similar to: Understanding eval

I ran into a weird, to me at least, problem, and hoping someone can shed some light into it. In a nutshell, there seems to be some problem when one calls plot with a formula, from within another function, using ... to pass arguments, and one of those arguments being xlim (and only xlim shows this problem). Here is an example: > plotw <- function(obj,...) { + plot(k~j,

I'm trying to do a linear regression between the columns of matrices. In example below I want to regress column 1 of matrix xdat with column1 of ydat and do a separate regression between the column 2s of each matrix. But the output I get seems to give correct slopes but incorrect intercepts and another set of slopes with value NA. How do I do this correctly? I'm after the slope and

Dear all, I have a problem when passing parms from one function to another when the argument list is just '...'. Consider this example: foo<-function(){ xx <- 111222 bar(x=xx) } bar <- function(...){ cl <- match.call(expand.dots=TRUE) print(cl) x <- eval(cl$x) print(x) } foo() > bar(x = xx) > Error in eval(expr, envir, enclos) : Object "xx" not

Hi all, I'm trying to write a plugin for R Commander, following the model of the TeachingDemos plugin. I am struggling trying to even add items by editing the menus.txt file. I would welcome any help from anyone who has messed with it. Essentially the problem I am having is: I cannot create a submenu to a newly created menu. Here is what the menus.txt file looks like: # type

Greetings, I am trying to add a boxplot to the bottom of a histogram, right between the histogram bars and the x axis. Here is the code I am using at the moment (the par line is probably not relevant for our discussion): hs <- hist(x, breaks = 20, plot = F) par(mar = c(3,3,2,1)) hist(x, breaks = 20, main = NULL, ylim = c(-2, max(hs$counts))) boxplot(x, horizontal = T, axes = T, add =

Hello all, I ran into the following, to me unexpected, behavior. I have (for reasons that don't necessarily pertain to the question at hand, hence I won't go into them) the need/desire to use an empty string for the name of a vector entry. Perhaps I did not read ?"[" very carefully, but it seems to me that he following lines should return "1" at the end:

Greetings, I have a problem that I am sure is very straightforward, but I just can't wrap my head around it. I've read the help pages on text, plotmath, expression, substitute, but somehow I can't find the answer to this simple question. Basically consider the following example: plot( NULL, xlim = c(0,2), ylim = c(0,2) ) expressions <- expression( -infinity, infinity )

I am absolutely new to R and I am aware of only a few basic command lines. I was running a robust regression in R, using the following command line library (MASS) rfdmodel1 <- rlm (TotalEmployment_2004 ~ MISSISSIPPI + LOUISIANA + TotalEmployment_2000 + PCWhitePop_2004 + UnemploymentRate_2004 + PCUrbanPop2000 + PCPeopleWithACollegeDegree_2000 + PCPopulation.of.or.over.65.years.of.age_2004)

Dear friends, I am testing glm as at page 514/515 of THE R BOOK by M.Crawley, that is on proportion data. I use glm(y~x1+,family=binomial) y is a proportion in (0,1), and x is a real number. I get the error: In eval(expr, envir, enclos) : non-integer #successes in a binomial glm! But that is exactly what was suggested in the book, where there is no mention of a similar warning. Where am I

> datafilename="E:/my documents/r/sex/bysex1.csv" > data.sex=read.table(datafilename,header=T) > data.sex y.sex.age.region.c.n 1 1980,F,A,N,-18.15,13.61 2 1980,F,A,N,-18.61,13.04 3 1980,F,A,N,-18.81,12.32 4 1990,F,A,N,-21.12,11.7 5 1990,F,A,N,-20.77,11.58 6 1990,F,A,N,-21.6,13.34 7 1990,F,A,N,-21.78,12.6 > model.anova<-aov(c~age*sex,data=data.sex)

Hello, new to the list, first message. This question perhaps might be more appropriate to R-sig-teaching, and I'd be happy to take it there if this is not the right place for it. I am teaching applied statistics at a small liberal arts college with limited resources, and we are currently using SPSS for our courses. Mainly the reason for this, as I understand it, is that this is what

Dear mailing list, I have found some strange behaviour which I think relates to parent frames and eval. Can anyone explain what's going on here? First example: > test.parent.funcs_ function() { outer.var_ 5 subfunc1_ function() substitute( outer.var, envir=parent.frame()) print( subfunc1()) subfunc2b_ function() eval( quote( outer.var), envir=parent.frame()) print(

Hi R-listers, I am trying to make a trellis boxplot with the HSuccess (y-axis) in each Rayos (beach sections) (x-axis), for each Aeventexhumed (A, B, C) - nesting event. I am not able to do so and keep receiving: Error in eval(expr, envir, enclos) : object 'Rayos' not found Please advise, Jean require(plyr) resp <- read.csv("ABC Arribada R File Dec 12 Jean

my understanding of `eval' behaviour is obviously incomplete. my question: usually `eval(expr)' and `eval(expr, envir=parent.frame())' should be identical. why does the last `eval' (yielding `r3') in this code _not_ evaluate in the local environment of function `f' but rather in the global environment (if `f' is called from there)?

I just acquired a copy of "Statistical Models in S", I guess most commonly known as the "white book", and realized to my dismay that most of the code is not directly executable in R, and I was wondering if there was a source discussing the things that are different and what the new ways of calling things are. For instance, the first obstacle was the solder.balance data

I have a data frame named "database" with panel data, a little piece of which looks like this: Symbol Name Trial Factor1 Factor2 External 1 548140 A 1 -3.87 -0.32 0.01 2 547400 B 1 12.11 -0.68 0.40 3 547173 C 1

hello all sorry for the following "none" R related question. does anyone know of a reference to calculate the following identity: |I + ABC| where I is an identity matrix and A, B,C may not have to be square matrices? you help will be greatly appreciated. H. V. Henderson; S. R. Searle SIAM Review, Vol. 23, No. 1. (Jan., 1981), pp. 53-60. provides a result to

I don't have time now to investigate myself, and I'm not feeling like deciding myself if the following is a bug: myplot <- function(dat, cex = 1.2, ...) { if(!is.data.frame(dat <- as.data.frame(dat))) stop("`dat' must be a data.frame") if(any(is.na(match(c("x","y"), names(dat))))) stop("`dat' must have a `x' and a

I'm running an LSODA to generate some graphs, but I need to stop at a certain point and use those values to generate another LSODA output. This is working fine, but when I try to run the second LSODA, I get the "Error in eval(expr, envir, enclos) : object 'N' not found". Any ideas what can be causing this? I have no object 'N' anywhere in the script. I made an

Hi all, I have a problem to estimate Std. Error and t-value by ?polr? in library Mass. They result from the summary of a polr object. I can obtain them working in the R environment with the following statements: temp <- polr(formula = formula1, data = data1) coeff <- summary(temp), but when the above statements are enclosed in a function, summary reports the following error: