similar to: preparing data for barplot()

Hi, I'm a R newbie and want to accelerate the following pre-filtering step of a data set with more than 115,000 rows : #----------------- # Function to filter out constant data columns filter.const<-function(X, vectors=c('column', 'row'), tol=0){ realdata=c() filteredX<-matrix() if( vectors[1] == 'row' ){ for( row in (1:nrow(X)) ){ if(

Dear list, It seems that S4 methods defined for an S3 'base' generic are not used in 'base' functions. This can be problematic when 'base' functions start with something like 'as.matrix'. ### START R code setClass("classA", contains = "matrix", representation(realData = "numeric")) setMethod("as.matrix",

Dear R helpers Suppose val1 = c(10, 20, 35, 80, 12) val2 = c(3, 8, 11, 7) I want to select either val1 or val2 depending on value of third quantity val3. val3 assumes either of the values "Monthly" or "Yearly". If val3 = "Monthly", then val = val1 and if val3 = "Yearly", then val = val2. I tried the ifelse statement as ifelse(val3 =

Hello list, I am wondering if a joining "one-to-many" can be done a little bit easier. I tried merge function but I was not able to do it, so I end up using for and if. Suppose you have a table with locations, each location repeated several times, and some attributes at that location. The second table has the same locations, but only once with a different set of attributes. I would

Hi, there: I spent some time on this but I think I really cannot figure it out, maybe I missed something here: my data looks like this: > dim(trn3) [1] 7361 209 > dim(val3) [1] 7427 209 > mg.rf2<-randomForest(x=trn3[,1:208], y=trn3[,209], data=trn3, xtest=val3[, 1:208], ytest=val3[,209], importance=T) my test data has 7427 observations but after prediction, > dim(mg.rf2$votes)

Dear all, I want to calculate mean values for multiple rows: structure(list(Name = structure(c(1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L), .Label = c("AKT", "CKT"), class = "factor"), val1 = c(2, 3, 2, 2, 2, 5, 3, 8, 2), val2. = c(4, 5, 4, 8, 4, 8, 4, 7, 4), val3 = c(5, 6, 5, 9, 5, 9, 5, 9, 5)), .Names = c("Name", "val1", "val2.",

Hi, XML doesn't use the `$` to access child nodes. Instead use either `[name]` to get a list of children of that name or `[[name]]` to get the just the first child of that name encountered in the genealogy. Thus for your example... > root$child1 NULL > root[['child1']] <child1 name1="A" name2="B" name3="C"/> On the other hand, you might

Big thanks. newXMLNode works great. Wonder why it is not included in the documentation. There is newXMLDoc and newXMLNamespace, but no mention of newXMLNode. Stephen From: Ben Tupper [mailto:btupper at bigelow.org] Sent: Wednesday, March 21, 2018 6:18 PM To: Bond, Stephen Cc: r-help Subject: Re: [R] how to add a child to a child in XML Hi, XML doesn't use the `$` to access child nodes.

Hello, I would like to be able to plot an array on a plot, something like: |arg1 | arg2 | arg3 val1| 0.9 | 1.1 | 2.4 val2| 0.33 | 0.23 | -1.4 val3| hello| stop | test I know Rwave is good to report but don't want to use it. ? Is there a package that allow quick and dirty plot of dataframes like this ? Thanks a lot -- View this message in context:

Hello R-Help, ----------------------------------------------------------------------------------------------------------------------------------------- Issues (there are 2): 1) Possible bug when using lmtest::encomptest() with a linear model created using nlme::lmList() 2) Possible modification to lmtest::encomptest() to fix confusing fail when models provided are, in fact, nested. I have

Hi, It's a reasonable question. The answer is that it actually is included, but there are many instances across packages where multiple functions are documented on a single help page. The following brings up such a page... (for XML_3.98-1.9) > library(XML) > ?newXMLNode You can see the same on line... https://www.rdocumentation.org/packages/XML/versions/3.98-1.9/topics/newXMLDoc

I am trying to add a child to a child using XML package in R. the following fails library(XML) node1 <- c("val1","val2","val3") names(node1) <- c("att1","att2","att3") root <- xmlNode("root", attrs=node1) node2 <- LETTERS[1:3] names(node2) <- paste("name",1:3,sep="") root <-

Just to clarify and hopefully catch the attention of the maintainer: The newXMLNode function is not mentioned in: https://cran.r-project.org/web/packages/XML/XML.pdf which supposedly describes all functions in the package. Stephen From: Ben Tupper [mailto:btupper at bigelow.org] Sent: Thursday, March 22, 2018 10:40 AM To: Bond, Stephen Cc: r-help Subject: Re: [R] how to add a child to a

I got simple x,y pairs of data and simple scatterplot and just cannot figure how to do it , there are many examples but always there is error popping out please show me an example stripped with additional data just core of what I need to do to get this damn line -- View this message in context:

I'd like to convert a dist into a table/matrix/thingy of the form: A B value A C value B C value (assuming the dist was over 3 names). Is there a way to do this without using a for loop? -- Taral <taralx at gmail.com> "Please let me know if there's any further trouble I can give you." ? ? -- Unknown

Dear R users, I am facing a pretty a unusual problem while converting character to numeric. Any input would be appreciated. Below is the code and error faced: --------------------------------------- *> str(cmie.dts)* *'data.frame': 4397 obs. of 1 variable:* * $ INE001A01036: chr "1482181740.000000" "1482181740.000000" "1482181740.000000"

Hi, I am running my code in a cluster at Arizona State University. I have a huge climate data, 66000 X 500 I am not sure if I can find correlation of such a huge data in the cluster. Normally I allocate 20000M and operate on 5 X 20000. Even this is taking lot of time. Is there any way I can find cl = cor(cdata) utilizing the computers in the clusters(I am using 32 nodes ). I am using the

As a java programmer, I'm having issue conceptualizing the following use case: Given an value, passed into a function, how do I pull out the lookup? Ie. A list of keys (key1, key2, key3) A list of values (val1,val2,val3) I want to write a function (or is there something built in?) such that Callit <- (thekey) { (magic happens here) Return value } Any ideas? Thanks a bunch!

Hi, i do have a dataframe representing data from a repeated experiment. PID is a subject identifier, Time are timepoints in an experiment which was repeated twice. For each subject and all three timepoints there are 2 sets of four values. df <- data.frame(PID = c(rep("A", 12), rep("B", 12), rep("C", 12)), Time = rep(c(0, 0, 0, 0, 30, 30, 30,

Dear useRs, i have certain commands for some operations in R. They are good if you have a small dataset but my dataset, apart from what i used in the recent past, is prety large. I want to convert these massive sets of commands into a simple loop. Your help is required on it thanks in advance eliza kindly note: "e" is matrix whose each column has to be executed into a distance vector