similar to: ggplot2 - facetting

Dear All, I am trying to build a stacked bar plot, where I define the colours to use. I have asked this before, and I was using a solution in http://thread.gmane.org/gmane.comp.lang.r.general/100649/focus=100673 (thanks, Thierry). However, it looks this works only when the data are in the sequence of the levels in the factor defining the fill colours. When the sequence is different, the

Dear R's (most likely Hadley), I want to build a stacked bar plot where I would like to define which colours will be used for each of the groups. However, I do not seem to find a way to do this, even if I've been looking over many places. I have tried several variations, and my final try was this code, but I still do not manage to get the colours as I pre-define. Any hints about how

is it possible to use Effects.Scale to make a set of form input elements appear in a ''slide out'' effect? I''m trying to build a control with a button which, when clicked, will cause a row of form inputs to appear. I can do this with Effects.Appear, but what I really wanted was for the inputs to appear to ''slide out'' from the button. What I

This is really a question of how to program this *BETTER*. It works as I have done it, but is quite ugly. I want to do a 3d scatterplot of the upper triangle of a matrix, where the z-values are the values in the matrix, and the row and column indices are the y- and x-values. The complete (11 by 11) matrix is mmtop94.2. Here is my awkward code: mmtop94.2[lower.tri(mmtop94.2)] <- NA # Here i

Hello Again R Folk: I have found items about this in the archives, but I?m still not getting it right. I want to use ggplot2 with facet_grid inside a function with user specified variables, for instance: p <- ggplot(data, aes_string(x = fac1, y = res)) + facet_grid(. ~ fac2) Where data, fac1, fac2 and res are arguments to the function. I have tried p <- ggplot(data,

Hello there, I'm trying to do lots of plots in one for-loop. But somehow ggplot does not evaluate arguments as expected. Here is an example: library(lattice) library(ggplot2) pl <- list() pl2 <- list() cDat <- as.data.frame(cbind(x1=0:100,x2=0:10,x3=1:20)) for(obs in c("x1", "x2")) { pl[[obs]] <- xyplot(cDat[,obs] ~ cDat[,"x3"], main=obs)

I am plotting three Pearson Type IV distributions. It looks like I have to plot the distribution with the highest value of y and then use lines() to add the two distributions that are shorter / have lower max values of y. The following code figures out which distribution has the max y value, plots it first and then uses lines for the other two distributions with a series of three if statements.

I''m having an issue with flashing divs in IE (firefox is fine and the only other browser I''ve used) My scenario is as follows. I have 2 divs (initially hidden) and using the BlindDown and BlindUp functions (possibly others) the divs flash when starting to roll down in BlindDown (due to the Element.show call) and also at the end of the BlindUp call (due to the Element.hide call)

Whats going on here? df<-data.frame(x=1:10,y=1:10) ggplot()+geom_point(data=df,aes(x=x,y=y)) ## this is the normal usage right? ggplot()+geom_point(data=df,aes(x=df[,1],y=df[,2])) ## but I can also feed it column indices ggplot()+geom_point(aes(x=df[,'x'],y=df[,'y'])) ## or column names. ## but if i wrap it in a function... plot.func.one<-function(dff,x.var,y.var){

Problem: I am trying to get the histogram and box plot x axis to match. I?ve tried using the expand_limits function to make the axis match but that didn?t make the axis match. The histogram?s axis are still consistently larger than the ones for the box plot (though the function did help). Does anyone have a suggestion as to what I should do instead? Background: I am building a Shiny app that

Hi everyone, Hi ggplot users in particular, ggplot makes it very easy to plot things given their names when you use it interactively (and therefore can provide the names of the columns). qplot(x,foo,data=A) where A has columns (x,y,foo,bar) for example but I would like to use this from inside a function to which the name of the column is given. I cannot find an elegant way to make this

Hello, is there a way to basically achieve a BlindLeft and BlindRight effect and if yes, how would I do that? Thank you in advance for your help. _________________________________________________________________ Don’t just search. Find. Check out the new MSN Search! http://search.msn.click-url.com/go/onm00200636ave/direct/01/

I am trying to use the reshape package for the first time. I have two waves of a survey, so the id variables include a subject identification number and a variable denoting the wave of the survey. I used the following arguments: library(reshape) svy.melt <- melt(svy, id=c("id", "WAVE")) svy.wide <- cast(svy.melt, id ~ WAVE + ...) and got the following error:

Hi all, I setup a new CentOS 5.2 domU, and then proceeded to install cPanel, which is a simple task of downloading http://layer1.cpanel.net/latest - and running it in the command line, as such: cd /home wget http://layer1.cpanel.net/latest sh latest. But, I get the following error: sh-3.2# sh latest Creating directory installd Verifying archive integrity... All good. Uncompressing

I am trying to use the "cast" function from the reshape package, where the formula is not passed in directly, but as the result of the as.formula() function. Using reshape v. 0.7.2 I am able to properly melt() by data with: > molten <- melt(x, id=1:2) then I can properly cast with this: > cast(molten, days ~ variable) but if I try > cast(molten,

Hello Icecast group, I have a problem with compiling lame or other programms, I get always the message from stupid libtool libtool is installed, I use Solaris9 (sunOS 5.9) has any person a idea? thank you for help Daniel # make cd . \ && CONFIG_FILES= CONFIG_HEADERS=config.h \ /bin/bash ./config.status config.status: creating config.h config.status: config.h is unchanged

Hi all, Is there any way for me to to string in the argument of qplot or ggplot? for example qplot(x='carat',y='price',data=diamonds,geom=c('point','smooth')) instead of qplot(x=carat,y=price,data=diamonds,geom=c('point','smooth')) Thanks!! Regards, TszKin Julian [[alternative HTML version deleted]]

Hi everybody I hope that somebody can help me with the following .... I have 2 quadbri cards 2 - 1t0 cards 1 pabx alcatel 4200 I would like to connect my asterisk to the alcatel , I installed bristuff 0.3.0-1p , loaded the zaphfc driver in NT mode configured zaptel and zapata , it works great. then I removed the 1 t0 card, added the quadbri loaded qozap : insmod qozap.ko ports=15 ( 4 ports

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Hi, I need to make a cluster classification by the unique values of the data frame. I explain the problem. I need to classify this table, and assign to the same cluster each row that has the same combination of value: > data1 layer_1 layer_2 layer_3 [1,] 0.2460000000 2 -0.1 [2,] 0.5460000000 3 -0.1 [3,] 0.2460000000 2 -0.1 [4,]