similar to: Bug in hist() when working with Dates ?

Hello, I have a problem with the hist() function and showing densities. The densities sum to 50 and not to 1! I use R version 2.9.1 (2009-06-26) and I load the seqinR library. My data is the following vector: [1] 0.1400000 0.2000000 0.2200000 0.2828283 0.1600000 0.1600000 0.3600000 [8] 0.1600000 0.2200000 0.2600000 0.2000000 0.3000000 0.2200000 0.2342342 [15] 0.1800000 0.2200000 0.1600000

Hi, I have a casting/formatting question on hist.POSIXt: The histogram plot from POSIXct works perfect (with help of Prof. Ripley -thanks!). When processing the hist(plot=FALSE) output and then plotting the results over the x-axis (bins) coming from hist(), I lose the date/time labels, getting instead integers displayed. Trying to cast the $breaks with as.POSIXct gives silly results with

Hi, I have a large amount of data that I would like to create a histogram of and plot and do things with in R. It is pretty much impossible to read the data into R, so I have written a program to bin the data and now have a list of counts in each bin. Is it possible to somehow import this into R and use hist(), so I can, for instance, plot the probability density? I have looked at the help page

Hi there, I hope this question is not as stupid as the one before ... I tried to shorten my histogram (because the distribution is quite skewed and I simply don't want to see the long tail but still use the histogram plot). How can I do something like this? (The example does not work but I don't know why...) data <- rnorm(100) # as example, of course this is not skewed... h <-

Hi all, I am trying to find a way to rename R objects with names pulled from a vector of names. For example, I have a data frame, my.data.frame, and a list of names, my.names. My.names is simply the column names of my.data.frame. I want save the histogram with the column name as the name of the object. for (i in 1:ncol(my.data.frame) { tmp<-hist(my.data.frame[,i])

Hello, all; I get an unexpected result when trying to plot a probability histogram with R1.9.1 on windows xp: #with the following code: > x <- runif(100,0,1) > hist(x) > hist(x, freq=F) > h <- hist(x, freq=F) > summary(h) # Length Class Mode #breaks 11 -none- numeric #counts 10 -none- numeric #intensities 10 -none- numeric #density 10

Dear All, I am a undergraduate using R for the first time. It seems like an excellent program and one that I look forward to using a lot over the next few years, but I have hit a very basic problem that I can't solve. I want to produce a standardised histogram, i.e. one where the area under the graph is equal to 1. I look at the manual for the histogram function and find this: freq:

I have two large datasets (156K and 2.06M records). Each row has the hour that an event happened, represented by an integer from 0 to 23. R's histogram is combining some data. Here's the command I ran to get the histogram: > histinfo <- hist(crashes$hour, right=FALSE) Here's histinfo: > histinfo $breaks ?[1] ?0 ?1 ?2 ?3 ?4 ?5 ?6 ?7 ?8 ?9 10 11 12 13 14 15 16 17 18 19 20 21

With R and the hist function, is there a way to make a histogram in which the y axis denotes propotion with respect to a separate sample dataset of the same range instead of frequency? [[alternative HTML version deleted]]

Hello! Up to now I have been using hist() to display the distributions. Howevere, I noteiced strange numbers on y (vertical) axis, if I used probability = T or freq = F option. I thought it is a bug and launched the R-bug system and found some posts on that matter. Brian Ripley responded to one, that one should look at truehist() for that. Ok I can use truehist() if I want to see the ratios

Hi, if I dermine the break points using the hist() function and then try to re-use these in a new histogram, R fails. Here is an example of the problem: ##First, plot a histogram: data(islands) foo <- hist(islands,freq=T) ##Now, try plot it again, with the previously determined break points: hist(islands,breaks=foo$breaks,freq=T) ##... this lead to the warning message: Warning message:

Hi all, In the histogram created with the `hist` command, the label of the y axis reads "Frequency ?. Finding that the ylab key is used to change (localize) that word may seem difficult for people who are beginners either in R or in english. I suggest very minor modifications of the file hist.Rd at https://svn.r-project.org/R/trunk/src/library/graphics/man/hist.Rd. 1) make the default value

Hello all, I'm trying to make a histogram of the data contained in my dataframe. The summary of the data gives me exactly what I want summary (Data) V1 V2 first001: 3 last001: 9 first002: 3 last002: 7 first003: 2 last003: 6 (Other) :52 (Other): 27 But how do I capture the names and values in vectors so I can plot them?

Dear: I want to plot barplot and let bar be in the middle of each x axis category. Do you have this experience? Many Thanks! Xin [[alternative HTML version deleted]]

There were some questions about hist() a couple of days ago which triggered this post. My question/suggestion is about the y-axis in hist. There are reasons to prefer making the y-axis density=relative frequency/bin width. One reason is that the height of the plot does not depend on the bin width; another is that if your histogram is in density then you can easily superimpose a smooth theoretical

Hi, I have several files with data in this format: 20070102 20070102 20070106 20070201 ... The data is sorted and each line represents a date (YYYYMMDD). I would like to analyze this data using R. For instance, I would like to have a histogram by year, month or day. I've already made a simple Perl script that aggregates this data but I believe that R can be much more powerful and easy on

Dear developers, the current implementation of hist.default() calculates 'density' (and 'intensities') as dens <- counts/(n*h) where h has been calculated before as h <- diff(fuzzybreaks) which results in 'fuzzy' values for the density, see e.g. > tmp <- hist(1:10,breaks=c(-2.5,2.5,7.5,12.5),plot=FALSE) > print(tmp$density,digits=15) [1]

In R0.61, In hist(), should the line rel.freqs <- counts/(sum(x) * diff(breaks)) computing the relative frequencies or height of the rectangles in a histogram not be rel.freqs <- counts/(sum(counts) * diff(breaks)) instead, or do I misunderstand something? Thanks, Philippe -- -------------------------------------------------------- Philippe Lambert Tel:

Just for the record, here are my steps for producing a date based histogram. Data is stored in a file where each line only has a date - 2007/02/16 >d<-readLines("filename.dat") >d<-as.Date(d, format="%Y/%m/%d") >pdf(yearly.pdf) >hist(d, "years") >dev.off() Instead of "years" you can also use "days", "weeks",

Hi, What's the best way to average dates? I though mean.POISXct would work fine but... > a [1] "2007-04-02 19:22:00 WEST" > b [1] "2007-03-17 16:23:00 WET" > class(a) [1] "POSIXt" "POSIXct" > class(b) [1] "POSIXt" "POSIXct" > mean(a,b) [1] "2007-04-02 19:22:00 WEST" > mean(b,a) [1] "2007-03-17