similar to: how to shorten elements in a data frame?

Displaying 20 results from an estimated 7000 matches similar to: "how to shorten elements in a data frame?"

2008 Nov 24
4
EPT walks for guest page table
Hi, I am really confused about NPT walks for guest page table , and eager to know the details about it. It is treated as data writes even if the access itself is a code read in AMD NPT.I just want to know : is it the same in EPT? Could anyone help me? I would like to know that very much Thank you in advance Bo Ma _______________________________________________ Xen-devel mailing list
2009 Sep 25
2
synchronisation of time series data using interpolation
Readers, I have data with different time stamps that I wish to plot (for example): data set 1 time(hh:mm:ss),datum 01:00:00,500 01:00:15,600 01:00:30,750 01:00:45,720 01:01:00,700 01:01:15,725 01:01:30,640 01:01:45,710 data set 2 time,datum 01:00:12,20 01:01:01,55 01:01:55,22 The time interval in data set 1 does not change, but the time interval in data set 2 does change, such that for a
2004 Mar 03
8
need help with smooth.spline
Dear R listers, When using smooth.spline to interpolate data, results are generally good. However, some cases produce totally unreasonable results. The data are values of pressure, temperature, and salinity from a probe that is lowered into the ocean, and the objective is to interpolate temperature and salinity to specified pressures. While smooth.spline provides excellent values at the
2005 Jul 25
1
Fortran function name not in load table
Using R 2.0.1 on Windows XP, I am getting an error msg: Error in .Fortran("conic", nxy = nxy, npt = npt, CP = cp, EP1 = ep1, EP2 = ep2, : Fortran function name not in load table I am wondering if there is a way to see what function names are in the load table? Maybe the function name has been altered? The first thing I do in my analysis script is to load a DLL, conic.dll,
2010 Jul 06
1
information reduction-database management question
If you redefine your NAs as below to be detected as some arbitrary large number, then the code should work through. Any 5's left in your dataset can be replaced just as easily by NAs again. Not elegant, but effective. site <- c("s1", "s1", "s1", "s2","s2", "s2") pref <- c(1, 2, 3, 1, 2, 3) R1 <- c(NA, NA, 1, NA,NA,NA) R2
2004 Jun 25
2
[LLVMdev] Using -noexternals option of NightlyTest.pl
Result night tester run at FreeBSD 5.1 accessable by URL http://npt.cc.rsu.ru/testresults-X86-FreeBSD/index.html I can't guaranty run it per day base, sorry. As i can see, make (bug 385) and perl (bug 386) not builded by NightlyTest.pl (but builded if use gmake night tests run format) So I don't known preferable solutions: its can be closed or patches applied. Vladimir
2014 May 29
1
Divide error in kvm_unlock_kick()
Chris Webb <chris at arachsys.com> wrote: > My CPU flags inside the crashing guest look like this: > > fpu vme de pse tsc msr pae mce cx8 apic sep mtrr pge mca cmov pat pse36 clflush > mmx fxsr sse sse2 ht syscall nx mmxext fxsr_opt pdpe1gb lm rep_good nopl > extd_apicid pni pclmulqdq ssse3 fma cx16 sse4_1 sse4_2 x2apic popcnt aes xsave > avx f16c hypervisor lahf_lm
2014 May 29
1
Divide error in kvm_unlock_kick()
Chris Webb <chris at arachsys.com> wrote: > My CPU flags inside the crashing guest look like this: > > fpu vme de pse tsc msr pae mce cx8 apic sep mtrr pge mca cmov pat pse36 clflush > mmx fxsr sse sse2 ht syscall nx mmxext fxsr_opt pdpe1gb lm rep_good nopl > extd_apicid pni pclmulqdq ssse3 fma cx16 sse4_1 sse4_2 x2apic popcnt aes xsave > avx f16c hypervisor lahf_lm
2014 Dec 12
2
Fwd: Fwd: Fwd: Fwd: Fwd: Fwd: Fwd: Fwd: 26.
