similar to: download webpage in R

Dear everybody! I am making a graph in R and employ pstoedit to expot the .pdf-output to .svg. When I open the .svg with firefox I get the .svg-code shown wit the following header: "Mit dieser XML-Datei sind anscheinend keine Style-Informationen verkn?pft. Nachfolgend wird die Baum-Ansicht des Dokuments angezeigt." Which information should how be included? Thank you in advance. Yours,

On Wed, Apr 29, 2015 at 8:12 PM, Paul Gilbert <pgilbert902 at gmail.com> wrote: > > As I recall, several packages mask the simulate generic in stats, if you > are looking for examples. > FWIW, here is a list of base* functions masked** by CRAN packages: https://github.com/gaborcsardi/rfunctions/blob/master/rfunctions.md Look at the long table in the end. simulate indeed comes up

Hi, First, when I try the example Prostate with bound 0.44 (as in the manual), I got a different result: > l1c.P <- l1ce(lpsa ~ ., Prostate, bound=0.44) > l1c.P .... Coefficients: (Intercept) lcavol lweight age lbph svi 1.0435803 0.4740831 0.1953156 0.0000000 0.0000000 0.3758199 lcp gleason pgg45 0.0000000 0.0000000

All, I'm trying to obtain a one-liner to generate a certain sequence of alternatign numbers. Consider: > unlist(rep(list(c(1,2), c(3,4)), each = 6)) [1] 1 2 1 2 1 2 1 2 1 2 1 2 3 4 3 4 3 4 3 4 3 4 3 4 I'd like the result to be as above but continue until 38. Of course, I could hardcode this going up to c(37,38), but is there a more elegant way? Thanks! David

Hey, all Now I am using EM algorithm to do some optimization. Within that E-step, I have to calculate some multivariate integration given some parameter values Theta and function form of a probability density function f. So I want to know if there are some package in R to do such numerical integration given such function form and parameter values? Thanks for your kind support on this. Have a

Hi all: A short question: For example, a=[3,4,6,2,3], obviously the 3rd entry of the array has the maxium value, what I want is index of the maxium value: 3. is there a neat expression to get this index? Thank you! Best, Feng [[alternative HTML version deleted]]

Dear all, Why does not the three-dot accept arguments from the parent environment? I am just confused with this error, can someone give me a hint? > rm(list=ls()) > testFun <- function(a, ...) + { + if(a){ + print(a) + }else + { + print(b) + } + } > > myTask <- function(a) + { + b <- 3 + testFun(a, b = b) + } >

patch revision history ---------------------- v1: Initial patch to handle this issue involving changing the hypercall interface v2:Totally handled inside hypervisor. v3:Change some logics of handling msi-x pending unmask operations. v4:Some changes related to coding style according to Andrew Cooper''s comments From 51c5b7f1f9c8f319da8adf021b39e18fbd3bf314 Mon Sep 17 00:00:00 2001 From:

Hi, Given a simple example, test <- matrix(c(0.1, 0.2, 0.1, 0.2, 0.1, 0.1, 0.3, 0.1, 0.1), 3, 3) How to generate row indexes for which their corresponding row values are less than or equal to 0.2 ? For this example, row 2 and 3 are the correct ones. Thanks [[alternative HTML version deleted]]

Dear R, Is there an efficient way to make a list that each element is from the corresponding column of a matrix. For example, if I have a matrix "a" > a <- matrix(1:10, 5, 2) > a [,1] [,2] [1,] 1 6 [2,] 2 7 [3,] 3 8 [4,] 4 9 [5,] 5 10 I would like to have a list "b" like this > b <- list(a[, 1], a[, 2]) > b [[1]] [1] 1 2 3

Dear R, I have a simple question concerning with a special case of spare matrix multiplications. Say A is a 200-by-10000 dense matrix. B is a 10000-by-10000 block- diagonal matrix, and each diagonal block B_i is 100-by-100. The usual way I did A%*%B will take about 30 seconds which is to time consuming because I have to do this thousands of times. I also tried to partition A into 100 small blocks

Hi, I have a simple beginner's question on removing a list of objects. Say I have objects C243.Daily1, C243.Daily2...C243.Daily5 in my workspace. I'd like to remove these without using rm five times. So I write. > a <- list(paste("C243.Daily",sep="",1:5)) > rm(a) Obviously this wouldn't work, as it would only remove the object a. But is there any way

I haven''t done rails in a year, but can someone tell me if there is a plugin or how much work is it to add an auto fill function like google''s front page? Would you just use an observer on the form or is there already a built in class that can do this? Thanks! Feng -- Posted via http://www.ruby-forum.com/. --~--~---------~--~----~------------~-------~--~----~ You received

Dear R, I have a covariates matrix with 10 observations, e.g. > X <- matrix(rnorm(50), 10, 5) > X [,1] [,2] [,3] [,4] [,5] [1,] 0.24857135 0.30880745 -1.44118657 1.10229027 1.0526010 [2,] 1.24316806 0.36275370 -0.40096866 -0.24387888 -1.5324384 [3,] -0.33504014 0.42996246 0.03902479 -0.84778875 -2.4754644 [4,] 0.06710229 1.01950917

Dear R, How can I disable using "enter" key to exit the browser() in debug mode? I would love to have this option because it is so annoying to jump out of the debugging mode unexpectedly when I don't want to. I guess some of us have encouraged at least one of these situations, 1, Accidentally pressed the enter key within the browser. 2, Copy and paste a piece of debugging code

Hey, I want to draw several plots sequently, but have to make them dispaly in one figure. So how to achieve this? Thanks. Fred

Hello I am a relatively new user of R and am struggling to use the 'network' package. I have a correlation matrix (produced using 'cor'), and want to draw a network where each item showing correlation above a threshold (say 0.5) is joined by a green line, and each item showing correlation below a threshold (say -0.5) is joined by a red line. Does anyone have any hints of how to

Hey, R-listers I was recommended to try using smooth.spline function for estimating 2-Dimensinal curve given a data set. So will you please tell me where to get this R function? Or which package provides this function? Thanks for your point. Fred

Dear R, I have two questions: 1, Why both R and Matlab give 0*Inf==NaN? To my knowledge, it should be zero mathematically. Am I right? 2, I need to calculate e.g. exp(a)/(exp(b)+c), where both a and b are very large numbers (>>1000, e.g a=1000, b=1007, and c=5). R gives me NaN when I use the following command: > exp(1000)/(exp(1007)+5) [1] NaN I am pretty sure this should be close to

Dear R, I have a silly question concerns with *apply. Say I have a list called A, A <- list(a = array(1:20, c(2, 2, 5)), b = array(1:30, c(2, 3, 5))) I wish to calculate the mean of A$a, and A$b w.r.t. their third dimension so I did lapply(A,apply,c(1,2),mean) Now if I still wish to do the above task but take away some burn-in, e.g. do not take A$a[,,1:2],and A$b[,,1:2] into account.