other solutions and I understood 2 of them but not the

Hallo, I am running R-2.6. on Windows. I have a code which uses library(convert). Can anyone tell me which package I need to install to run this code. Everytime I receive the error message library (convert) not found. Thanks, Corinna