similar to: weird behavior with the 3rd root....

my problem can be explained with the following example: x <- 1:12 y <- 13:24 a <- data.frame(x = x, y = y) ## if i write a$x ## it returns [1] 1 2 3 4 5 6 7 8 9 10 11 12 ## but the function get doesn't recognize a$x. Instead it produces the following error: get("a$x") Error in get(x, envir, mode, inherits) : variable "a$x" was not found i intend to do

Dear users, I got this problem and i don't have a clue of what it could be happening... The context: i'm running a loop in which i extract information from a raster map (I work with GRASS and R, using spgrass6 package), and rearrange it to create a matrix. I've tried it with small maps and it works smoothly, but in large maps I have to resort to saving data in the hard disk regularly

Hello list! i write because i'm having a strange problem with the "save" function, here an example: > x <- stats::runif(20) > y <- list(a = 1, b = TRUE, c = "oops") > save(x, y, file = "xy.Rdata") > xy <- load("xy.Rdata") > xy [1] "x" "y" why does this happens, when: > x [1] 0.96586833 0.60340508

?Hello everyone, I guess this is really directed to the R Core Team, but I understand that this is the best channel to submit this (please correct me if I'm wrong!). I would like to submit a function to consideration, as an upgrade for the current read.arff in package foreign. Code in github: https://raw.githubusercontent.com/jumanbar/misc/master/R/read.arff.R This function is a modified

Dear All, The function curve() draws the graph of functions from R to R. Is there some homologous function to curve() to draw functions from R^2 to R? Thanks in advance, Paul

I want to generate a valid variance-covariance matrix. One way could be to generate some random sample from multivariate normal distribution and then calculate cov. matrix. Another way could be to sample from wishart distribution itself. However both cases need a valid i.e. PD covariance matrix. As I need to generate that covariance matrix only, I am not interested those two methods. Can anyone

Hi R-helpers, I have two queries relating to generalising to n dimensions: What I want to do in the first one is generalise the following statement: expand<-expand.grid(1:x[1],1:x[2],...1:x[n]) where x is a vector of integers and expand.grid gives every combination of the set of numbers, so for example, expand.grid(1:2, 1:3) takes 1,2 and 1,2,3 and gives 1,1 2,1 1,2 2,2 1,3 2,3 My x

Hi, This might be me missing something painfully obvious but why does the cube root of the following produce an NaN? > (-4)^(1/3) [1] NaN > As we can see: > (-1.587401)^3 [1] -4 Thanks! Greg

This is some interesting: > -8^(1/3) [1] -2 > x=(-8:8) > y=x^(1/3) > y [1] NaN NaN NaN NaN NaN NaN NaN NaN 0.000000 1.000000 [11] 1.259921 1.442250 1.587401 1.709976 1.817121 1.912931 2.000000 So, can anybody explain this?! (Why is x[1]^(1/3)=y[1]=NaN, but -8^(1/3)=-2?) Thx!!! [[alternative HTML version deleted]]

hi all why does R do this: (-8)^(1/3)=NaN the answer should be : -2 a silly question but i kept on getting errors in some of my code due to this problem. i solve the problem as follows: say we want : (-a)^(1/3) then : sign(a)*(a^(1/3)) works but there has to be a simpler way of soing such a simple mathematical operation. thanking you / allan

Dear Listers, I've been a big fan of R since graduate school. After working in the industry for years, I haven't had many opportunities to use R and am mainly using SAS. However, I am still forcing myself really hard to stay close to R by reading R-help and books and writing R code by myself for fun. But by and by, I start realizing I have hard time to keep up with R and am afraid that I

Hi, > 1e10+5i [1] 1e+10+0e+00i > Im(1e10+5i) [1] 5 maybe little better... --- R-3.5.1.orig/src/main/complex.c 2018-03-26 07:02:25.000000000 +0900 +++ R-3.5.1/src/main/complex.c 2018-07-10 12:50:42.523874767 +0900 @@ -381,6 +381,7 @@ r->i = fround(pow10 * x->i, digits)/pow10; } else { digits = (double)(dig); + if(digits < 1) digits=1; /* a little better */

I am debugging some code and found a function that returns and error most of the time. I have issolated the problem to when it raises an argument to the 1/3 power but for the life of me I can not figure out why it is not working. i have gone through the FAQs and have found nothing (not to say I might have missed something). I am highly embarrased with my inability find the problem (my face is

Why does the expression "(-8)^(1/3)" return NaN, instead of -2? This is not answered by http://cran.r-project.org/doc/FAQ/R-FAQ.html#Why-are-powers-of-negative-numbers-wrong_003f Thanks, Dave [[alternative HTML version deleted]]

Hi I have several methods for evaluating a function. The methods are algebraically identical but use different numerical techniques. The different methods work better (converge faster, etc) in different parts of the function's domain. I am compiling a test suite for a package, and would like to verify that the different methods return approximately identical results. Toy example

Hello everyone I am finding complex numbers to be printed oddly in R-alpha. > 1e100+1e100i [1] 1e+100+1e+100i > 1e100 + 1e44i [1] 1e+100+100000000000000008821361405306422640701865984i > dput(1e100+1e44i) 1e+100+100000000000000008821361405306422640701865984i > [same thing at home on a linux box] The first line is what I would expect, the second and third lines aren't: I

Hi, Recently i have worked on re-writing beryl's transparent cube, and ported 3d plugin to compiz. I'm attaching a patchset here that includes the transparent cube patches (i'll post the 3d plugin when i fix some problems that didn't happen in beryl). Patching order: btf-ftb.patch, clip-planes.patch, plugin-events.patch, cube-paint-order.patch, transparent-cube.patch. Special

Dear colleagues, I have the following code. This code is to 'filter' the data set. It works on the data frame 'whole' with four numeric columns: a,b,d, and c. Every row in the data frame is considered as a point in 3-D space. Variables a,b, and d are the point's coordinates, and c is its value. This code looks at every point, builds a cube 'centered' at this

Hello, I'm having what seems like a weird issue connecting Asterisk 13 (FreePBX 12) to a Cisco 2811 router via a chan_sip trunk. Whenever I try dialling out via this trunk, something appends '@CUBE' onto the end of the dialled number, as per the following examples; Asterisk log; app_dial.c: Called SIP/test/0429123456 at CUBE chan_sip.c: Got SIP response 500 "Internal Server

Currently, the cube plugin uses mipmapping only when cube is unfolded. When the cube is rotated, mipmaps are not used, which leads to ugly look of textures. The attached patch fixes this. This leads to another kind of artifacts, which are fixable with anisotropic filtering. http://team.pld-linux.org/~wolf/aniso.png The leftmost image is the current state of cube plugin. The center image is with