similar to: HELP: How to subtract a vector out of each row of a matrix or array

Hi R, I have a column with dates. I need to create a vector say from (current date-90 days: current date) For example I need to subtract 90 days from say Sys.Date()-92 If Sys.Date()-92 == "Sunday", Sys.Date()-92+1 if Sys.Date()-92 == "Saturday", Sys.Date()-92+2 i.e if subtracting gives me a weekend I need the next work day. I used the below.

Hello I have this little dataset, my goal is create one column in the data.frame with between the diference DataTime and Duration. I'm using the next code to make do this TIME_STAMP SESSIONTIME Time TimeStart 1162343932 8320 2006-10-31 19:01:34 2006-10-31 16:42:54 1162343215 592 2006-10-31 19:02:04 2006-10-31 18:52:12 1162341465 11875

Hi, For some 64-bit immediates, ARM can generate a two instruction sequence. For example, for the following code: ; 734439407618 = 0x000000ab00000002 define i64 @f1(i64 %a) { %tmp = sub i64 %a, 734439407618 ret i64 %tmp } We should be able to generate: subs r0, r0, #1 sbc r1, r1, #171 @ 0xab But instead we get: $ llvm-as < %s | llc -march=thumb -mattr=+thumb2 mvn r2, #1

Hi, I am new to R an dI need some help I have a matrix of real values 100*300 and I would like to calculate the mean for each column , then for each entry in a column i need to subtract the mean so I will have a matrix where the columns have zero mean. any one know how to do that . Thanks -- View this message in context:

Just starting to learn R so excuse me if this is a simple question. I'm wondering how I get the percent difference in sequential values in one column of a dataframe. If I had a dataframe and one of the columns was "value", how would I go about calculating (v2-v1)/v1 ....(v3-v2)/v2 ....(v4-v3)/v3 ...etc ? -- View this message in context:

hi R users I have a data set with the name AA AA<-1:100 Now I want to get a child array from AA every 10 numbers e.g. ab =c(10,20,30,40,50,60,70,80,100) How could I subtract aa from AA? thank you . -- TANG Jie Email: totangjie@gmail.com Tel: 0086-2154896104 Shanghai Typhoon Institute,China [[alternative HTML version deleted]]

--- silk/arm/macros_arm64.h | 39 +++++++++++++++++++++++++++++++++++++++ silk/macros.h | 4 ++++ silk_headers.mk | 1 + 3 files changed, 44 insertions(+) create mode 100644 silk/arm/macros_arm64.h diff --git a/silk/arm/macros_arm64.h b/silk/arm/macros_arm64.h new file mode 100644 index 0000000..ed03041 --- /dev/null +++ b/silk/arm/macros_arm64.h @@ -0,0 +1,39 @@

Hi everyone, I am having trouble using my own data in the Nash-Sutcliffe efficiency (NSE) function. In R, this is what I have done: Vobsr <- read.csv("Observed_Flow.csv", header = TRUE, sep =",") # see data below Vsimr <- read.csv("1000Samples_Vsim.csv", header = TRUE, sep =",") # see data below Vobsr <- as.matrix(Vobsr[,-1]) # remove column 1

I have the following array: 3 dimensional object, one dimension being year. Object is 3*3*3 library(plyr, reshape) a1<-rep(c(2007,2008,2009),9) a2<-c(rep("a",9),rep("b",9),rep("c",9)) a3<-c(rep(c(rep(1,3),rep(2,3),rep(3,3)),3)) a4 <- rnorm(27) A<-data.frame(cbind(comp=a2,val=a3, year=a1, a4)) A1<-melt(A, id=c("year", "comp",

Hi, For example, given two 2x2 matrices m1 and m2. I would like to add/subtract element by element > m1 [,1] [,2] [1,] NA NA [2,] 1 2 > m2 [,1] [,2] [1,] 1 NA [2,] NA 2 > m1 + m2 [,1] [,2] [1,] NA NA [2,] NA 4 How can I ignore the NA, and get this ? Hope the solution can be extended to subtract and modulo also. [,1] [,2]

Hi list, I am writing a for loop that looks like this: samples<-rep(NA,10) x <- rep(c(111, 225), 5) for(i in 1:10){ If(x[i]<200){ samples[i] <- x[i] }else{ i=i-1 } } The problem is that the returning vector still contains NA, I think the i in "else" is not getting subtracted. How should I get it to work? Thanks, Mike [[alternative HTML version

Hello everybody, how can I reduce e.g. 30 days from a date? When I do the following "2011-05-01 CEST" -"2011-04-01 CEST" I get: "Time difference of 30 days" an thats fine. But when I try "2011-05-01 CEST" - 30 I get nonsense. So how can I subtract some days, month or years from a date? thanking you in anticipation Claudia Paladini

Hi, I have a dataframe wf existing of a header with different labels and beneath the values of those labels : wf: label1 label2 ... 0,45 0,21 0,10 0,45 .... .... I have a list fl <- c("label2","label3",..) Isn't possible to use the list elements in the list in order to subtract values from the dataframe? like : wf$fl[[1]] When I do in R I get :NULL

there are really two related problems here I have a 2D matrix A <- matrix(1:100,nrow=20,ncol =5) S <- matrix(1:10,nrow=2,ncol =5) #I want to subtract S from A. so that S would be subtracted from the first 2 rows of #A, then the next two rows and so on. #I have a the same problem with a 3D array # where I want to subtract Q for every layer (1-10) in Z # I thought I solved this one

Hello, I'm having problems working with date values in POSIXct format. Here is what I got (eg.lig attached): x <- read.table("eg.txt", sep = ',', col.names=c("ok","time","secs","lig")) # it gives time as factor z <- cbind(x,colsplit(x$time, split="\\s", names=c("date", "clock")))

Dear R-help I am using R version 2.6.2. I am trying to subtract specific values from a larger data frame. I feel this should be straightforward, but I am struggling. I have a dataframe "Bk" as follows: DateTime cumPrecip 01/01/2008 00:00 348 01/01/2008 01:00 348 01/01/2008 02:00 348 01/01/2008 03:00 347 01/01/2008 04:00 348 01/01/2008 05:00 348 01/01/2008 06:00 349

Dear R Group Here is what i am trying to do.. but couldnt figure out how.. string<-"ABC DEFG HIJKLM NOPQ RSTUV WXY" string1<-substr(string,1,4) I want to create an R object string 2 ( following the logic shown).. R does not allow string subtraction.. any suggestions how to achieve this? string2<-string-string1 (it should now hold "DEFG HIJKLM NOPQ RSTUV WXY" I

Dear list, could someone point me to the right command to subtract 2 columns in a data.frame. Might be a bit embarrassing question. But I cannot figure out how to do this simple command in R. Thanks, Ulrich -- __________________________________________________ Ulrich Leopold MSc. Department of Physical Geography Institute for Biodiversity and Ecosystem Dynamics Faculty of Science University

I have the following: Table Products: With a column called "purchased_at" of type "datetime". Products.find(:all, :conditions => ["? - purchased_at >= 120", Time.now]) Why doesn''t that work? What I''m trying to do is find records that were purchased less than or equal to 2 minutes ago. Thanks for your help. -- Posted via

Dear R experts, I've realized that it might not be possible to define a negative SELCET statement in a SQL call so now I'm looking for the smoothest way to generate a list of what I would like from my large database by first pulling all the names with a query like this "SELECT top 1 * FROM your_table" (thank you Bart Joosen for the idea) and then subtract the variables I am not