Displaying 20 results from an estimated 3000 matches similar to: "fix variance parameter values for lmer estimation"
2008 Dec 13
2
weird pasting of ".value" when list is returned
could someone explain why the name of FPVAL gets " .value" concatenated
onto it when the code below is run and temp is returned.
I've been trying to figure this out for too long. It doesn't matter when
I put the FPVAL in the return statement. It happens regardless of
whether it's first or last. Thanks.
f.lmmultenhanced <-
function(response, pred1, pred2)
{
2004 Jun 16
2
gam
hi,
i'm working with mgcv packages and specially gam. My exemple is:
>test<-gam(B~s(pred1)+s(pred2))
>plot(test,pages=1)
when ploting test, you can view pred1 vs s(pred1, edf[1] ) & pred2 vs
s(pred2, edf[2] )
I would like to know if there is a way to access to those terms
(s(pred1) & s(pred2)). Does someone know how?
the purpose is to access to equation of smooths terms
2009 Feb 23
1
Follow-up to Reply: Overdispersion with binomial distribution
THANKS so very much for your help (previous and future!). I have a two
follow-up questions.
1) You say that dispersion = 1 by definition ....dispersion changes from 1
to 13.5 when I go from binomial to quasibinomial....does this suggest that
I should use the binomial? i.e., is the dispersion factor more important
that the
2) Is there a cutoff for too much overdispersion - mine seems to be
2008 Jul 01
2
Problem installing Topix
Guten Tag,
I need to install a software called Topix (www.topix.de) wih wine.
It is our main order management software with enterprise recource planing, accounting, stock keeping and customer relation management.
I use Kubuntu newest version and Wine 1,10.
Here you can see the message list from wine:
http://ubuntuusers.de/paste/380352/
Do you have any idea to avoid the software crash?
Best
2008 Sep 11
1
how to calcaulate matrices for two subsets
I am an R beginner and trying to run a market model using event study in
R framework.
First, I run a market model, that is lm(stock security~SP500 index,
subset=Obs[197, 396]) ->result1
Then I get predict results for a new dataset using predict (result1,
newdata=Obs[397,399]) ->pred1
Pred1 should have three numbers.
Now I need to calculate abnormal return by the formula stock
2009 May 12
1
ROCR: auc and logarithm plot
Hi,
I am quite new to R and I have two questions regarding ROCR.
1. I have tried to understand how to extract area-under-curve value by looking at the ROCR document and googling. Still I am not sure if I am doing the right thing. Here is my code, is "auc1" the auc value?
"
pred1 <- prediction(resp1,label1)
perf1 <- performance(pred1,"tpr","fpr")
plot(
2012 Mar 19
1
glm: getting the confidence interval for an Odds Ratio, when using predict()
Say I fit a logistic model and want to calculate an odds ratio between 2
sets of predictors. It is easy to obtain the difference in the predicted
logodds using the predict() function, and thus get a point-estimate OR. But
I can't see how to obtain the confidence interval for such an OR.
For example:
model <- glm(chd ~age.cat + male + lowed, family=binomial(logit))
pred1 <-
2011 Sep 06
1
Question about Natural Splines (ns function)
Hi - How can I 'manually' reproduce the results in 'pred1' below? My attempt
is pred_manual, but is not correct. Any help is much appreciated.
library(splines)
set.seed(12345)
y <- rgamma(1000, shape =0.5)
age <- rnorm(1000, 45, 10)
glm1 <- glm(y ~ ns(age, 4), family=Gamma(link=log))
dd <- data.frame(age = 16:80)
mm <- model.matrix( ~ ns(dd$age, 4))
pred1 <-
2011 Apr 06
3
ROCR - best sensitivity/specificity tradeoff?
Hi,
My questions concerns the ROCR package and I hope somebody here on the list can help - or point me to some better place.
When evaluating a model's performane, like this:
pred1 <- predict(model, ..., type="response")
pred2 <- prediction(pred1, binary_classifier_vector)
perf <- performance(pred, "sens", "spec")
(Where "prediction" and
2007 Jun 04
3
Extracting lists in the dataframe $ format
I'm new to R and am trying to extract the factors of a dataframe using numeric indices (e.g. df[1]) that are input to a function definition instead of the other types of references (e.g. df$out). df[1] is a list(?) whose class is "dataframe". These indexed lists can be printed successfuly but are not agreeable to the plot() and lm() functions shown below as are their df$out
2005 Mar 03
3
creating a formula on-the-fly inside a function
I have a function that, among other things, runs a linear model and
returns r2. But, the number of predictor variables passed to the
function changes from 1 to 3. How can I change the formula inside the
function depending on the number of variables passed in?
