Displaying 20 results from an estimated 5000 matches similar to: "VEC Operator in R"
2008 Oct 23
1
Calculating confidence limits for the difference betweenmeans
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Subject: Re: [R] Calculating confidence limits for the difference between	means
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Recipient: ngottlieb at marinercapital.com
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2008 Oct 20
3
A question about positive definite matrix
I know, this is a forum about R.  But I am so desperate of this problem (BTW,
anyone knows any good Statistics/Math forum to post question like this?):
A and B are both n x n positive definite matrix.
Denote A > B, if A - B is positive definite.
I know this is true: if A > B, then A^{-1} < B^{-1}.  But how to prove this?
I tried to diagonalize A and B, but since they can have different
2008 Oct 23
3
xy.coords in text
Hello,
I want to add text annotation about correlation on "pairs" plots. I
found that I could pass a function to the "panel" argument of pairs :
  panel.annot <- function(x, y, ...) {
    points(x, y, ...)
    c <- cor.test(x, y)
    legend("topleft", legend=substitute(rho == r, list(r=sprintf("%.2f",
c$estimate))), bty="n")
  }
And then :
2008 Oct 22
3
Help finding the proper function
This might not be the correct forum for this question for there might be some
flaws in my logic so the R function I'm looking for might not be the
correct, but I know there?s a lot of smart people in this forum so please
correct me if I'm wrong. I have been googling and searching in this forum
for something useful but so far I'm out of luck.
This is the background to my problem. I
2008 Oct 23
2
I have an xyplot, I want to keep the format, but only show x or y
Good Morning,
I am using xyplot to show two variables for a large number of 
subjects.
Currently I am using xyplot(y~x|as.factor(ID), layout=c(7,9)) to 
give me a little plot of the x and y factors for each ID.
The purpose of the plot is to let the PI quickly look through the 
data for irregularities.
The good news is that they like the layout of the xyplot, but they 
don't want to have to
2008 Oct 23
4
odfWeave error
odfWeave is throwing up a cryptic error, after successfully processing a 
file with a large number of figures (~30) and many \Sexpr{} calls.  The 
error is (at least to me) cryptic. I am not sure where to look to 
correct this problem.
Here's the error:
Post-processing the contents
Error in .Call("RS_XML_Parse", file, handlers, endElementHandlers, 
as.logical(addContext),  :
 
2008 Oct 22
3
Substitute problem
hello R users,
I didn't find a solution for a special problem.
I have two dataframes.
dataframe1:
  X        value    	 row    	 col 		           ID           
 1  8.973498062 	5512625 	3460000  	1 
 2 11.656658570 	5501625 	3464000  	2  
 3 11.121777570 	5495625 	3473000  	3 
 4  9.310465964 	5508625 	3477000  	4 
 5  8.883483845 	5515625 	3496000  	5 
dataframe2:
  X        value    	
2008 Oct 24
0
following up on infinite email server loop
just to add to ted's explanation in case it helps to fix the email 
server problem: below are the two Recipients  and one of the two is 
always contained in the repeated emails that I'm receiving.  Also,  of 
course i don't mean to claim that the names contained in below are 
doing anything to cause the problem .  VEC Operator is just an example. 
There are 3 or 4 others that repeat
2008 Oct 24
2
plotrix and prettyR
Hi folks,
Both plotrix and prettyR have been updated. plotrix now has the "Matlab" 
style dotplot that was requested not long ago on the list, provided by 
that intrepid duo, Barry Rowlingson and Rolf Turner. Mike Cheetham has 
contributed an implementation of the Piper diagram, also in response to 
a request. prettyR has finally learned how to display SPSS value labels 
in the xtab and
2008 Oct 23
1
[R-SIG-Finance] forecasting earnings, sales and gross margin of a company...
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Subject: Re: [R] [R-SIG-Finance] forecasting earnings,	sales and gross margin of a company...
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Recipient: ngottlieb at marinercapital.com
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2008 May 14
4
Accessing items in a list of lists
Using R 2.6.2, say I have the following list of lists, "comb":
data1 <- list(a = 1, b = 2, c = 3)
data2 <- list(a = 4, b = 5, c = 6)
data3 <- list(a = 3, b = 6, c = 9)
comb <- list(data1 = data1, data2 = data2, data3 = data3)
So that all names for the lowest level list are common.  How can I most
efficiently access all of the sublist items "a" indexed by the outer
2013 Mar 08
2
Unexpected behaviour of apply()
Hello everyone,
Considering the following code sample :
----
indexes <- function(vec) {
    vec <- which(vec==TRUE)
    return(vec)
}
mat <- matrix(FALSE, nrow=10, ncol=10)
mat[1,3] <- mat[3,1] <- TRUE
----
Issuing apply(mat, 1, indexes) returns a 10-cell list, as expected.
