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Hi, Could you please help me? I am trying to load an csv-file in R, but it works wrong! My data is 0,0127 -0,0016 0,0113 0,0037 -0,0025 > Ret<-read.csv("Ret.csv") > Ret X0 X0127 1 0 16 2 0 113 3 0 37 4 0 25 Thank you in advance! -- Best regards, Andy [[alternative HTML version deleted]]

Dear Colleagues, I have faced with the problem that function rollaply with rolling window for calculation of volatility doesn't give the all results of calculations. I have run the rolling window for calculation in Excel and obtained that the number of outputs for Excel is 36 and for R is 18. The total number of observations is 37. In the attachment you can find pdf of the Excel and Excel

Hi, I faced with problem when start using function - rollapply(returns, 3 , mean) Error in UseMethod("rollapply") : No suitable Method for "rollaply" How can I fix the problem? Thank you for help. -- Best regards, Andy Fetsun [[alternative HTML version deleted]]

Hi Colleagues, Could you please help? I get as the output of my calculations following [1] 0.000000e+00 1.890000e-04 3.933000e-05 1.701501e-04 2.040456e-04 [6] 3.119242e-04 2.545665e-04 1.893930e-03 1.303112e-03 9.880183e-04 [11] 1.504378e-03 1.549246e-03 5.877690e-04 4.771359e-04 8.528219e-04 How is it possible to transform the data to get a vector as following 10

Hi, Could you please help me with EGARCH and GJR? Is it possible to use EGARCH and GJR in R? I have used below mentioned code for GARCH in R, but I never used EGARCH and GJR in R. Thank you in advance! daten<-read.table("H://Daten//Zeitreihen//dax_1.csv", sep=";", header=T) DAX.kurs<-daten DAX.kurs<-ts(DAX.kurs,names="DAX-Kurs")

Dear Specialists in R, May be somebody has experiment in using pakage for the book Quantitative Risk Management by McNeil? This package is writen in R. I have run this package for fitting the data to Nornal Inverse Gaussian distribution and fased with following problem. > Return<-read.csv("data.csv") > Transpose<-t(Return) > fit.NH(Transpose, case="NIG",

Thank you for the hint. I adjusted the code and it works: The code after replacing inttoptr with getelementptr: define { i32, i32, i8* } @test(i32 %foo, i32 %bar, i8* %sp) { entry: ; push foo (On "stack") %sp_1 = getelementptr i8, i8* %sp, i32 -4 %sp_1_ptr = bitcast i8* %sp_1 to i32* store i32 %foo, i32* %sp_1_ptr, align 4 ; push bar %sp_2 = getelementptr i8, i8* %sp_1,

I am new to R. I want to graph group data using a "Traditional Bar Chart with Standard Error Bar", like the kind shown here: http://samiam.colorado.edu/~mcclella/ftep/twoGroups/twoGroupGraphs.html Is there a simple way to do this? So far, I have only figured out how to plot the bars using barplot. testdata <- scan(, list(group=0,xbar=0,se=0)) 400 0.36038 0.02154 200 0.35927

Hello, I am trying to emulate the "stack" as like on x86 when using push/pop so afterwards I can use LLVM's optimizer passes to simplify (reduce junk) the code. The LLVM IR code: define { i32, i32, i32 } @test(i32 %foo, i32 %bar, i32 %sp) { ; push foo (On "stack") %sp_1 = sub i32 %sp, 4 %sp_1_ptr = inttoptr i32 %sp_1 to i32* store i32 %foo, i32* %sp_1_ptr, align

For the following code below, the x-axis ticks are 1,2,3,4,5,6,7 when I was expection them to be 1,2,8,9,10,11,12. Please help me figure out where is the mistake. library(lattice) testdata <- as.data.frame(t(structure(c( 1,2005,9.24,6.18,634, 2,2005,8.65,6.05,96, 8,2004,6.81,6.51,16, 9,2004,9.0,7.29,8, 10,2004,8.84,6.18,524, 11,2004,8.54,6.35,579, 12,2004,9.97,6.3,614, 12,2005,8.75,5.84,32,

Thanks for the answers. Although I am not sure if I've understood the docs about how inttoptr/ptrtointr are different when compared to gep. It says: "It’s invalid to take a GEP from one object, address into a different separately allocated object, and dereference it.". To go back to my intention why I am doing this, I would like to "emulate" some x86 instructions with

Hi again, So I finally gave up on trying to get through the converting (x86' push pop mov add) because it deals a lot with crazy pointer arithmetics and sonce inttoptr and ptrtoint doesn't provide any alias analysis information. Daniel, you said it doesn't make much sense to provide it but in my cases it is actually very much needed, you didn't say it wasn't possible to

Hello, I am currently trying to translate some custom IR to LLVM-IR and came across and issue. The custom IR has several registers and I am basically try to SSAfy it so it can be easily translated/converted to LLVM-IR. The problem: Since in my custom IR I can reassign every register I have to reassign every new expression with a new llvm Value. But my IR has something like this: REG A = VAR C

I want to keep the translation short and simple (My IR doesn't have control flow so it's basically on basic block) that's why I don't want to rely on alloca/load/store. 2016-02-08 6:08 GMT+01:00 George Burgess IV <george.burgess.iv at gmail.com>: > Hi! > > I don't know what "the right way" to do this is, but is there any reason > you're against

Hi... With samba4 I sometimes feel like a bloody beginner even I use samba since ages. Miracle of the day: Users connecting using samba4 cannot write to group writeable folders even they should be able to. I upgraded one 3.6 fileserver to 4.2.3. PDC is always a samba 4.2.3 instance. I am using samba4 in classic PDC mode for a couple of reasons. On my fileserver I have a folder called

Hi All.. Have a question.. For the following r code testdata <- as.data.frame(t(structure(c( "1/1/04","LV1",3.8,2,87, "2/1/04","LV1",3.2,3,28, "3/1/04","LV1",3.4,3,88, "4/1/04","LV1",3,2,26, "5/1/04","LV1",3.8,2,87, "6/1/04","LV1",3.2,3,28,

I have a text string that contains text within two brackets. e.g. "testdata[3]" "testdata[-4]", "testdata[-4g]", I wish to "extract" the string enclosed in brackets? What is a good way to do this? e.g. fun(testdata[3]) = '3' fun(testdata[-4g]) = '-4g' --------------------------------- Moody friends. Drama queens. Your life?

Hello All, I was wondering if it's possible to reshape data from long to wide in R without using a "timevar". I've pasted some sample data below along with some code. The data are sorted by Subject and Drug. I want to transpose the Drug variable into multiple columns in alphabetical order. My data have a variable called "RowNo" that functions almost like a

In playing around with data.frames (and wanting a simple, cheap way to use the variable and case names in plots; but I've solved that with some hacks, yech), I noticed the following behavior with subsetting. testdata <- data.frame(matrix(1:20,nrow=4,ncol=5)) names(testdata) ## expect labels, get them names(testdata[2,]) ## expect labels, get them names(testdata[,2]) ## expect labels, but

Dear all, I have a dataset where the interaction is more than obvious, but I was asked to give a p-value, so I ran a logistic regression using glm. Very funny, in the outcome the interaction term is NOT significant, although that's completely counterintuitive. There are 3 variables : spot (binary response), constr (gene construct) and vernalized (growth conditions). Only for the FLC construct