An example:
get.model.fit <- function(response.dat, pred1.dat, pred2.dat = NULL,
pred3.dat = NULL)
{
res <- lm(response.dat ~
2006 May 27
1
Recommended package nlme: bug in predict.lme when an independent variable is a polynomial (PR#8905)
Full_Name: Renaud Lancelot
Version: Version 2.3.0 (2006-04-24)
OS: MS Windows XP Pro SP2
Submission from: (NULL) (82.239.219.108)
I think there is a bug in predict.lme, when a polynomial generated by poly() is
used as an explanatory variable, and a new data.frame is used for predictions. I
guess this is related to * not * using, for predictions, the coefs used in
constructing the orthogonal
2007 Sep 04
1
data.frame loses name when constructed with one column
Not sure why the data.frame function does not capture the name of the column field when its being built with only one column.
Can anyone help?
> data
out pred1 predd2
1 1 2.0 3.0
2 2 3.5 5.5
3 3 5.5 11.0
> data1=data.frame(data[,1])
> data1
data...1.
1 1
2 2
3 3
> data1=data.frame(data[,1:2])
> data1
out pred1
1 1 2.0
2 2
2013 Sep 25
1
Best and worst values for each date
Hi,
May be you can try this:
obj_name<- load("arun.RData")
Pred1<- get(obj_name[1])
Actual1<- get(obj_name[2])
library(reshape2)
dat<-cbind(melt(Pred1,id.vars="S1"),value2=melt(Actual1,id.vars="S1")[,3])? # to reshape to long form
colnames(dat)[3:4]<- c("Predict","Actual")
dat$variable<- as.character(dat$variable) #not that
2017 Oct 06
2
Using response variable in interaction as explanatory variable in glm crashes R
The following code crashes R (I know I shouldn't try to estimate such a
model; this was a bug in some code of mine). I also tried with R-devel;
same result.
tab <- structure(list(dob_day = c(FALSE, FALSE, FALSE, FALSE, TRUE,
TRUE, TRUE, TRUE), dob_mon = c(FALSE, FALSE, TRUE, TRUE, FALSE,
FALSE, TRUE, TRUE), dob_year = c(FALSE, TRUE, FALSE, TRUE, FALSE,
TRUE, FALSE, TRUE), n =
2011 Aug 02
0
[LLVMdev] Multiple successors, single dynamic successor
Nella citazione martedì 2 agosto 2011 22:01:13, Carlo Alberto Ferraris
ha scritto:
> My question is:
> what is the best way to
> express such relationships in LLVM IR ("best" in the sense of allowing
> other optimizations to run effectively)? Bear in mind that in this
> example N=2, but it may be way bigger than that.
Just to clarify: I already figured out two ways to
2005 Aug 07
1
prediction from glm...
Hello r-help,
I'm trying to fit birds counts over years using glm. In fact I'm trying to reproduce an analysis already perform with genstat (attach document). I have done (with Estate
and year as factors):
Model1 <- glm(Females~Estate+Year+offset = log(area)), family =
quasipoisson(link = log), na.action = "na.exclude")
After I have calculated the prediction using:
Pred1
2018 Oct 22
1
OPUS at Texas Instruments C6418
Hi Jean-Marc,
thank you for that suggestion!
It seems that the file "fixed_c6x.h" is not part of the Opus sources, so the compiler cannot find it after enabling the TI_C6X_ASM config option.
Maybe it was only part of an early version of the Opus sources?
I looked for the file in versions V1.1, V1.1.1, V1.2alpha and V1.3 but did not found it.
Do you have an idea, where I can get the
2006 Oct 09
1
testing for error
Dear R Helpers,
I want to test if a procedure within a loop has produced an error or not.
If the procedure has produced an error, then I want to ignore its result.
If it has not produced an error, then I want to use the result. The problem
In order to run the loop without crashing if the procedure produces an
error,
I place the routine inside a try() statement.
So, suppose I am trying to find
2024 Jul 13
1
Obtaining predicted probabilities for Logistic regression
?s 12:13 de 13/07/2024, Christofer Bogaso escreveu:
> Hi,
>
> I ran below code
>
> Dat = read.csv('https://raw.githubusercontent.com/sam16tyagi/Machine-Learning-techniques-in-python/master/logistic%20regression%20dataset-Social_Network_Ads.csv')
> head(Dat)
> Model = glm(Purchased ~ Gender, data = Dat, family = binomial())
> head(predict(Model,