similar to: Coerce rectangular matrix to symmetrical square matrix

folks, if i have three matrices, a, b, cc with some colnames in common, and i want to create a matrix which consists of the common columns added up, and the other columns tacked on, what's a good way to do it? i've got the following roundabout code for two matrices, but if the number of matrices increases, then i'm a bit stymied. > a <- matrix(1:20,ncol=4); colnames(a) <-

Hi R users, I still have the problem about plotting. I wanted to put the datasets on one figure, x-axis represents values B, y-axis represents values C, while different colors label column A. Each record uses a circle on the figure, while hollow circles represent DF=1 and solid circles represent DF=2. I put my code below, but the A labels do not correspond to the true record, so I don't know

Hi Jim, For true color, I meant that the points in the figure do not correspond to the values from the dataframe. Also, why to use rainbow(9) here? And the legend is straight in the middle, is it possible to reformat it to the very bottom? Thanks again. On Sun, Jul 16, 2017 at 2:50 AM, Jim Lemon <drjimlemon at gmail.com> wrote: > Hi lily, > As I have no idea of what the "true

Hi lily, As I have no idea of what the "true record" is, I can only guess. Maybe this will help: # get some fairly distinct colors rainbow_colors<-rainbow(9) # this should sort the numbers in dfm$A dfm$Acolor<-factor(dfm$A) plot(dfm$B,dfm$C,pch=ifelse(dfm$DF==1,1,19), col=rainbow_colors[as.numeric(dfm$Acolor)]) legend("bottom",legend=sort(unique(dfm$A)),

For more than 10 records, how to reformat the colors? Also, how to show the first legend only, but at the bottom, while the second legend in your code is not necessary? In all, the same A values have the same color, but different symbols in DF==1 and DF==2. Thanks for your help. On Sun, Jul 16, 2017 at 9:28 AM, lily li <chocold12 at gmail.com> wrote: > Hi Jim, > > For true color,

Dear All - The problem: comment lines in an R function (lines beginning with # ) are *sometimes* removed on leaving the R default editor (same with notepad). I'm working on a Windows machine with R version 2.14.1. An example is below. Couldn't find anything that seemed to relate to this in the Changelog. I don't recall encountering this behavior with previous versions of R. Any

I have a binary matrix of size N x 300. I then create the following: > set.seed(1234) > (key_file <- sample(letters[1:4], 300, replace=TRUE)) [1] "a" "c" "c" "c" "d" "c" "a" "a" "c" "c" "c" "c" "b" "d" "b" "d" "b"

Hi, I searched the archives and did not find a good solution to that. assume I have 10 sets and I want to have the common character elements of them. how could i do that? -- Weiwei Shi, Ph.D Research Scientist GeneGO, Inc. "Did you always know?" "No, I did not. But I believed..." ---Matrix III

Hi, I am just wondering if there is an easy way to count in a numeric vector how many numbers don't have replicates. For example, a=c(1,1,2,2,3,4,5), how can I know there are three numbers (3, 4 and 5) without replicates? Thank you! Jun =====

Hi peoples, I'm trying to work out a function which will allow me to relace column names on the basis of substrings within the existing names. e.g. I'd like: blah.Na blah2.Na blah3.Mg blah4.Mg blah5.K blah6.K R1 x x x x x x R2 x x x x x x ... to become: Na (%) Na (%) Mg (%) Mg

... finding myself doing this by hand one too many times ... maybe someone else has found a nice general solution ... I have a data frame containing n rows on p+q variables which I will call p.1, p2, ..., pp and q1, q2, ... qq. For simplicity all of these variables are continuous numeric. I want to create the following arrangement of plots: A scatterplot matrix which contains p times q panels

Dear R-Listers, I have spatial data on an equidistant rectangular grid, similar to topographic data. I know that there are quite a few R-packages or base functions that provide nice iso-contours plot, but I don't want a plot, just the smoothed isocontour line of ONE level (e.g. 10 mm). Data sets are large, so it would be preferable if the availability of regular grid data could be exploited,

My client would like to add new functionality, such as call queuing, to their PBX. They presently have a Telrad PBX; it has a T1/PRI circuit from the CLEC and a few POTS lines. They use DID for some incoming calls and an attendant for calls on the main number. The client's commitment to customer service will not allow us to outright replace their PBX with a new system--we could never

Bare test code: My simple Java test class source and R test code follow: public class RJavTest { public static void main(String[]args) { RJavTest rJavTest=new RJavTest(); } public final static String conStg="testString"; public final static double con0dbl=10000001; public final static double[]con1Arr=new double[] { 10001,10002,10003,10004,10005,10006 }; public final static

On Wed, 9 Oct 2013 10:44:27 +0000 (UTC) Thorsten Glaser <tg at mirbsd.de> wrote: > Anil Singhar dixit: > > >Manual testing as provided within the package has been done with all > >tests passing. This includes the units tests available under > >usr/klibc/tests, usr/utils, usr/dash and usr/gzip. For dash and > >gzip, only sanity testing has been done. > >

Hello R-Group I found how to fill the data.frame -> http://finzi.psych.upenn.edu/R/Rhelp02a/archive/70843.html N1 <- rnorm(4) N2 <- rnorm(4) N3 <- rnorm(4) N4 <- rnorm(4) X1 <- LETTERS[1:4] ################### nams <- c(paste("N", 1:4, sep = ""), "X1") dat <- data.frame(lapply(nams, get)) names(dat) <- nams dat But I need also to create

does anyone know how to get ksh to use tab completion? -- Andrew Rice Jr Systems Analyst Carrier Management Systems, Inc. 500 Chestnut Street, Suite 500 Abilene, TX 79602 USA support: (325) 672-0975 office: (325) 677-5900 fax: (325) 676-0529 http://www.nams.net NAMS III, NAMS 2000 Centralized, NAMS BMX

I have some square matrices with na values in corresponding rows and columns. M<-matrix(1:2,10,10) M[6,1:2]<-NA M[10,9]<-NA M<-as.matrix(as.dist(M)) print (M) 1 2 3 4 5 6 7 8 9 10 1 0 2 1 2 1 NA 1 2 1 2 2 2 0 1 2 1 NA 1 2 1 2 3 1 1 0 2 1 2 1 2 1 2 4 2 2 2 0 1 2 1 2 1 2 5 1 1 1 1 0 2 1 2 1 2 6 NA NA 2 2 2 0 1 2 1 2 7 1 1 1 1 1 1 0 2 1 2 8

using vsftpd, I know its possible to specify what directory you want a user to be dropped into when he ftps in...but I dont remember where to go to change that. any suggestions? -- Andrew Rice Jr

Dear All, I would like to plot a scalar (e.g. a temperature) on a non-rectangular domain (or even better: I would simply like to be able to draw a contour plot on an arbitrary 2D domain). I wonder if there is any tool to achieve that with R. I did some online search in particular on the list archives, found several queries similar to this one but was not able to find any conclusive answer. I