similar to: Umlaut read from csv-file

Dear All, Encoding() goes beyond my understanding. See the example. I would expect from reading the help for Encoding() that strsplit preserves the encoding for each resulting element, but for simple letters it gets lost. Also it seems that an Encoding() cannot be declared for simple letters. They remain in any case "unknown". In paste() "latin1" seems to dominate

Dear All! If I try to compare the attributes of two objects, I find a surprising behaviour of attr.all.equal(). With identical attributes I receive the answert NULL. If the attributes differ, the answer is as expecxted and differences are shown. all.equal(attributes(), attributes()) instead returns TRUE, if attributes are equal. See example: v <- 1:5 attr(v, 'testattribute')

Dear All, trying to write a data.frame, containing Surv objects to a csv-file I get "Error in dimnames(X) <- list(dn[[1L]], unlist(collabs, use.names = FALSE)) : length of 'dimnames' [2] not equal to array extent". See example below. May be, I overlooked something, but I expected that also data.frames containing Surv objects may be written to csv files. Is there a

Dear All, to drop unused factor levels two ways are outlined in R-help. In both cases a label attribute is lost. The same happens, when using car:::recode. Is there a simple way to avoid losing attributes? Thanks, Heinz ## example ff <- factor(substring("statistics", 1:10, 1:10), levels=letters) attributes(ff)$label <- 'test label' attributes(ff)$label gg <- ff[,

hi, i'd like to install the package "RGoogleDocs ". i downloaded to path "E:/R/R-2.13.0/library/RCurl_0.91-0.tar.gz" i run R from an usb-stick and can't get the install.packages() prompt to run correctly - can anyone help with this? thanks, kay > sessionInfo() R version 2.13.0 (2011-04-13) Platform: i386-pc-mingw32/i386 (32-bit) locale: [1]

Dear R-users, I am working with R version 2.10.1 and package RODBC Version: 1.3-2 under windows. Say I have a table "testtable" (in an Access data base) with 3 columns and 1 row that looks like this: X Y Z 0012345 42 42,1 The columns are of these types: X - character, Y - Long Integer, Z - Decimal. I use RODBC to get these data into R: > library(RODBC) >

I have newly installed R, R-tools, RStudio, but still not working: library(caret)Lade n?tiges Paket: latticeError: Laden von Paket oder Namensraum f?r ?caret? in loadNamespace(i, c(lib.loc, .libPaths()), versionCheck = vI[[i]]): fehlgeschlagen Namensraum ?vctrs? 0.5.2 ist bereits geladen, aber >= 0.6.0 wird gefordert Error in createDataPartition(hypotezis_df$X, p = 0.75, list = FALSE, times

Many thanks Bert, now is ok, i did not know that "Namensraum" should mean a package Am So., 16. Apr. 2023 um 23:44 Uhr schrieb Bert Gunter < bgunter.4567 at gmail.com>: > So update the vctrs package to the latest version first before loading > R-tools (or the caret package, specifically)? > > -- Bert > > On Sun, Apr 16, 2023 at 1:57?PM G?bor Malomsoki >

So update the vctrs package to the latest version first before loading R-tools (or the caret package, specifically)? -- Bert On Sun, Apr 16, 2023 at 1:57?PM G?bor Malomsoki <gmalomsoki1980 at gmail.com> wrote: > > I have newly installed R, R-tools, RStudio, but still not working: > > library(caret)Lade n?tiges Paket: latticeError: Laden von Paket oder > Namensraum f?r

Hello! A problem with special characters seemed to me to be a bug. I sent a mail to R-windows at r-project.org concerning the problem (see below). How can I find out, if this is considered as a bug or an error of myself? Which part of FAQs or documentation did I miss to find the answer? thanks in advance Heinz T??chler -------------------- copy of abovementioned mail ---------- to: R-windows

Dear All, it seems to me that the function read.spss of package foreign changed its behaviour regarding factors. I noted that in version 0.8-8 variables with value labels in SPSS were transformed in factors with the labels in alphabetic order. In version 0.8-10 they seem to be ordered preserving the order corresponding to their numerical codes in SPSS. However I could not find a description of

Dear All, it seems to me that the function read.spss of package foreign changed its behaviour regarding factors. I noted that in version 0.8-8 variables with value labels in SPSS were transformed in factors with the labels in alphabetic order. In version 0.8-10 they seem to be ordered preserving the order corresponding to their numerical codes in SPSS. However I could not find a description of

Hello, it seems that the main results of survival analysis with package survival are shown only as side effects of the print method. If I compute e.g. a Kaplan-Meier estimate by > km.survdur<-survfit(s.survdur) then I can simply print the results by > km.survdur Call: survfit(formula = s.survdur) n events median 0.95LCL 0.95UCL 100.0 58.0 46.8 41.0 79.3 Is

Dear All, to produce output of several columns of a data frame, I tried to use lapply and also l_ply. In both cases, I would like to print a header line containing also the name of the respective column in the data frame. For example, I would like the following lapply(data.frame(a=1:3, b=2:4), function(x) print(deparse(substitute(x)))) to produce: [1] "a" [1] "b" and

Dear All, is there a simple way to print a data.frame without its row.names? example: datum <- as.Date(c("2004-01-01", "2004-01-06", "2004-04-12")) content <- c('Neujahr', 'Hl 3 K.', 'Ostern') df1 <- data.frame(datum, content) print(df1) datum content 1 2004-01-01 Neujahr 2 2004-01-06 Hl 3 K. 3 2004-04-12 Ostern Can I get

Dear All, where can I find information about how to write an assigment form of a function? For curiosity I tried to write a different form of the levels()-function, since the original method for factor deletes all other attributes of a factor. Of course, the simple method would be to use instead of levels(x) <- newlevels, attr(x, 'levels') <- newlevels. I tried the following: ##

Dear All, to my surprise as.factor does not accept a levels argument. Maybe I did not read the documentation well enough. See the example below. I wanted to use ch1 as factor in the newdata argument of survfit, so I assumed that I could write as.factor(ch1, levels=ch1), since the order should be kept. But as.factor(ch1, levels=ch1) results in the error: Error in as.factor(ch1, levels = ch1)

Dear All! For descriptive purposes I would like to add attributes to objects. These attributes should be kept, even if by indexing only part of the object is used. I noted that some attributes like levels and class of a factor exist also after indexing, while others, like comment or label vanish. Is there a way to make an arbitrary attribute to be kept after indexing? This would be especially

Dear All, Assume I have a data.frame that contains also factors and I would like to get another data.frame containing the factors as numeric vectors, to apply functions like sapply(..., median) on them. I read the warning concerning as.numeric or unclass, but in my case this makes sense, because the factor levels are properly ordered. I can do it, if I write for each single column

Dear All! If I pass an object to an assignment function I cannot get it's name by deparse(substitute(argument)), but I get *tmp* and I found no way to get the original name, in the example below it should be "va1". Is there a way? Thanks, Heinz ## example 'fu1<-' <- function(var, value) { print(c(name.of.var=deparse(substitute(var))))} fu1(va1) <- 3 name.of.var