Displaying 20 results from an estimated 3000 matches similar to: "features boxplot"
2008 Feb 11
3
Difference between P.Value and adj.P.Value
Hallo,
> fit12<-lmFit(qrg[,1:2])
> t12<-toptable(fit12,adjust="fdr",number=25,genelist=qrg$genes[,1])
> t12
ID logFC t P.Value adj.P.Val B
522 PLAU_OP -6.836144 -8.420414 5.589416e-05 0.01212520 2.054965
1555 CD44_WIZ -6.569622 -8.227938 6.510169e-05 0.01212520 1.944046
Can anyone tell me what the difference is between P.Value
2007 May 21
4
How to compare linear models with intercept and those without intercept using minimizing adjs R^2 strategy
Dear R-list,
I apologize for my many emails but I think I know how to desctribe my
problem differently and more clearly.
My question is how to compare linear models with intercept and those without
intercept using maximizing adjusted R^2 strategy.
Now I do it like the following:
> library(leaps)
> n=20
> x=matrix(rnorm(n*3),ncol=3)
> b=c(1,2,0)
> intercept=1
>
2008 Jan 24
3
store variable as tab-del. txt-file
Hallo,
how can I store a variable as a tab-delimited txt-file? I crated a
variable with the following commands:
> fit12<-lmFit(qrg[,1:2])
> t12<-toptable(fit12,adjust="fdr",number=25,genelist=qrg$genes[,1])
> t12
ID logFC t P.Value adj.P.Val B
522 PLAU_OP -6.836144 -8.420414 5.589416e-05 0.01212520 2.054965
1555 CD44_WIZ -6.569622
2006 Nov 17
2
Getting R and .Rdata together again
Somehow, I've managed to have my .Rdata files become `disassociated'
from the R program. I am running Windows XP Pro. I have re-installed R
2.4 in an attempt to have it re-associate itself with .Rdata files, but
to no avail. .Rdata files are now associated with a file compression
program or alternatively with Rgui.exe. .Rdata files are represented by
the blue R, but double-clicking on
2006 Oct 20
2
Forest plot
Has anyone developed a function to generate a forest plot, the one used
a lot in meta-analysis?
Joseph F. Lucke, PhD
Biostatistician
Center for Clinical Research and Evidence-based Medicine
Department of Pediatrics
School of Medicine
University of Texas Health Science Center at Houston
Voice: 713-500-5651
Email: Joseph.F.Lucke@uth.tmc.edu
Postal Mail: PO Box 20708, Houston, TX 77225-0708
2009 May 11
3
Looking for a quick way to combine rows in a matrix
I'm working with genotype data in a frequency table:
> a=matrix(1:16, nrow=4)
> rownames(a)=c("AA","AT","TA","TT")
> a
[,1] [,2] [,3] [,4]
AA 1 5 9 13
AT 2 6 10 14
TA 3 7 11 15
TT 4 8 12 16
'AT' and 'TA' are essentially the same, and I'd like to combine (add) the rows to reflect
2010 Apr 17
2
Interacting with dendrogram plots, locator() or click()
I would like to explore dendrogam plots interactively. For example, click on a node and return information about all of the children of that node.
Is there a high level wrapper for locator() or click() that will return the nearest dendrogram node on a plot?
If not, is there a way to obtain the [x,y] coordinates of all the nodes on a plot?
Thanks,
David
David J. States, M.D., Ph.D.
Professor
2011 Feb 14
1
conditional value assignment
Dear R-Help,
I am trying to compute a new variable, let's call it "target cannon orientation (tco)" based conditionally on old variables, "TargetColor," "CannonOriB," and "CannonOriR." For every case in the data set, if TargetColor is "B" then I want tco to equal the value for that case of CannonOirB, else CannonOriR. I've tried writing
2011 Apr 07
2
replace an expression with its value, or read macros
I know my subject line seems odd, but I want to replace an expression—such as a variable—with its value. For example, I want to paste() some strings together, assign the result to a variable s, then use the value of s as a variable to hold another value. Something like this:
import_subjects <- function (start, iterations) {
for (i in 1:iterations) { # iterate from start to end
s <-
2007 Apr 05
8
package for Matlab
Hallo,
does a package for Matlab exist in R?
