similar to: Converting data.frame to xts

Displaying 20 results from an estimated 5000 matches similar to: "Converting data.frame to xts"

2011 Oct 03
1
xts/time-series and plot questions...
Hello, I'm a complete newbie to R. Spent this past weekend reading The Art of R Programming, The R Cookbook, the language spec, Wikis and FAQs. I sort-of have my head around R; the dizzying selection of libraries, packages, etc? Not really. I've probably missed or failed to understand something... I have very a simple data set. Two years (ish) of temperature data, collected and
2012 May 29
2
Converting to XTS loses data.frame structure
Hello, I noticed something odd when working with data frames and xts objects. If I read in a CSV file, R creates a nice data.frame. This works well. If I then convert to an XTS object, I see that all the values in the data are now quoted. My data is a mix of numeric and character. This is usually seen when converting a data.frame to a matrix, as R will treat all the data as the same class.
2012 Feb 16
3
Converting ts into xts and subsetting
Greetings, I would like to subset observations in a time series using xts, after converting from ts to xts. X=ts(1:100, frequency=12, start=c(1976)) X2=as.xts(X) X2["1984"] The output: Feb 1984 98 Mar 1984 99 Apr 1984 100 What happened to January? The index is always one month off, with X2["1976-01"] giving me Feb 1976. Should I set the time using something else
2009 Nov 16
0
OCaml-R and xts works!
Hi. I've managed to make a *very* simple wrapper around the xts library for R into OCaml. (Need to be downloaded from CRAN for OCaml users, but I expect other wrapping to be fairly similar...). The good, good, good thing (from my humble point of view) is that all loading is done statically: Loading the R interpreter is done statically. Loading the xts library is done statically... etc...
2011 Jan 04
1
XTS : merge.xts seems to have problem with character vectors
Hi, Please can you tell me what I am doing wrong. When trying to merge two xts objects, one of which has multiple character vectors for columns...I am just getting NAs. > str(t) POSIXct[1:1], format: "2011-01-04 11:45:37" > y2 = xts(matrix(c(letters[1:10]),5), order.by=as.POSIXct(c(t + 1:5))) > names(y2) = c(1,2) > y2 1 2 2011-01-04 11:45:38
2010 Aug 17
0
Merge xts
Hi all , I have 12 xts objects of differing timeseries stamp. For example : > str(s1_predict.xts) An ?xts? object from 1990-03-25 20:00:00 to 1990-12-15 09:00:00 containing: Data: num [1:725, 1] 11.23 10.18 9.3 9.74 10.18 ... - attr(*, "dimnames")=List of 2 ..$ : NULL ..$ : NULL Indexed by objects of class: [POSIXt,POSIXct] TZ: Original class: 'double' xts
2009 Sep 25
0
differing behaviour between xts (0.6-7) and zoo (1.5-8)
Folks, I have some weekly dataseries that I convert to monthly xts (with yearmon indices), and obtain the two following extracts: > str(sig) An 'xts' object from Apr 1998 to Sep 1998 containing: Data: num [1:6, 1] 0.0083 0.2799 -0.2524 -0.0119 0.18 ... - attr(*, "dimnames")=List of 2 ..$ : NULL ..$ : chr "e1" Indexed by objects of class: [yearmon] TZ:
2011 Nov 09
1
Are there equivalents to xblocks or rect that can be used with plot.xts?
