similar to: Saving environment object

Hi, I would like to convert a simple list into an environment object. It seems I have to create an environment object with new.env() and assign the single values afterwards. Now what I did not really understand from the guides until now is, how the parent environment supplied to the new.env() function influence the final environment. So: 1. Do I ALWAYS have to supply a parent during creation? 2.

Hi All, I am trying to lable the y-axis on my scatterplot with the following: "Soil moisture content (m3m-3)" I am using the following coding for plotting the graph: plot(soilmoisture~gradientlevel, xlab="Levels of droughting gradient", ylab="Soil moisture content (m3m-3)", bty="l", font.main="2", pch=16, las=1, cex.lab="1.13") I have

Hi, Plotting a graphic into a postscript device using family="mono" returns the following error message: >> family 'mono' not included in PostScript device Looking at postscriptFonts() however lists the "Courier" font as availeable mono font. So where is the problem? Thanks guys for your help. Best regards Benjamin sessionInfo() R version 2.5.0

hi, I'd like to do graphs like shown on the right panel on the following link: http://www.clinchem.org/cgi/content/full/53/8/1544/F1 (if link doesn't work see attached file) Any help and ideas highly appreciated, thanks in advance. Thomas von K?nel Human Genetics Uni Berne

Dear all I am new R user, and trying to learn more. I am doing linear regression analysis in R with my data. I am trying to find the way to calculate the slope value (coefficient of x) to degree of slope. Please give me idea on this. Thanking you in anticipation Warm regardMS _________________________________________________________________ [[alternative HTML version

Hi all, I would like to replace the for loop in the code below with a function to improve the speed and to make the script more efficient. The loop creates a vector of integers (x) with the probability of f for each integer. The length of f is variable, but sums to 1. I tried to use a function with optional arguments which did not work. Here is the code: f <- data.matrix(c(0.5,0.15,0.35))

Dear R-user Suppose I have the following data y=c(2,1,5,8,11,3,1,7,50,21,33,7,60) x=data.frame(y) for(i in 4:nrow(x)) x[i,] =var(x[i-3:i-1,]) I'm trying to get a new variable with the variance of the 3 previous values (just an example) and with NA in the three first positions. I know that my for() is wrong but I'm not able to find my error. Any idea? Thanks, Marlene.

Hi all, I have two vectors (columns) called "efinal" and "efinal 2". I want to plot them on the same plot and "draw" a shaded area beween the two lines using function polygon I have tried all but I don ?t understand the polygon area, can you help me with examples? plot(efinal,type="l",ylim=range(min(efinal2),

Hey all, In order to test if a marker is a risk factor, I built two models (using cox proportional hazard model). One model included this marker, and the other is not. Then, I use R package risksetROC to test how much predictive value did the marker add to this model. I get two C statistics by analyzing the linear predictors of the two models into this package. The qustion is How to test if two

Dear R-helpers, does anyone know of some package/function that can build a network from the functions that are implemented in a package, i.e. visualize the cross-references from one function to another in the same or some dependent package? An example would be a function like 'nls' on top of the hierarchy and then a network of nodes from the functions that are called within 'nls'

Dear List members, I really, like the feature that one can call R functions with mathematical expressions, e.g. curve(x^2, 0, 1) I wonder, how I can construct in a simple way a function like mycurve = function (expr) {...} such that that a call mycurve(x^2) has the same effect as the call curve(x^2, -100,100) Below is some code that works, but it seems much to complicated: it first

Dear expeRts, I it possible to have serif labels in the following plot? x <- 1:10 y <- x plot(x, y, type="b", xlab=expression(x[1]), ylab=expression(x[2])) I know that one can use pdf(, family="serif"), but then also the axis tick marks are printed in serif font. Apart from the fact that it may not look nice, I'm just interested if one can have serif axis labels

Dear all, I have a vector, which looks about like this: str <- c("14.XYZ", "15.ABCDE", "16.dkieowo", "120.EIDKAI") I need to extract the numerical characters out of the string, so I receive in the end a normal vector containing: vec <- c(14, 15, 16, 120) I need a generic solution for this. My actual vector contains about 403

Dear R Users, I have a question, how does one print an r function like t.test in R (to get the whole function and not just a summary of the environment)? For example if I type the following: > t.test function (x, ...) UseMethod("t.test") <environment: namespace:stats> > print(t.test) function (x, ...) UseMethod("t.test") <environment: namespace:stats> I

Hi I have data in the following format Cort Day Animal 23 0 1 27 3 1 24 0 2 27 1 2 34 2 2 30 3 2 24 4 2 20 0 3 24 1 3 28 2 3 34 4 3 etc. It is measured across time(day) however no every individual is measured the same number of times. All I want to do is plot the Raw data and then run a line connecting the

Hello, I used the function cor to calculate the pearson correlation coefficient between variables. However, the resulting values do not correspond to the outcome of my excel-calculations, for which I used the formula Cor(x,y)=Cov(x,y)/(SD(x)*SD(y)) So my question is: How does the function "cor" compute the pearson correlation coefficient? Thank you in advance, Ake Nauta

Hi, I'd like to execute simple commands and functions in R through a website, is there any service like this somewhere? I only found http://www.osvisions.com/r-online/ but it does not work (last update 2003) and the links to releated websites only give errors (if I calculate 7+3). Thanks for help & hints, Thomas

Help-Rs,   I'm doing some string manipulation in a file where I converted a string date in mm/dd/yyyy format and returned the date yyyy.   I've used regexpr (hat tip to Gabor G for a very nice earlier post on this function) in steps (I've un-nested the code and provided it and an example of what I did below.  My question is: is there a more efficient way to do this.  Specifically is

Hello R-help list,   I am looking for way to toggle the case of the characters like a flip-flop; that is from ''Hello'' to "hELLO" or vice versa.   I know that there are a number of functions like casefold, tolower, toupper, etc. but these functions change the case in an uniform way.   Thanks in advance,   Antonio Rivero Ostoic         Antonio Rivero Ostoic PhD Student,

? stato filtrato un testo allegato il cui set di caratteri non era indicato... Nome: non disponibile URL: <https://stat.ethz.ch/pipermail/r-help/attachments/20130423/641d9950/attachment.pl>