similar to: use of quotation marks

Dear R People: I'm sure that this is a very simple problem, but I have been wresting with it for some time. I have the following file that has the following one line: CRS("+init=epsg:28992") Fair enough. I scan it into R and get the following: > u [1] "CRS(\"+init=epsg:28992\")" > gsub(pattern='\"',replacement='"',x=u) [1]

I am using read.table to import a text file within R.   There are several "errors" in my text file.  An "extra" quotation mark has inadvertently been included within a few text fields.   e.g. for a pipe (|) delimited text file, I have something similar to this:   1|7|30| "dog" 2|6|25| ""cat" 3|4|20|"" 4|5| 56| "mouse" 5|3|56|

Hi, I would like to substitute a semicolon with two double quotation marks and a comma inbetween. It suppose to look like that: I have: FBpp0070086;FBpp0099643;FBpp0112915 I would like to have: "FBpp0070086","FBpp0099643","FBpp0112915" I tried with various numbers of backslashes, but noe have worked. for example: gsub(";", "\\\",\"",

Dear mailing list members, My question is maybe very basic, but I could not find the solution. I would like to do the following things 1) colnames(V1)[2] <- par$V2[1] colnames(V2)[2] <- par$V2[2] colnames(V3)[2] <- par$V2[3] ... colnames(V37)[2] <- par$V2[37] 2) V1 <- V1[,-1] V2 <- V2[,-1] V3 <- V3[,-1] ... V37 <- V37[,-1] 3) ms <- merge(V1,V2) ms <- merge(ms,V3)

Hi, I am trying to process genomics data and the presence of both characters and integers in an array is giving issues. The following is an example: > a<-array(c(2,2,"X",1:3,2:4),dim=c(3,3)) > b<-cbind(a[,1],a[,2]) With the output being: [,1] [,2] [1,] "2" "1" [2,] "2" "2" [3,] "X" "3" Is there any

Hi again R users. I was reviewing the manual of R about how to install packages using the GUI and it's corresponding menu packages. My question is how to download a specific set of packages in order to install them in a computer that doesn't have internet access. Is there a web page where I can search those packages? Basically I'm trying to copy in a flash drive the packages MASS, BOOT

I wish to place quotation marks around each element of the following list; X1 1 Label 1 2 Label 2 3 Label 3 4 Label 4 and combine the values in the following format for use in another function; c("Label 1","Label 2","Label 3","Label 4") Many thanks, Jerry

Dear all, One of my friends asked me if it is possible to extract actual R function arguments literally (precisely, as strings). The reason is simple. He feels sometimes awkward to attach quotation marks :-). What he actually wants is to pass R command arguments to XLisp subroutines (He has been an enthusiastic XLisp user for a long time and still tends to use R as a wrapper to XLisp). Is it

Dear R friends: Can someone help me with the following problem? Many thanks in advance. # Problem Description: # I want to write functions which take a (character) vector of dataframe names as input argument. # For example, I want to extract the number of observations from a number of dataframes. # I tried the following: nobs.fun <- function (dframe.vec) { nobs.vec <-

Hi there I want to be able to take all the files in a given directory, read them in one at a time, calculate a distance matrix for them (the files are data matrices) and then print them out to separate files. This is the code I thought I would be able to use (all files are in directory data_files) for(i in 1:length(files)) + { + x<-read.table("data_files/files[[i]]") +

Dear R users, Let?s say I have 10 models, each named m1,m2,m3..., and I would like to summarize them automatically and simultaneously - e.g., to extract parameter estimates later on from all models; how can I do that? I have tried: x=1:10 #this creates some example data y=rnorm(10) m1=lm(x~y) m2=lm(x~1) sum.lms=function(x)summary(paste("m",x,sep="")) sum.lms(1:2) but

Dear Sir, We would lik to subscribe the support for OpenSSH for a tender project. Please kindly advise the annual subscription plan (with details of SLA) & annual fee. For the price, is it determined by number of server? or number of CPU? or number of core? Shall we get quotation/support from you? or please advise the reseller contact. Since the tender will be closed next week, may we

i need a quotation for a E&M Digium card for my asterisk PBX where i can find it??? thank you in advance Rodney Acosta Coya.

Hello, just getting around to tuning and the benchmarker script. I understand, from the rails book, that the command used is: script/benchmarker 10 "Product.search(''version_control'')" Maybe I''m misunderstanding it but what if there are some nested " or '' required inside the command, such as: script/benchmarket 10 "Question.find(:all,

Hi I have a matrix of type "character" (strangly) and am trying to apply the function "aggregate" to it, but unfortunately without success. It seems to me that aggregate would work, if I only could get rid of the quotation marks around each item. So for a very simple example which looks as my actual data look (of course here I put the quotation marks on purpose, but I have

In Windows; to have Firefox pass psyn links to the Curse client I use this command: Code: "C:\Program Files\Curse\CurseClient.exe" -url "%1" but when I try to get Linux's Firefox to pass the psyn link to the Curse client running in wine, wine of course assumes that -url and the quotation marks are for it and not the actual Windows command it's meant to run. How do I

dovecot version v2.2.29 v2.2.36 v2.3.5 LIST "" * The returned mailbox does not display quotes dovecot version v2.1.17 LIST "" * The returned mailbox shows quotation marks Why is the quotation mark removed in the new version? Is there any configuration option in the new version to add quotes? Because I see a lot of big public mailboxes with quotation marks.

Hi R-helpers, I have a character string, for example: "lm(y ~ X2 + X3 + X4)" from which I would like to strip off the leading and trailing quotation marks resulting in this: lm(y ~ X2 + X3 + X4) I have tried using gsub() but I can't figure out how to specify the quotation mark using a regular expression. Alternatively, I would like a function that lets me delete the leading

Hi, I'm trying to generate valid R code using R. Parts of the task is to read a sequence of characters from file and escape them such that they can be put in quotation marks to form a valid R code string. Example: Let the input file be (four rows containing ASCII 0-255 characters): abcdef<tab>ghijk\nlmno second row\t\a\\ fourth and so on... <EOF> Now, find escapeString() such

Hi, I'm trying to generate valid R code using R. Parts of the task is to read a sequence of characters from file and escape them such that they can be put in quotation marks to form a valid R code string. Example: Let the input file be (four rows containing ASCII 0-255 characters): abcdef<tab>ghijk\nlmno second row\t\a\\ fourth and so on... <EOF> Now, find escapeString() such