I would like to add vertical shaded blocks in plot.xts graphs (like recession periods in FRED graphs) The reason I use plot.xts instead of plot.zoo is that I like the fact that the grid is automatically aligned with major ticks in plot.xts. xblocks() and rect() do not seem to work with plot.xts (only with plot.zoo). Are there any alternative methods that work with plot.xts? Thanks. -- View
2012 Mar 04
1
Store vectors as values in xts time-series object
Hi R programmers, I have stumbled across what seems a very simple problem. My goal is to create a xts time series object which contains vectors as values. In other words, I try to create something like this: 2009-01-01 => c('aa', 'bb', 'dd') ... 2010-02-01 => c('mm') I have figured out parts of separately. Here's what works (new xts time-series with
2015 Nov 04
1
setOldClass("xts")
Hello, I apologize that I am cross posting here after getting no answer from my initial question on stack overflow <http://stackoverflow.com/questions/33492601/r-setoldclass-only-if-needed>. I should certainly have posted it first here.. I am using 3 packages: - xts - quantmod - 'myPackage' quantmod is creating a union class by doing: setOldClass("xts");
2009 Sep 15
0
xts and data.frame question
Hello there! does any one know how to convert the following type of data > z DATE TIME ISIN PRICE VOL ID_DEAL RANK 1881 2009-09-11 10:30:59 RTS-9.09 117445 10 98200801 1 1882 2009-09-11 10:31:59 RTS-9.09 117450 1 98202144 6 1883 2009-09-11 10:32:59 RTS-9.09 117285 1 98203075 1 1884 2009-09-11 10:33:59 RTS-9.09 117180 3 98203828 1 1885 2009-09-11
2009 Nov 18
0
xts timeseries
Hi, I try to calculate the correlation between macroeconomic data from FRED vs Market Data However, since the timeseries are not in synch, the correlation fails. require(quantmod) USPBS =get(getSymbols("USPBS", src="FRED" )) USPBS = USPBS['1983-1-1::'] monDMANEMP = Cl(to.monthly(USPBS)) > length(monDMANEMP) [1] 312 > head(monDMANEMP) USPBS.Close
2011 Jul 30
1
Plot.xts - how to change the x-axis labels to show weekly labels.
Dear R-users I am new to R and struggling not to bother the list with silly questions. I read the documentation on xts and searched for some examples over the internet on how to use plot.xts. The xts object is as follows dataxts : An 'xts' object from 2010-06-27 to 2010-08-05 containing: Data: num [1:56161, 1:14] 74 74.2 74.2 74.1 73.9 ... Indexed by objects of
2010 Dec 06
1
as.xts error
Dear all, I am using the as.xts function to transfer a data frame to the xts The following is the code and result: a<-read.csv("price.csv") a$Date<-as.POSIXct(a$Date) str(a) 'data.frame': 15637 obs. of 2 variables: $ Date : POSIXct, format: "2010-01-04 09:45:01" "2010-01-04 09:45:02" "2010-01-04 09:45:03" ... $ bid_hsi: int 21850
2011 Dec 24
1
Optimising timeboxing in xts
I don't know if timeboxing is the correct term to use to accomplish what I'm attempting, so allow me to explain. I have a set n of tagged observations in time series t. What I'm interested in is taking i seconds before and after every n. My code is below: # observations.xts is an xts time series and arg is the number of seconds to for the timebox timeboxes <-
2009 Nov 12
1
xts conversion problem
I have two data frames, with two columns each, the first being a Date variable. I would like to convert them to xts objects, indexed by the Date column. I would like to use as.Date and not as.POSIXct as the dateformat. The puzzling fact is that it works for the first one but not the other. Here is a screenshot of the error: > str(DF1) 'data.frame': 367 obs. of 2 variables: $
2012 Jun 10
1
Gaps on merging xts objects
Looking for a little help figuring out what's driving gaps in data after merging two xts objects (msci.m and x2). The merge statement I'm using is ... y <-merge(x2,msci.m, all=FALSE). Here's info on the output , y: head(y) t-bill msci Sep 1985 7.310 316.963 Mar 1986 6.560 463.471 Jun 1986 6.180 498.791 Jul 1987 6.200 778.898 Aug 1987 6.400 833.519 Nov 1987
2012 Nov 30
1
xts indexed with Date class
Hi I see a changed behaviour in xts indexed on class Date in the latest versions, versus 2. It seems to be related to changes to/from daylight savings time, happens those weekends. Is it not intended that class Date be used like this, or is this new behaviour incorrect? Giles Example: > a<-as.Date(15423:15426) > x<-xts(seq_along(a),a) > print(x) [,1] 2012-03-24
2013 May 13
1
Math problem with xts objects
Hello, I coming across a strange problem doing math on an xts object. If I have an xts object of stock prices (perhaps 5 minute bars of open, high, low,close) and want to do some math, the results fail. For example: d$close[10] - d$open[10] works perfectly d$close[10] - d$open[9] fails. I just get an answer of "numeric(0) Index: numeric(0)". My guess is that xts is breaking
2009 Jun 25
1
apply on xts
Hi, I do not understand why after I called apply on a function that returns an xts (getIdvAdjSeries) it returns a matrix whose columns are just numeric value of time series in xts instead of a list of xts objects. Basically, I called the following: apply(matrix(tickers,ncol=1),1,FUN=getDivAdjSeries) getDivAdjSeries <- function(ticker) { seriesName <-