similar to: selectively altering variable value

Displaying 20 results from an estimated 3000 matches similar to: "selectively altering variable value"

2009 Jan 31
1
Splitting a data frame with break points where factor changes value
I have a data frame called s3. This data frame has a column called saccade which has two levels 1 and -1. > head(s3$saccade, 100) [1] NA NA NA NA -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 [26] -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 1 1 1 [51] 1 1 1 1 1 1 1 1 1 1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 [76] -1 -1 -1 -1 -1
2005 Apr 05
2
cat bailing out in a for loop
Dear All, I am trying to calculate the Hardy-Weinberg Equilibrium p-value for 42 SNPs. I am using the function HWE.exact from the package "genetics". In order not to do a lot of coding "by hand", I have a for loop that goes through each column (each column is one SNP) and gives me the p.value for HWE.exact. Unfortunately some SNP have reached fixation and HWE.exact requires a
2006 Feb 16
1
explicitly creating new sessions
When reading Agile Web Devlopment with Rails book, at the end of section 21.3 (avoiding session fixation attacks) it states: "...you should consider creating a new session every time someone logs in." But how would you do such a thing? When I look through the API docs, I only see functions for enabling/disabling session management for certain actions, nothing about explicitly
2005 Nov 08
1
Reducing the deleterious effects ofego related issues on the list
Bryan... NOBODY CARES how many times Chris is wrong. NOBODY CARES what you prove on this point. Whether Chris is right, wrong or stoopid is NOT proper fodder for this (CENTOS) list. Chris being wrong is *strictly* a "Bryan Fixation". Part of YOU growing up is YOU realizing that whether Chris is or is not wrong is UNIMPORTANT to ANYTHING that you or anybody important to you think is
2009 Nov 05
0
config.action_controller.session_options[:cookie_only] = true
Recently, I got this security vulnerability on my app: Ruby on Rails Multiple Method Session Fixation Synopsis : The remote web server is affected by a session fixation vulnerability. Description : The web server on the remote host appears to be a version of Ruby on Rails that supports URL-based sessions. An unauthenticated remote attacker may be able to
2005 Nov 09
1
strategies to obtain convergence using nlme
Hello. I am working on an analysis involving the nonlinear mixed model function (nlme) in R. The data consist of measures of carbon fixation by leaves as a function of light intensity and the parametric function (standard in this area because it has a biological interpretation) is a non-rectangular hyperbola. I cannot get the nonlinear mixed model (nlme) function to converge cleanly. I am
2005 Dec 25
5
understanding session fixation attacks
is there a way that, our application can understand wheteher the session id sent from the browser is forged or created by rails? I understand that if the attacker guesses session id, theres nothing we can do about it; but can we understand if he/she is trying to guess by creating random session ids. _______________________________________________ Rails mailing list
2008 Dec 13
3
Standard error of mean for aov
Hi all, I'm quite new to R and have a very basic question regarding how one gets the standard error of the mean for factor levels under aov. I was able to get the factor level means using: summary(print(model.tables(rawfixtimedata.aov,"means"),digits=3)), where rawfixtimedata.aov is my aov model. It doesn't appear that there is an equivalent function to get the standard
2005 Jun 24
1
r programming help II
Dear List, Suppose we have a variable K.JUN defined as (with 1=wet, 0=dry): K.JUN1984 = c(1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1) K.JUN1985 = c(0, 1, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 1, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0, 1, 1, 1, 1, 1, 1, 1) K.JUN1986 = c(0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1)
2012 Oct 16
2
cannot coerce class '"rle"' into a data.frame
why? > rle Run Length Encoding lengths: int [1:1650061] 2 2 8 2 4 5 6 3 26 46 ... values : chr [1:1650061] "4bbf9e94cbceb70c BG bg" "4fbbf2c67e0fb867 SK sk" ... > as.data.frame(rle) Error in as.data.frame.default(vertices.rle) : cannot coerce class '"rle"' into a data.frame it seems that rle.df <-
2013 Mar 26
2
Feed rle() output to hist()
I want to make a histogram from the lengths vector which is part of the output of rle. But I don't know how to access that vector so that I use it as an argument of hist(). What argument must I use so that I use the lengths vector as an input to hist()? Example output is: Run Length Encoding lengths: int [1:4] 1 2 3 3 values : num [1:4] -1 1 -1 1 A printout of the function rle() may
2011 Jun 17
3
rle on large data . . . without a for loop!
