similar to: Vectorization of duration of the game in the gambler ruin's problem

I ran dovecot -a and the blizzard of data seemed ok to my limited knowledge. Is there another log I should look into to trace this error down? Dovecot and system info: thufir at dur:~$ thufir at dur:~$ dovecot --version 2.0.19 thufir at dur:~$ thufir at dur:~$ cat /etc/lsb-release DISTRIB_ID=Ubuntu DISTRIB_RELEASE=12.04 DISTRIB_CODENAME=precise DISTRIB_DESCRIPTION="Ubuntu 12.04.1

Hello, I am a R beginner and I have a question about a litte function I found. Here is the code: # Gambler's Ruin Problem. # seed capital: k # rounds: n # probability of success: p # number of trials: N # graphical output (yes/no): draw # Wait for new graphic (yes/no): ask ruin<- function( N = 1, n = 10, k = 1, p = 1 /

Dear R-mates, # Here's what I am trying to do. I have a dataset like this: id = c(rep(1,8), rep(2,8)) dur1 <- c( 17,18,19,18,24,19,24,24 ) est1 <- c( rep(1,5), rep(2,3) ) dur2 <- c(1,1,3,4,8,12,13,14) est2 <- rep(1,8) mydata = data.frame(id, estat=c(est1, est2), durat=c(dur1, dur2)) # I want to one have this: id = c(rep(1,8), rep(2,8))

I have a question about some strange results I get when using lmer to build a logistic mixed effects model. I have a data set of about 30k points, and I'm trying to do backwards selection to reduce the number of fixed effects in my model. I've got 3 crossed random effects and about 20 or so fixed effects. At a certain point, I get a model (m17) where the fixed effects are like this

To use dovecot-postfix stack with thunderbird, do I put the configuration into /usr/share/dovecot/protocols.d/impad.protocol? That would seem to be how the stack is configured. "Thunderbird To use with Thunderbird, edit the file /etc/dovecot/dovecot.conf: protocol imap { ... login_greeting_capability = yes imap_client_workarounds = tb-extra-mailbox-sep }"

Hey fellas: I would like to integrate the following function: integrand <- function (x,t) { exp(-2*t)*(2*t)^x/(10*factorial(x)) } with respect to the t variable, from 0 to 10. The variable x here works as a parameter: I would like to integrate the said function for each value of x in 0,1,..,44. I have tried Vectorize to no avail. Thanks in advance, jose romero

Howdo folks, So I have my data (attached). There are two columns I'm interested in; "algname" and "dur". I'd like to know how dur changes with algname. algname is nominal and there are 7 possibilities. There are two more nominal independents, "task" and "id", so my model is: dur ~ algname+task+id From the research I've done, a TukeyHSD

In the area plots below, I see 4 triangle ticks at both sides of the bar; I believe these are non-stacked values for p, but they are definitively confusing. In addition, I would like to get the order of the colors in the plot the same as in the legend, and not arranged alphabetically (the factor is ordered, don't touch my order). Hadley once mentioned an undocumented aestetics

Hi, I have a data frame and want to merge adjacent rows if some condition is met. There's an obvious solution using a loop but it is prohibitively slow because my data frame is large. Is there an efficient canonical solution for that? > head(d) rt dur tid mood roi x 55 5523 200 4 subj 9 5 56 5523 52 4 subj 7 31 57 5523 209 4 subj 4 9 58 5523 188 4 subj 4 7

Greetings - I am working on a piece of code to simulate vehicle times in and out in each of a number of parking spaces. At this stage, my code basically does what it is supposed to do but for the sequential number of each new parking event for a given space (i.e., the index of the loop variable). Instead of passing the index of the loop variable (iter) to the data frame, it passes the value

I'd like do a simple xyplot with customized order of panels and try to understand how to use index.cond for that. Several attempts didn't deliver the correct results. Now, I noticed the following: > p <- xyplot(dur~roi|trial, data) > p$index.cond [[1]] [1] 1 2 3 4 5 6 7 8 9 10 These numbers are "valid indexing vector for the integer vector

Dear R users A quite simple question:?how can I get the mean duration (persistence) of daily data, when the data set looks as follows:? [1] 7 7 7 9 9 5 7 5 5 5 9 5 5 6 6 6 1 1 1 2 2 4 4 4 4 7 7 3 3 2 4 4 7 7 7 7 7 [38] 7 7 5 5 9 9 5 5 5 1 7 9 9 9 9 9 5 5 5 5 5 3 4 4 4 4 4 4 4 4 2 2 2 2 2 2 8 [75] 8 6 6 6 8 8 8 8 8 6 6 2 8 8 8 8 8 8 8 8 8 2 2 2 2 2 6 6 6 6 6 6 6 6 6 6 3 [112] 3 2 2 2 1 5 1 1 4

Hi list, I was trying to use "predict.coxph" to calculate martingale residuals on a test data, however, as pointed out before http://tolstoy.newcastle.edu.au/R/e4/help/08/06/13508.html predict(mycox1, newdata, type="expected") is not implemented yet. Dieter suggested to use 'cph' and 'predict.Design', but from my reading so far, I'm not sure they can

I''ve seen a few posts about this, but no answers. I would like to be able to call a function when a draggable revert occurs. What I''m trying to do is replace a photo with an icon on drag (which I''ve accomplished), but I need to swap it back if the revert fires. I really, really wish there were an onRevert() option, but there isn''t, so I guess I''ll

All, I'm in the process of upgrading an LLVM client from using 3.8 to using 4.0 and am running into the following issue: // compile with: // clang++ -std=c++11 -Wno-c++14-extensions -S -emit-llvm // ~/chrono.cpp -o chrono.ll #include <chrono> #include <ratio> #include <thread> using namespace std; using namespace std::chrono; using tick = ratio<1, 300>; using

Hello, Can someone give me hint to change a data.frame. I want to split a column in more columns depending on the value of a other column. Thanks for the reaction, Andre Example: > dat x1 x2 1 1 a 2 1 b 3 1 c 4 2 d 5 2 e 6 2 f 7 3 g 8 3 h 9 3 i in > dur d1 d2 d3 1 a d g 2 b e h 3 c f i [[alternative HTML version deleted]]

Hallo, I have an other problem, I have this vector signData with an alternation of 1 and -1 that corrispond to the duration of two different percepts. I extracted the durations like this: signData<- scan("dataTR10.txt") dur<-rle(signData)$length Now I would like to extract only the positive duration, e.g. signData <- c(1,1,1,1,-1,-1,-1,1,1,-1,-1) posduration <- c(4,2) I

Dear list, After reading different mails, blogs, and tried a few different codes without any success, I am asking your help! I have the following data frame where each row represent a survey unit with the following variables: > names(RV09) [1] "record.t" "trip" "set" "month" "stratum" "NAFO" [7]

Hi there, I''m a new to Rails and to Ruby too. I hope you can help with what hopefully is a simple installation problem. I have successfully installed version: C:\>ruby -v ruby 1.8.2 (2004-12-25) [i386-mswin32] I have successfully installed gem: C:\>gem --version 0.8.11 When I try to install Rails i get the following error: C:\>gem install rails --include-dependencies

Dear R experts, I would really appreciate if you had an idea on how to use more efficiently the aggregate method: More specifically, I would like to calculate the mean of certain values on a data frame,? grouped by various attributes, and then create a new column in the data frame that will have the corresponding mean for every row. I attach part of my code: matchMean <-