Now if I do:
----
mat[1,3] <- mat[3,1] <- FALSE
apply(mat, 1, indexes)
----
I would expect a
2007 Jun 12
3
Read Windows-like .INI files into R data structure?
I need to process some datasets where the configuration information was 
stored in .INI-like files, i.e., text files with sections like this:
[Section1]
var1=value1
var2=value2
[Section2]
A=value3
B=value4
...
>From Google and other searches I haven't found any package, or function 
within a package, that reads .INI files into an R list, or other data 
structure.
Any suggestions, or
2016 Aug 04
1
findInterval(all.inside=TRUE) for degenerate 'vec' arguments
What should findInterval(x,vec,all.inside=TRUE) return when length(vec)<=1,
so there are no inside intervals?
R-3.3.0 gives a decreasing map of x->output when length(vec)==1 and -1's
when length(vec)==0.  Would '0' in all those cases be better?
> findInterval(x=c(10, 11, 12), vec=11, all.inside=TRUE,
rightmost.closed=FALSE, left.open=FALSE)
[1] 1 0 0
>
2011 Jul 23
1
Achieving 'reverse-Vech' of a matrix
Let say i have a square matrix and applied the 'vech' operator to stack the lower triangular elements into a vector:
> Mat <- matrix(1:25, 5)
> Mat
? ? ?[,1] [,2] [,3] [,4] [,5]
[1,] ? ?1 ? ?6 ? 11 ? 16 ? 21
[2,] ? ?2 ? ?7 ? 12 ? 17 ? 22
[3,] ? ?3 ? ?8 ? 13 ? 18 ? 23
[4,] ? ?4 ? ?9 ? 14 ? 19 ? 24
[5,] ? ?5 ? 10 ? 15 ? 20 ? 25
> Mat[lower.tri(Mat)]
?[1] ?2 ?3 ?4 ?5 ?8 ?9 10 14
2012 Oct 08
1
Diagnostic testing in a VEC
Hi everyone,
I'm using the Johansen framework to determine a VEC using package urca. I
have estimated the corresponding VEC using likelihood ratio test for
restrictions on alpha, beta or both and I have generated objects of the
class cajo.test. Now I want to diagnostic tests in the model,
like heteroskedasticity test, residuals normality and serial
autocorrelation, but I cannot find the way
2006 Sep 09
2
duplication matrix
Dear R-list members,
Just wondering if there is any way to compute the duplication matrix in R.
I tried to search for it but only found functions "xpnd" and "vech".
Basically for a symmetric n by n matrix A, the duplication matrix D_n is
a matrix of dimension n^2 by n(n+1)/2 such that
D_n vech(A)= c(A), where c(A) just vectorizes A. 
The duplication matrix is defined on page
2012 Jan 04
3
[newbie] stack operations, or functions with side effects (or both)
summary: Specifically, how does one do stack/FIFO operations in R?
Generally, how does one code functions with side effects in R?
details:
I have been a coder for years, mostly using C-like semantics (e.g.,
Java). I am now trying to become a scientist, and to use R, but I don't
yet have the sense of "good R" and R idiom (i.e., expressions that are
to R what (e.g.) the Schwartzian
2020 Nov 16
2
RFC: [SmallVector] Adding SVec<T> and Vec<T> convenience wrappers.
On Mon, Nov 16, 2020 at 12:55 PM David Blaikie <dblaikie at gmail.com> wrote:
> I will say I'm not a huge fan of adding even more names for things in
> this fairly core/common use case (now we'll have even more vector
> names to pick from) - can we use default template arguments so we can
> write SmallVector<T> instead of SmallVector<T, N> and would that
>
2004 Jun 18
1
Is there an easy way to generate linearly independent vec tors
I believe eigen(), svd() and qr() can all do it.
Andy
> From: Jonathan Baron
> 
> On 06/17/04 19:04, Fred wrote:
> >Dear R-listers:
> >
> >I am trying to test an algorithm on a set of linearly 
> independent vectors
> >{x1,x2,...,xn}.
> 
> Well, here's an idea, for 10 vectors of length 10,
> as columns of a matrix m1.  The 11th seems to be needed.