similar to: NA value

I'm trying to make a loopo with some file.... > > library(dplR) > files.rwl <- system("ls *.rwl", intern=TRUE) > files.rwl [1] "cimfasy.rwl" "rocquce.rwl" > for (i in files.rwl) assign(gsub("\\.rwl$", "_rwl", i), read.rwl(i, header=0)) There are 70 series There are 21 series > > cimfasy_rwl 1990 1.55 0.00

Hi, With this data.frame: > class(rwl) [1] "data.frame" >rwl 0028002F 0028013F 0028032F 1833 3.39 NA NA 1834 3.09 NA NA 1835 3.05 NA NA 1836 3.31 NA NA 1837 2.26 NA NA > colnames(rwl) [1] "0028002F" "0028013F" "0028032F" Ok.... > colnames(rwl[,1]) NULL why??

I'm trying to make a loop with many files... > library(dplR) > > files <- system("ls *.rwl", intern=TRUE) > > files [1] "cimfasy.rwl" "rocquce.rwl" > for (i in files) {a <- read.rwl(i,header=0)} There are 70 series There are 21 series > class(a) [1] "data.frame" This loop import all the files rwl in a single data.frame ( a

I've a matrix like this: 1985 1.38 1.27 1.84 2.10 0.59 3.47 1986 1.05 1.13 1.21 1.54 0.21 2.14 1987 1.33 1.21 1.77 1.44 0.27 2.85 1988 1.86 1.06 2.33 2.14 0.55 1.40 1989 2.10 0.65 2.74 2.43 1.19 1.45 1990 1.55 0.00 1.59 1.94 0.99 2.14 1991 0.92

Hi everybody, If I've a data frame like this: dataframe a X0 X2 X4 X6 X8 X10 X12 X14 X16 1957 0 0 0 0 0 0 0 0 0 1958 0 0 0 0 0 0 0 0 0 1959 831 0 0 0 0 0 0 0 0 1960 544 282 0 0 0 0 0 0 0 1961 446 365 0 0 0 0 0 0 0 1962 442 473 0 0 0 0 0 0 0 1963 595 468 0 0 0 0 0 0 0 1964

Hi, I've a vector like this: > inc [1] NA NA NA NA NA NA NA [8] NA NA NA NA NA NA NA [15] NA NA NA NA NA NA NA [22] NA NA NA NA NA NA NA [29] NA NA NA NA

Hi, > a <- 4 > a*0.2 [1] 0.8 ok!! Is there a method to obtain this: > a*0.2 [1] 0.80 I need to round the number also with the zero. Thanks in advance, Alfredo

Hi, how can I replace NA value with 0: 1991 217 119 103 109 137 202 283 240 146 NA 1992 270 174 149 144 166 239 278 237 275 NA 1993 146 111 104 89 98 131 153 148 175 NA 1994 177 123 146 124 121 200 266 191 240 106 1995 145 98 95 89 95 130 183 161 164 129 1996 145 98 89 90 93 138 158 131 161 161 1991 217 119 103 109 137 202 283 240 146 0 1992 270 174 149 144 166 239 278 237

Hi, I've a vector like this: ------------------------------------------------------ > inc[,5] [1] NA NA NA NA NA NA NA [8] NA NA NA NA NA NA NA [15] NA NA NA NA NA NA NA [22] NA NA NA NA NA NA

Hi, If I have this values: 21 23 14 58 26 .... How can I sum the values by a progression like this: (21) (21 + 23) (21 + 23 + 14) (21 + 23 + 14 + 58) (21 + 23 + 14 + 58 + 26) (21 + 23 + 14 + 58 + 26....) I've try with the function "loop".... Best Wishes, Alfredo [[alternative HTML version deleted]]

Hi, I've this data.frame: > dia X1006109F X1006110F X1006111F X1006112F X1006113F X1006114F X1006115F 1 NA NA NA NA NA 45 NA X1006116F X1006117F X1006118F X1006119F X1006120F X1006122F X1006123F 1 45 NA NA NA 40 NA NA X1006124F X1006125F X1006126F X1006128F X1006203F X1006209F X1006210F

