similar to: looping problem

I'm attempting to modify a parser generator to emit LLVM code instead of C. So far the experience has been trivial, but I am now running into an error regarding labels that I can't seem to solve. Situation 1: A label is used immediately after a void function call (l6 in this case): <snip> %tmp26 = load i32* @yybegin, align 4 %tmp27 = load i32* @yyend, align 4 call void

Dear All- I am trying to merge two data files - they have different date formats and different times zones. I need to match up the date/time of the datasets and then invoke a conditional statement, such as: if dataC$mph is >= 12 then keep dataM$co23 for the corresponding time/date stamp. snippets of data files: *dataC.txt* LST in mph Deg DegF DegF2 % volts Deg

Dear all- I have a dataset (see a sample below - but the whole dataset is June 2005 - June 2008). The "LST" format is "YYMMDDHHmm" and I would like to get the hourly average of the "mph" for the summer months (spanning all years). I have been trying to use "aggregate" but am not having much success at all! any thoughts would be greatly appreciated.

Dear All, I am working with skewed-t copula in my research recently, so I needed to write an mle procedure instead of using a standard fit one; I stick to the sn package. On subsamples of the entire population that I deal with, everything is fine. However, on the total sample (difference in cross-sectional dimension: 30 vs 240) things go wrong - the objective function diverges to infinity. I

Hi, I'm trying to figure out how anova works in R by translating the examples in Sokal And Rohlf's (1995 3rd edition) Biometry. I've hit a snag with planned comparisons, their box 9.4 and section 9.6. It's a basic anova design: treatment <- factor(rep(c("control", "glucose", "fructose", "gluc+fruct",

While using Lattice I received the following error. Error in if (xx != 0) xx/10 else z/10 : argument is of length zero In addition: Warning messages: 1: is.na() applied to non-(list or vector) in: is.na(x) 2: is.na() applied to non-(list or vector) in: is.na(x) 3: no finite arguments to min; returning Inf 4: no finite arguments to max; returning -Inf 5: NaNs produced in: log(x, base) Can anyone

While using Lattice I received the following error. Error in if (xx != 0) xx/10 else z/10 : argument is of length zero In addition: Warning messages: 1: is.na() applied to non-(list or vector) in: is.na(x) 2: is.na() applied to non-(list or vector) in: is.na(x) 3: no finite arguments to min; returning Inf 4: no finite arguments to max; returning -Inf 5: NaNs produced in: log(x, base) Can anyone

Hi R-users,   I would like to transform my data using gamma, my data are ahll, bhall and dp1 as shown below:   > ahall      ah1  ah2  ah3  ah4  ah5  ah6  ah7  ah8  ah9 ah10 ah11 ah12 [1,] 0.9 1.01 1.24 1.85 1.85 2.45 3.67 3.02 3.06 2.33 1.86 0.96   > bhall        bh1   bh2   bh3   bh4  bh5   bh6   bh7   bh8   bh9  bh10  bh11  bh12 [1,] 48.39 44.26 37.34 29.93 33.5 26.54 20.26 25.73 20.14

Hi everyone, apologies if the answer to this is in an obvious place. I've been searching for about a day and haven't found anything.. I'm trying to replicate Stata's confidence intervals in R with the survey package, and the numbers are very very close but not exact. My ultimate goal is to replicate Berkeley's SDA website with R (http://sda.berkeley.edu/), which seems to

Hello, I have the following data.frame structure(list(Study = structure(c(1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 13L, 14L, 15L, 16L, 17L, 18L, 19L, 1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 13L, 14L, 15L, 16L, 17L, 18L, 19L, 1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 13L, 14L, 15L, 16L, 17L, 18L, 19L, 1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 13L, 14L,

Hi list-members can anybody tell me why > pairwise.t.test(val, fac) produces an empty p-table. As shown below: Pairwise comparisons using t tests with pooled SD data: val and fac AS AT Fhh Fm Fmk Fmu GBS Gf HFS Hn jAL Kol R_Fill AT - - - - - - - - - - - - - Fhh - - - - - - - - - - - - - Fm - - - - - - -

Hi, I have tried to use cups and samba together. Everything works great, however I am not able to configure and/or setup samba correctly, that the clients are able to install the driver. To test everything I used a dedicated system installed a fresh SuSE 8.0 and compiled samba (2.2.4) and cups (1.1.14). I only userd a differnet prefix for samba. Everything else is default.

I have a data set like this: > head(FormatedData) ID Target Actual Date Time 1 2030 0 -57.0 12/20/08 17:03:00 2 2030 90 90.0 12/20/08 18:41:00 3 2030 45 43.8 12/21/08 14:36:00 4 2030 0 -23.8 12/21/08 19:30:00 5 2030 90 90.2 12/21/08 21:48:00 6 2030 45 48.6 12/22/08 13:02:00 I wan to convert the format of Date and Time, so I did this: pdate

Hello, This is a standard example in which I read the time series data from a csv file and create a zoo object: x0 <- read.csv(file="CPI.csv", header=TRUE) time_0<-as.yearmon("1981-01")+(0:371)/12 x0zoo<-zoo(x0, time_0) The data look like this: TIME CPI CPI_food CPI_Clothes CPI_House CPI_Rent 198101 62.1 55.34 103.45 65.24 61.43 198102 63.16 56.95

I would like to be able to shade between two lines using ggplot2 (with faceting too). But, despite reading all the documentation on the website, cant figure out how to do it (either because i am a novice or idiot - or, of course, possibly both) My data looks is readership of paid & free newspapers in london by age since 1994. The structure is reading.melt <- structure(list(Date =

Date Fo Co 6/27/2007 57.1 13.9 6/28/2007 57.7 14.3 6/29/2007 57.8 14.3 6/30/2007 57 13.9 7/1/2007 57.1 13.9 7/2/2007 57.2 14.0 7/3/2007 57.3 14.1 7/4/2007 57.6 14.2 7/5/2007 58 14.4 7/6/2007 58.1 14.5 7/7/2007 58.2 14.6 7/8/2007 58.4 14.7 7/9/2007 58.7 14.8 Hello all: I am a newbie to R, and I was wondering how can I

I'm applying a function (Cov.f) defined below to each element of a distance matrix. When I run the code below, I get a warning message (below) and elements of returned matrix [2,3] and [3,2] are not zero as I would expect. Clearly, there is an error... What am I doing wrong? Thanks. --Dale Warning message: In if (h <= phi) { : the condition has length > 1 and only the first element

Dear list, I am facing a problem in my statistical analyses on R. My experiments are about plants, I record there growth after each cutting (every 3 weeks). 'BC' is for the plant, and '1' to '5' is the time of cutting and recording. The data and R script are : "" BourdCoup <- c(21, 7.2, 9.2, 0, 8.52, 14.7, 8.31, 6.2, 127.05, 115.2, 100.7, 24, 162.64, 136.8,

Dear colleagues, What did I not understand ? ->my intention I want to create a new variable: In plain language: If someone is taking anithypertensive treatment (med.hyper==1) table(med.hyper) med.hyper 0 1 472 97 I want to subtract 5 mmHg (rr.dia.2m-5) from the measured diastolic blood pressure (rr.dia.2m) if not treated - the value of the measured diastolic blood pressure should

Hi We're using 1.8.23.1 on CentOS 5 and are trying to get accurate stats for queues. For a particular customer, when I run queue show <queue_name> I get the following numbers: <queue_name> has 0 calls (max unlimited) in 'ringall' strategy (17s holdtime, 94s talktime), W:0, C:175, A:44, SL:48.6% within 45s So from that data we look at 17s holdtime And assume that is the