If yes, where can I find it and how can I install it under R?
Thanks, Corinna
2007 May 25
1
normality tests [Broadcast]
The normality of the residuals is important in the inference procedures for the classical linear regression model, and normality is very important in correlation analysis (second moment)...
Washington S. Silva
> Thank you all for your replies.... they have been more useful... well
> in my case I have chosen to do some parametric tests (more precisely
> correlation and linear regressions
2012 Nov 28
4
How to disable ipv6
Hi all,
I'm pretty new to CentOS. I am working with a newly set-up server:
[cbearden at host ~]$ lsb_release -a
LSB Version:
:core-4.0-amd64:core-4.0-noarch:graphics-4.0-amd64:graphics-4.0-noarch:printing-4.0-amd64:printing-4.0-noarch
Distributor ID: CentOS
Description: CentOS release 6.3 (Final)
Release: 6.3
Codename: Final
I'm trying to solve this problem (X11 forwarding)
2009 Mar 25
1
Hopefully a simple question
What am I missing here? Both of my column headers in the 'FREQ' table are found in the 'genotype'; however, they aren't being recognized.
> colnames(FREQ)
[1] "X17362526" "X17362627"
> colnames(genotype)
[1] "X17362311" "X17362316" "X17362346" "X17362420" "X17362421" "X17362422"
2010 Sep 17
1
How to compare, match two columns from diferent dataframe and assign values from one datafram to the other
Dear R experts,
I'm new to R. It seems to be a simple question but I just can't find a way to do it. Please help me.
I have two data sets x and y as shown in the following. I want to compare the first two columns in x and y, find the matched ones and assign the relative value from column 2 of y to generate the third column of x. Any help wil be appreciated. Thanks.
> x
[,1]
2010 Jul 16
2
Deleting a variable number of characters from a string
I have a text processing problem I'm hoping someone can help me solve. This issue it this.
I have a character string in which I need to delete a variable number of characters from the string. The string itself contains the number of characters to be deleted. The number of characters to be deleted is proceeded by either a "+" or a "-".
A toy example:
Suppose I have
2008 Sep 08
7
Question about multiple regression
Dear R-list,
maybe some of you could point me in the right direction:
Are you aware of any FREE Fortran or Java libraries/actual pieces of
code that are VERY efficient (time-wise) in running the regular linear
least-squares multiple regression?
More specifically, I have to run small regression models (between 1
and 15 predictors) on samples of up to N=700 but thousands and
thousands of them.
I
2007 Jun 14
3
Problems with na.rm=T
Suddenly (e.g. yesterday) all my functions that have "na.rm=" as a
parameter (e.g., mean(), sd(), range(), etc.) have been reporting
warnings with "na.rm=T". The message is "Warning message: the condition
has length > 1 and only the first element will be used in: if (na.rm) x
<- x[!is.na(x)] ". This has never happened before. I don't recall
having done
2004 Jul 07
1
AW: boxplot a list of objects
One possibility ist
boxplot(sapply(ListOfNames, get, env = .GlobalEnv))
Hope that this helps
Thomas
-----Urspr??ngliche Nachricht-----
Von: Lefebure Tristan [mailto:Tristan.Lefebure at univ-lyon1.fr]
Gesendet: Mittwoch, 7. Juli 2004 10:34
An: r-help at stat.math.ethz.ch
Betreff: [R] boxplot a list of objects
Hi list,
#Imagine we have vectors of different length (in practice 100 vectors):
2010 Jul 21
3
String processing - is there a better way
I have a two part question
Part 1)
I am trying to remove characters in a string based on the position of a key character in another string.? I have a solution that works but it requires a for-loop.? A vectorized way of doing this has alluded me.?
CleanRead<-function(x,y) {
? if (!is.character(x))
??? x <- as.character(x)
? if (!is.character(y))
??? y <- as.character(y)
?
2012 Mar 14
3
Needing a better solution to a lookup problem.
I have a solution (actually a few) to this problem, but none are computationally efficient enough to be useful. I'm hoping someone can enlighten me to a better solution.
I have data frame of chromosome/position pairs (along with other data for the location). For each pair I need to determine if it is with in a given data frame of ranges. I need to keep only the pairs that are within any of