similar to: How to import timestamps from emails into R

I want to plot quantitative data as a function of three two-level factors. How do I group the bars on a barplot by level through labeling and spacing? Here <http://www.thomaslevine.org/sample_multiple-factor_barplot.png>'s what I'm thinking of. Also, I'm pretty sure that I want a barplot, but there may be something better. Tom [[alternative HTML version deleted]]

# Hi, # This plot has two colors. overflow <- read.csv('http://chainsaw.thomaslevine.com/overflow.csv', stringsAsFactors = F) png('original.png') stripchart(overflow$precipi ~ overflow$after.9.am, method='stack', pch = 22, bg = overflow$overflow + 1, vertical = T, col = 0) dev.off() # I wanted continuous bands of color, so I sorted the data frame. # But after

I would like to make bar plots where the bars are composed of text like this: http://www.thomaslevine.com/lowres/text_bars.png Is there a package that will help me with this? Thanks Tom

Ilio Fornasero writes: > Yet, I am at this point. > > > > > ## 01. Finding the dataverse server and making a search > Sys.setenv("DATAVERSE_SERVER" =3D "dataverse.harvard.edu") > dataverse_search(".Hunger") > > > ## 02. Loading the dataset (in this example, I have chosen the word ".Hunge= > r" to get > # one list and

I submit a couple options for addressing bug 16719: kruskal.test documentation for formula. https://bugs.r-project.org/bugzilla3/show_bug.cgi?id=16719 disallow-character.diff changes the documentation and error message to indicate that factors are accepted. allow-character.diff changes the kruskal.test functions to convert character vectors to factors; documentation is updated accordingly. I

Hi, After the previous debacle with PHP and MySQL it has been decided that we think about an upgrade from CentOS 3 to 5, since that would solve our problem, if successful. I tried finding information on how to best attempt this, but thanks to a plethora of contradictory information my head is now spinning with a few rpm (rounds per minute). The situation is as follows: Remote box at our

I have a dataset with transactions and a timestamp at which they occoured during a day. The time stamp is in the format YYYY/MM/DD hh:mm:ss. I would like to plot a timeseries of the transactions to see if there is a particular time in the day when there is a spike in transactions. Ofcourse the YYYY/MM/DD can be dropped since I am monitoring activity for the day and the actual date is

Hello alltogheter, I have the following problem and maybe someone can help me with it. I have a list of values with times. They look like that: V1 V2 1 2008-10-14 08:45:00 94411.08 2 2008-10-14 08:50:00 90745.45 3 2008-10-14 08:55:00 82963.35 4 2008-10-14 09:00:00 75684.38 5 2008-10-14 09:05:00 78931.82 6 2008-10-14 09:20:00 74580.11 7 2008-10-14 09:25:00

Hi, All. I'd have a set of data in an array: process <- c( 5 , 7 , 4 , 1 , 4 , 1 , 4 , 1 , 4 , 4 , 1 , 5 , 4 , ...) and I'd like to know the number of transitions in this data. I calculate transitions as the number of times a number follows another number. thus, something like this would be a 1 deep transition: 1 --> 1 : 10% (and actual number of 1 --> 1 occurrences) 1

Hi all, Why subscripting a one column matrix drops one dimension? > x<- matrix(rnorm(100), ncol=1) > str(x) num [1:100, 1] -0.413 -0.845 -1.625 -1.393 0.507 ... > str(x[20:30,]) num [1:11] -0.315 -0.693 -0.771 0.448 0.204 ... > str(x[20:30]) num [1:11] -0.315 -0.693 -0.771 0.448 0.204 ... This breaks: > cov(x) [,1] [1,] 0.9600812 >

I'm writing a program that will tell me whether I should wear a coat, so I'd like to be able to download daily weather forecasts and daily reports of recent past weather conditions. The NOAA has very promising tabular forecasts (http://forecast.weather.gov/MapClick.php?CityName=Ithaca&state=NY&site=BGM&textField1=42.4422&textField2=-76.5002&e=0&FcstType=digital),

Hello all. Our system consists of two linux machines, each running Red Hat 7.1 (kernel 2.4.9-34), using SMB to mount multiple shares hosted by a Windows 2000 Advance Server. smbclient from Samba 2.2.5 is used to do the actual mounting. Over the weekend, a number of files on these SMBFS shares were created with incorrect timestamps (modification times). In some cases, the timestamps were off by

Hi Steven, Yes, both file systems are the same. rsync -nri --modify-window=1 <src> <dest> Gives me the following for most files >f..T....... 2015_167_1_1__Boy_What_A_Girl_R2/2015_167_1_1__Boy_What_A_Girl__UHD_DPX_R2/ BWAG_R2_00138428.dpx Although a few have >f..T......n 2015_167_1_1__Boy_What_A_Girl_R2/2015_167_1_1__Boy_What_A_Girl__UHD_DPX_R2/ BWAG_R2_00135909.dpx

I'm seeing timestamps off one hour in Windows 200 and XP clients that were modified earlier this year before the +1 hour daylight savings time. They show correctly when views from the Ubuntu Linux Server running Samba 3.2.3-1ubuntu3.8. As a test, I created three files in Linux at 00:13, 01:13, and 03:13. I could not create a file during 2 am as that time does not exist in the local

Hi there, I just wanted to take a quick second to thank everyone who maintains this service- just in case you don't hear it enough, there are a plethora of people who rely on this service (as evidenced by the help archives), and even if they don't say it, are greatly thankful for what you do here. Not only are you providing a service to people who are learning R, but indeed helping

Hi all. It will be great if some one will help me to solve my home task. So, the deal : i have .pcap file, i convert it to csv using tcpdump (tcpdump -tt -n -r x.pcap > x.csv) CSV file looks like that : 12890084,761659 IP 10.10.20.20.47808 > 10.10.20.255.47808: UDP, length 12 12890084,761659 IP 10.10.20.20.47808 > 10.10.20.255.47808: TCP, length 12 12890084,761659 IP 10.10.20.20.47808

Hello, I am new to R and I am trying to estimate a discrete model with three choices. I am stuck at a point and cannot find a solution. I have probability functions for occurrence of these choices, and then I build the likelihood functions associated to these choices and finally I build the general log-likelihood function. There are four parameters in the model, three of them are associated to

I want to do something like this. avo(q~a+b+c+d+e+f+g+h+i+j+k+l) avo(r~a+b+c+d+e+f+g+h+i+j+k+l) avo(s~a+b+c+d+e+f+g+h+i+j+k+l) (There's likely a better way to do this actually, but I think this'll work.) How do I define e=a+b+c+d+e+f+g+h+i+j+k+l such that the following works? avo(q~e) avo(r~e) avo(s~e) Tom

A subset of my raw data looks like this: -------------- "Grip" "Technique" "Baseline.integrated" "Task" "Stroke..direction." "Engag" "Disen" "PenDG" "PenUG" "PenDS" "PenUS" "Duration" -------------