I think need to do something like this: dat<-data.frame(state=sample(id=rep(1:5,each=200),1:3, 1000, replace=T,prob=c(0.7,0.05,0.25)),V1=runif(1,10,1000),V2=rnorm(1000)) rle.dat<-rle(dat$state) temp<-1 out<-data.frame(id=1:length(rle.dat$length)) for(i in 1:length(rle.dat$length)){ temp2<-temp+rle.dat$length[[i]] out$V1[i]<-mean(dat$V1[temp:temp2])
2011 Jun 23
3
problem (and solution) to rle on vector with NA values
Hello there R-help, I'm not sure if this should be posted here - so apologies if this is the case. I've found a problem while using rle and am proposing a solution to the issue. Description: I ran into a niggle with rle today when working with vectors with NA values (using R 2.31.0 on Windows 7 x64). It transpires that a run of NA values is not encoded in the same way as a run of other
2008 May 27
4
help with simple function
I have a matrix of frequency counts from 0-160. x<-as.matrix(c(0,1,0,0,1,0,0,0,1,0,0,0,0,1)) I would like to apply a function creating a new column (x[,2])containing values equal to: a) log(x[m,1]) if x[m,1] > 0; and b) for all x[m,1]= 0, log(next x[m,1] > 0 / count of preceding zero values +1) for example, x[1,2] should equal log(x[2,1]/2) = log(1/2) = -0.6931472 whereas x[3,2] should
2002 May 20
1
how does one apply Western Electric / AT&T rules to R plots?
I have searched for info on how to apply the Western Electric rules for process control, to data and plots I have in R, but I have not been able to learn how. Any help would be greatly appreciated. Thank you, sjcrauhut at agere.com 05/20/02 -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read
2006 Mar 18
1
Time-Series, multiple measurements, ANOVA model over time points, analysis advice
Hi, I have some general questions about statistical analysis for a research dataset and a request for advice on using R and associated packages for a valid analysis of this data. I can only pose the problem as how to run multiple ANOVA tests on time series data, with reasonable controls of the family-wise error rate. If we run analysis at many small sections of a long time-series, the Type-I
2012 Jun 08
2
help with rle function on paired data
Dear R Community - I hope you might be able to provide some guidance regarding the use of the rle function. I have a set of time-series data where a measured value is recorded every 30 seconds after the start of an experiment. Many of the measured values repeat and I am interested only in the values when there is a change. If I turn the measured values into a vector, the rle function works
2009 Jul 07
2
rle
Hallo, I have an other problem, I have this vector signData with an alternation of 1 and -1 that corrispond to the duration of two different percepts. I extracted the durations like this: signData<- scan("dataTR10.txt") dur<-rle(signData)$length Now I would like to extract only the positive duration, e.g. signData <- c(1,1,1,1,-1,-1,-1,1,1,-1,-1) posduration <- c(4,2) I
2005 Oct 26
3
splash screen
Is the splash screen RLE is standard 640x480x4 or a modified one because I can neither open the file in Photoshop CS2 (Windows under ext2fsd) or Gimp 2.2 (Linux 2.6.12.16ubuntu) and I am unable to decipher Perl scripts. Will syslinux support standard RLE?
2010 May 26
3
Peak Over Threshold values
Dear List I hope you can help me: I?ve got a dataframe (df) within which I am looking for Peak Over Threshold values as well as the length of the events. An event starts when walevel equals 5.8 and it should end when walevel equals the lower threshold value (5.35). I tried ?clusters (?)? from ?evd package?, and varied r (see example) but it did not work for all events (again