similar to: Can hist plot % of count instead of raw count?

Hi, I have a couple of aggregation operations that I don't know how to accomplish. Let me give an example. I have the following irregular time series time x 10:00:00.021 20 10:00:00.224 20 10:00:01.002 19 10:00:02:948 20 1) For each entry time, I'd like to get sum of x for the next 2 seconds

Hi, To set a simple an clear picture of what I'd like to do, here is an example. I would like to calculate mean of column A and B bucketed by factor in column X in a data.frame. lapply or aggregate operates on a single column. I found dapply function in some package which doesn't seem to exist any more. Is there anyway that I can accomplish something like this? Thank you so much in

Hi, I have the following string that I converted to a POSIXct: > a <- "2009-08-24 10:00:00.213" > a.p <- strptime(a,"%Y-%m-%d %H:%M:%OS") > as.double(as.POSIXct(a.p)) [1] 1251122400 I can't seem to get the decimal fraction of .213 out by casting to double or numeric. Is there anyway to make sure that POSIXct spits that out? Thank you. adschai

Hi, When I define a new class (through setClass), members defined in representation argument doesn't seem to like a class. For example, if I do the following: setClass("NotWork",representation=(x="zoo")) It seems to me that representation members will take in only primitive type to R. Is there any way to stuff a class as a member in another class? Thank you. - adschai

Hi, I am trying to install package xts. I am using OPENSUSE 11 64 bit. When I invoke: install.pacakges("xts",dependencies=T) I received a lot of "ERROR: compilation failed for package" errors when R tries to install xts dependencies. I do not understand this behavior. I notice one thing. It complains. ERROR: compilation failed for package 'Hmisc' ** Removing

Hi, I have a matrix or data.frame (df). When I would like to check if a column named "x" exists, it becomes my habit to do the following: if (length(which(colnames(df)=="x"))>0) Is there any smarter way to do this? Thank you. adschai [[alternative HTML version deleted]]

Hi, I have a list that contains about 100 elements. Each element contains the following matrix structure a b 1 1 4 2 2 5 3 3 6 I'd like to sum column b across all elements. I'm thinking of using lapply or sapply but cannot get it to work. Any help would be really appreciated. Thank you. adschai

Hello, After spending sometime trying to generate histograms of all the numeric variables in a data frame using a for loop, I realized I could use apply to create the histograms. This was one of those few moments when I `see' the alternative to looping. So, I can generate all the histograms with this command: apply(toblo.df[,-c(40,52)],2,hist) # 40 and 52 are ID's When I do this, the

Hi, I have the following code: hist(gps$heartpercent, breaks=5) rect(90, par("usr")[3], 100, par("usr")[4], col = "red") How do I get the rectangle to appear behind the histogram. Barring that, how can I make certain bars of the histogram to be a certain color? Thanks, Jason

Full_Name: Mark Wall Version: 1.6.0 OS: linux Submission from: (NULL) (63.251.119.254) I want to plot a histogram of a *subset* of some data: >t = c(0:9) >hist(t,right=FALSE,breaks=10,xlim=c(0,5),xaxs="i") This means I should plot a histogram from 0 to 5 with breaks at 1,2,3,4. This should produce exactly 5 bars of frequency=1. Instead I get 5 and 1/4 bars. I do not want the

Think I'm missing something to understand what is going on with hist(...) http://n2.nabble.com/What-is-going-on-with-Histogram-Plots-td3022645.html For my example I count 7 unique years, however, on the histogram there only 6. It looks like the bin to the left of the tic mark on the x-axis represents the number of entries for that year, i.e. Frequency. I guess it looks like the bin for

Dear listers, A quick question about breaks in hist(). The histogram is highly screwed to the right, say, the range of the vector is [0, 2], but 95% of the value is squeezed in the interval (0.01, 0.2). My question is : how to set the breaks then make the histogram look even? Thanks in advance, Leaf

This message is in MIME format. The first part should be readable text, while the remaining parts are likely unreadable without MIME-aware tools. Send mail to mime@docserver.cac.washington.edu for more info. --0-201145637-953833073=:7710 Content-Type: TEXT/PLAIN; charset=US-ASCII Dear all, I've been hacking on histograms the past couple of days. I wanted to do two things, add

> > Leaf Sun wrote: > > The histogram is highly screwed to the right, say, the range > > of the vector is [0, 2], but 95% of the value is squeezed in > > the interval (0.01, 0.2). I guess the histogram is as you wrote. See http://web.maths.unsw.edu.au/~tduong/seminars/intro2kde/ for a short explanation. > -----Original Message----- > From: Berton Gunter

Hello! Up to now I have been using hist() to display the distributions. Howevere, I noteiced strange numbers on y (vertical) axis, if I used probability = T or freq = F option. I thought it is a bug and launched the R-bug system and found some posts on that matter. Brian Ripley responded to one, that one should look at truehist() for that. Ok I can use truehist() if I want to see the ratios

Dear List, I have the following function where I plot on one page a histogram and a boxplot. I use option labels = TRUE in hist to show labels. However the label on the highest bar in the histogram is not showing entirely. How can I correct this? Thanks for any suggestions? histtst <- function(n = 100,...){ set.seed(15) # makes rnorm reproducible par(mfrow = c(2,1)) x <-

On Sun, 11 Dec 2005 clausen at econ.upenn.edu wrote: > Full_Name: Andrew Clausen > Version: 2.1.0 > OS: Debian GNU/Linux > Submission from: (NULL) (71.242.192.73) > > > Hi, > > When I type > > hist(x, freq=F) > > I get a density function, as I expect. However, if I type > > plot(hist(x, freq=F)) > > then I get the same output as if I had

Hi, I am trying to plot a histogram with my dataset that has 68 elements, 67 of which are zero and the last one is 18. It can be reproduced as follows: x<-array(0, dim=(68)) x[1] = 18 I am trying to plot its histogram using: hist(x, breaks=10, xlim=c(0, 100), axes=F) axis(2, at=seq(0, 70, 5)) # for the y-axis axis(1, at=seq(0, 100, 10)) # for the x-axis As you would also see if you

Hello R-list, I've been using hist to plot histograms of some data, but I get variable numbers of bins. I understood from reading the help file that breaks will set the number of bins. Please correct me if I'm wrong. I'm plotting measures from subsets of a larger data set. Depending on the data subset the number of bins varies despite having set breaks to 5 in all cases. See

Hi Folks, I'd like to know how hist() decides how many cells to use when it ignores my "suggestion" to use say 'hist(...,breaks=50)'. More specifically, I have the results of 10000 simulations, each returning an 8-vector, therefore 8 variables each with 10000 values. Some of these 8 have somewhat skew distributions. Say one of these 8 variables is X. I ask for H <-