similar to: how to sort

I have an object. I think it is a matrix, called 'answer2' str(answer2) int [1:1537, 1:2] 1 399 653 2 3 600 4 5 271 870 ... - attr(*, "dimnames")=List of 2 ..$ : chr [1:1537] "a4.1" "hirschsprung.399" "peritoneal.653" "abdomen.2" ... ..$ : chr [1:2] "row" "col" I want to delete rows that have the same entries.

Hola a todos Me gustaría saber si me pueden ayudar con lo siguiente. Realicé un Boxplot usando ggplot2 para visualizar el comportamiento de dos variables. Visualmente no se notan las diferencias porque la gráfica de la derecha (parásitos en el abdomen) llega hasta 20 en el eje y. ¿Cómo puedo hacer para que las dos gráficas muestren la misma escala en el eje Y, es decir, que las dos lleguen a 60?

Hi: I have asked this question on Cross-Validated. So it might be a cross posting but havent received any responses to it. I am trying to see which distribution will best fit the data I am working on. The dataset is as following: Site Nausea headache Abdominal Distension 1 17 5 10 2 12

Why can it not find my object? What am i missing here? Here is my code: require ''rexml/document'' include REXML # classes to represent the objects and relationships in the xml file class Article attr_accessor :id, :post, :archive, :ntype, :head, :blurb, :body, :fblurb, :fimage, :att, :source, :copy, :brand end # the base parser class BaseXMLParser def initialize(filename)

Dear all, I'm using R 2.8.1 under Windows Vista on a dual core 2,4 GhZ with 4 GB of RAM. I'm trying to reproduce a result out of "Analysis of Financial Time Series" by Ruey Tsay. In R I'm using the fGarch library. After fitting a ar(3)-garch(1,1)-model > model<-garchFit(~arma(3,0)+garch(1,1), analyse) I'm saving the results via > result<-model

Hi. I have a 925 by 925 correlation matrix corM. I want to identify all variables that have correlation greater than 0.9. Can anyone suggest an "R way" of doing this? Thank you. -- View this message in context: http://www.nabble.com/search-through-a-matrix-tp23153538p23153538.html Sent from the R help mailing list archive at Nabble.com.

Hi. I have an n x m matrix M some of who's entries are zeros. I want to know how many zeros there are in each row -perhaps stored in a 1 x n vector which lists the number of zeros for each row of M. Before I had a vector V and I was able to get the number of zeros in V by doing length(V[ V==0]) but when I try something similar for M, like M[ M==0] it creates a vector not a matrix and so

Error in matrix(unlist(value, recursive = FALSE, use.names = FALSE), nrow = nr, : invalid 'ncol' value (too large or NA) the statement was: for (i in v) {for (j in m[0,]){if(v[i]==m[0,j]){M[,-j]}}} where 'v' is a vector, and 'm' and 'M' are both matrices. -- View this message in context:

I am trying to build a glm model with many inputs. I saw the following code in Rattle crs$glm <- glm(value ~ ., data=crs$dataset[,c(1:59,922)], family=binomial(link="logit")) I am not clear about what value ~ . means and also, I see data=crs$dataset[,c(1:59,922)] I have read that the data argument is optional here "an optional data frame, list or environment (or object

Hi. Does anyone know of a function which will take as input a number n (or a set of n letters) and will give out, one at a time, the permutations of n (or of those n letters) as a vector? So that I can use the permutations one at a time. And such that it will exhaust all the permutations with no repeats. For example if n is 3, I would want a function which I could use in a loop and the first time

Hi. I started with a file which was a sparse 982x923 matrix and where the last column was a variable to be predicted. I did principle component analysis on it and arrived at a new 982x923 matrix. Then I ran the code below to get a neural network using nnet and then wanted to get a confusion matrix or at least know how accurate the neural net was. I used the first 22 principle components only for

Hi. I have a huge list called twitter: > dim(twitter) NULL > str(twitter) List of 1 $ :Classes 'PlainTextDocument', 'TextDocument', 'character' atomic [1:35575] 11999;10:47:14;20;10;2009;ObamaLouverture;Trails Mixed Lessons For Governance From Campaigner-in-chief: President obama jumps campaign 09 tuesday..

Hi. The following statement works fine in R-win 1.8.0, but yields a syntax error in R-win 2.0.1 (and possibly in other versions after 1.8.0): plot(c(1,2),main=expression(a==b==c)) I note that the following workaround executes successfully in both versions of R... plot(c(1,2),main=expression(a*"="*b*"="*c)) ...but I don't really understand

Dear all, Can anybody tell me how to export a 3d figure made with the plot3d function? I'm careless about whether it's still interactive or not in another format, as long I can get it out of R. Thanks! Alejandro Gonz?lez Departamento de Biodiversidad y Conservaci?n Real Jard?n Bot?nico Consejo Superior de Investigaciones Cient?ficas Claudio Moyano, 1 28014 Madrid, Spain Tel +0034

Hi. I tried running the following code. I don't understand the error. mydata <- read.table("C:/dataForR/radiology/wordFrequencies.csv", header=TRUE, sep=",") > dim(mydata) [1] 982 924 mydataN<-mydata[,-923] > dim(mydataN) [1] 982 923 cor(mydataN) factanal(mydataN, factors=3) Error in solve.default(cv) : Lapack routine dgesv: system is exactly singular

Hi. I am sure there is a better way in R to do this then using a loop but I am new to it and not sure what to do. I think it might be something about using a function as an argument but not sure. I have a 1 x 2000 vector TS2 which has entries from the set {x: x is in Z and 0<x<8} (where Z is the set of Integers). Then I also have a 5050 x 7 matrix called 'perm' whose entries are

Hello. I have an XYY series that I would like to graph with matplot() or some other single function that will do the trick. The X in question is a vector of POSIXt values obtained from strptime(). Is it possible to tell matplot() how to handle POSIXt x values? I have examined the examples at http://lark.cc.ukans.edu/~pauljohn/R/statsRus.html#5.22 , but would prefer not have to overlay the

Hi. I have a correlation matrix 'x' which is of size 923x923 I need to remove variables that are highly correlated. I don't have a sophisticated way of selecting which of the two in a highly correlated pair to remove. I thought I would just go through each entry of the correlation matrix and if it is greater than 0.6 (or less than -0.6) I will remove that column and then redo the

I've searched the Web with Google and do not find what might cause this particular error from an invocation of cenboxplot: cenboxplot(cu.t$quant, cu.t$ceneq1, cu.t$era, range=1.5, main='Total Recoverable Copper', ylab='Concentration (mg/L)', xlab='Time Period') Error in if (n > 0) (1L:n - a)/(n + 1 - 2 * a) else numeric() : argument is of length zero I do

To whom it may concern: I am trying a factorial design a system of mine that has two factors. Each factor was set at four different levels, with one replication for each of the combinations. My data is as follows: A B Response 1 600 2.5 0.0257 2 600 2.5 0.0254 3 600 5