Anna Crepes: Traubenzucker + Feldsalat spezielles Dressing (bringt selbst mit?) -------- Weitergeleitete Nachricht -------- Betreff: Fwd: Fwd: Fwd: Fwd: Fwd: Fwd: Fwd: 26. Datum: Thu, 11 Dec 2014 15:34:39 +0100 Von: Markus <universe at truemetal.org> An: universe at truemetal.org Geschenke Moritz: dunkle Schokolade. Geschenke Anna: normale Schokolade. -------- Weitergeleitete
2008 Jul 15
1
code reduction (if anyone feels like it)
# I am sure that I could be more efficient than this but how? Thanks in advance. #GPS in Decimal Degrees in the form longitude latitude RM215 <- matrix(c(-82.1461363, 33.5959109), nrow=1) SC <- matrix(c(-82.025888, 33.606454), nrow=1) RM202 <- matrix(c(-81.9906723, 33.5027653), nrow=1) RM198 <- matrix(c(-81.926823, 33.4634678), nrow=1) HC <- matrix(c(-81.920505, 33.46192), nrow=1)
2004 Jun 25
0
[LLVMdev] Using -noexternals option of NightlyTest.pl
On Fri, 25 Jun 2004, Vladimir Merzliakov wrote: > Result night tester run at FreeBSD 5.1 accessable by URL > http://npt.cc.rsu.ru/testresults-X86-FreeBSD/index.html > I can't guaranty run it per day base, sorry. Okay, sounds great. I added it to the page with a note to that effect: http://llvm.cs.uiuc.edu/testresults/ Thanks a lot for volenteering to run it. Also, if you notice
2011 Mar 10
2
Selecting ranges of dates from a dataframe
Hello list! I have a data.frame which looks like this: > serv datum op.read op.write read write 1 2011-01-29 10:00:00 0 0 0 0 2 2011-01-29 10:00:01 0 0 0 0 3 2011-01-29 10:00:02 0 0 0 0 4 2011-01-29 10:00:03 0 4 0 647168 5 2011-01-29 10:00:04 0 0 0 0 6 2011-01-29
2012 Aug 07
2
What is this called? lapply(datum,"[[","ColumnName")
Hello R users I recently learned how to use this command: lapply(datum,"[[","ColumnName") Unfortunately, I don't know how exactly it works, what it's called (in particular the "[[" part], and what other things you can do with it (retrieve multiple columns?). Given datum is a list of dataframes with the same column, but different number of rows,
2011 Nov 30
2
nls help
Hello, I have data like the following: datum <- structure(list(Y = c(415.5, 3847.83333325, 1942.833333325, 1215.22222233333, 950.142857325, 2399.5833335, 804.75, 579.5, 841.708333325, 494.053571425 ), X = c(1.081818182, 0.492727273, 0.756363636, 0.896363636, 1.518181818, 0.499166667, 1.354545455, 1.61, 1.706363636, 1.063636364 )), .Names = c("Y", "X"), row.names = c(NA,
2010 Jun 06
1
I need help in analyzing
I'm sory for my weak english. I need to analyze this subject : x1 x2 x3 x4 x5 x6 x7 x8 x9 x10 y 0 0 1 0 0 1 0 0 1 0 czarne 1 1 0 0 0 0 1 0 0 0 rude 0 0 1 0 0 1 1 0 0 0 braz 0 0 1 0 1 0 1 0 0 0 blond 1 0 0 0 0 1 0 0 0 1 rude 1 1 0 0 0 0 0 0 0 1 blond 0 0 1 1 0 0 0 0 1 0 czarne 1 0 0 1 0 0 1 0 0 0 blond 0 0 1 0 0 1 1 0 0 0 blond 1 0 0 0 0 1 1 0 0 0 czarne 0 0 1 0 0 1 0 0 0 1 czarne 1 0 1 0 0 0
2005 Aug 02
3
how to print a data.frame without row.names
Dear All, is there a simple way to print a data.frame without its row.names? example: datum <- as.Date(c("2004-01-01", "2004-01-06", "2004-04-12")) content <- c('Neujahr', 'Hl 3 K.', 'Ostern') df1 <- data.frame(datum, content) print(df1) datum content 1 2004-01-01 Neujahr 2 2004-01-06 Hl 3 K. 3 2004-04-12 Ostern Can I get
2011 Mar 22
1
help need on working in subset within a dataframe
Dear R-experts Execuse me for an easy question, but I need help, sorry for that. >From days I have been working with a large dataset, where operations are needed within a component of dataset. Here is my question: I have big dataset where x1:.....x1000 or so. What I need to do is to work on 4 consequite variables to calculate a statistics and output. So far so good. There are more vector
2012 Oct 18
1
spTransform longlat to utm
Dear all, I am trying to project my LongLat-maps to a plane. The ultimate purpose is to do a search of points in vicinity of other points using overlay-commands (sp) with radius in km. I am applying spTransform (package rgdal) and it gives my some curious results. An example. Let's take a point lying somewhere in Germany, zone=32U x <- 8.968735 y <- 49.454735 After conversion I
2008 Dec 20
2
NA, where no NA should (could!) be!
Hello, again I'm on my weblog-script... having problems... This code: =========================== weblog <- read_weblog("web.log") weblog_by_date <- split(weblog, weblog$date) #for ( i in names(weblog_by_day) ) { print(i); print(weblog_by_day$i) } for ( datum in names(weblog_by_date) ) { print(datum) selected <- weblog_by_date[[datum]] res_size_by_host <-
2004 Nov 03
3
cut POSIX results in NA - bug?
Dear all I try to make hourly average by cut() function, which almost works as *I* expected. What puzled me is that if there is only one item at the end of your data it results in NA. Example will explain what I mean datum<-seq(ISOdate(2004,8,31), ISOdate(2004,9,1), "min") cut(datum[1370:1381],"hour", labels=F) [1] 1 1 1 1 1 1 1 1 1 1 1 NA