Hi, I've two dataframe: > snag_totale AREA snag_ha 1 2 1.628128 2 3 10.274249 3 4 2.778503 4 5 73.764307 5 7 12.015985 > log_totale AREA log_ha 1 1 22.29846 2 2 17.16889 3 3 48.80377 4 4 144.18996 5 5 70.30962 6 6 61.81850 7 7 13.24876 > How can I obtain a new data.frame, by the sum of value "snag_ha" +

Hi, I've a data frame like this: > as.data.frame(cbind(rnorm(1:12),rnorm(1:12))) V1 V2 1 -1.30849402 -0.52094136 2 0.96157302 0.76217871 3 -0.44223351 -1.72630871 4 -0.10432438 -1.04732942 5 -1.38748914 0.95877311 6 -0.63965975 0.65494811 7 -0.24058318 0.19496830 8 -0.11172988 1.01680655 9 0.08065333 0.22168589 10 0.25196536 0.84619914 11

Hi, I've two data.frame: ind_comp and dati_area > ind_comp INDEX indice 1 1 0.3081856 2 2 0.1368007 3 3 0.1290952 4 4 0.2905484 5 5 0.2686706 6 6 0.1122784 7 7 0.4493264 8 8 0.1932665 9 9 0.1982783 10 11 0.3724666 > dati_area X_COORD Y_COORD DBH AREA ID ind_comp 1 0.0000000 0.0000000 70.0 1 1 0 2

Hi, I've this dataframe: V1 V5 V6 1 MOD13Q1_2000049 0.1723 A1 2 MOD13Q1_2000049 0.1824 B1 3 MOD13Q1_2000049 0.1824 C1 4 MOD13Q1_2000049 0.1774 A2 5 MOD13Q1_2000049 0.1953 B2 6 MOD13Q1_2000049 0.1824 C2 7 MOD13Q1_2000065 0.1921 A1 8 MOD13Q1_2000065 0.1938 B1 9 MOD13Q1_2000065 0.2009 C1 10 MOD13Q1_2000065 0.2035 A2 11 MOD13Q1_2000065 0.2157 B2 12

Hi, I've this dataframes: > data1 1 2 3 4 5 6 5 0.4963017 0 0 0.2481509 1.9852069 0.4963017 10 0.0000000 0 0 0.0000000 0.6317266 0.0000000 15 0.0000000 0 0 0.0000000 0.0000000 0.0000000 20 0.0000000 0 0 3.3955301 0.0000000 0.0000000 25 0.0000000 0 0 0.0000000 0.0000000 0.0000000 30 0.0000000 0 0 0.0000000 0.0000000

Hi, I've three values. What is the best method to choice the lowest values with an if function? example: a = 3 b = 1 c = 5 if (lowest(a,b,c) is a) {........} if (lowest(a,b,c) is b) {........} if (lowest(a,b,c) is c) {........} Thanks, Alfredo

Hi, I need to make a cluster classification by the unique values of the data frame. I explain the problem. I need to classify this table, and assign to the same cluster each row that has the same combination of value: > data1 layer_1 layer_2 layer_3 [1,] 0.2460000000 2 -0.1 [2,] 0.5460000000 3 -0.1 [3,] 0.2460000000 2 -0.1 [4,]

Hi, I've a list of list. I want to extract an element by the rownames. I can extract it by: data[[1]][[1]][[4]][1] But I want to exctract it by a command like this: data[[1]][["B0"]][["smac"]][["cont"]][1] It's possible? Thanks, Alfredo > str(data) List of 1 $ :List of 4 ..$ :List of 4 .. ..$ : num [1, 1:3] 0.4 0.458 0.5 .. ..$ : num

Dear all, I have a data frame in which the columns need to be ordered. The first column X is at the right position, but the remaining columns X1-Xn should be ordered like this: X1, X2, X3 etc instead of like below. > colnames(pos1) [1] "X" "X1" "X10" "X11" "X12" "X13" "X14" "X15" "X16"