similar to: (R) Using arguments for the empirical cumulative distribution function

Hello, I created an empirical distribution function: x = c(1.6,1.8,2.4,2.7,2.9,3.3,3.4,3.4,4,5.2) F2.5 <- ecdf(x) plot(F2.5, verticals= TRUE, do.p = TRUE, lwd=3, ylab = "f(x)", xlab = "x", main = "Figur 2.5 Empirische Verteilfunktion", xlim = c(1,5.5)) abline(h= (0:5)*0.2) Now I would like to label the points on the

Hi, I've got the following edf: *** x = c(1.6,1.8,2.4,2.7,2.9,3.3,3.4,3.4,4,5.2) F2.5 <- ecdf(x) plot(F2.5, verticals= TRUE, do.p = TRUE, lwd=3, ylab = "", xlab = "", xlim = c(1,5.5)) abline(h= (0:5)*0.2) #mean abline(v=mean(x), lwd=2) mtext(text=expression(bar(x) == 3.07), side=1, adj=0.462, padj=3, cex=1) *** Now I would like to

Hello, I have the following problem: I created an ecdf and a barplot. Unfortunatly, the bars are not where I would like them to be (please see picture below). http://www.nabble.com/file/p12877530/problem.gif That's my code: #------------------------ par(mfrow=c(2,1), mar=c(2,3,3,2)) #ECDF x = c(0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 2, 2, 2) F2.5 <- ecdf(x) plot(F2.5,

http://r.789695.n4.nabble.com/file/n3567636/ecdfs.jpg ecdfs.jpg http://r.789695.n4.nabble.com/file/n3567636/ecdf_curve.gif ecdf_curve.gif Hello, I have generated a plot of two empirical CDFs (attachment 1). As a result, they are stepwise when plotted. The following code was used: > plot(ecdf(mut), do.points=FALSE, verticals=TRUE, xlim=range(mut, non), > col="red") >

Greetings, I am attempting to use R throug PL/R in PostgreSQL to make several graphs (they show usage over time for radiochannels). However, as some never go above 100 in a 24 hour period, and others go well over 500, they get different y-axis values (which normally would be a good thing). However, as I want to overlay the graphs to add/remove channels in CSS on a webpage, I need a set y-axis.

Hi, all ecdf function (Empirical Cumulative Distribution Function) in "stats" package counts from smaller values to larger values. However, I want to draw it by counting from larger value to smaller values and I couldn't find options for this purpose. How can I draw ecdf or ecdf like graph by counting from larger values to smaller values. Thank you in advance. Hyunchul Kim

Hi! When I plot my filled.contour plot > filled.contour(dat,color=rainbow,plot.axes=matrix.axes(dat),xlab=myxlab,ylab=myylab) everything looks fine on the screen. But if I wrap these two lines >postscript(file="myplot.eps",paper="special",width=4,height=4,family='Times',horizontal=FALSE) ... >dev.off() around the line above in order to create an eps file, the

Dear R Users, Does R have an "inverse empirical cumulative distribution" function, something one can use to invert ecdf ? Thanks in advance, Tolga Generally, this communication is for informational purposes only and it is not intended as an offer or solicitation for the purchase or sale of any financial instrument or as an official confirmation of any transaction. In the event you

Dear list, I would like to plot the empirical cumulative distribution of the time needed by a treatment to attain a certain goal. A number of experiments is run with a strict time limit. In some experiments the goal is attained before the time limit, in other experiments time expires before the goal is attained. The situation is very similar to survivial analysis with censored data. I tryed

Hi, I was trying to draw an empirical distribution function with uniform confidence bands. So I tried to find a way to calculate values of the Kolmogorov-Smirnov Distribution but failed. I guess it must be hidden somewhere (since the ks-test is implemented), but I was unable to find it. Is there any way to do this? Thanks Leif Boysen

Hello, Does anyone know if it's possible to change the text direction of mtext? I'd like to use 'mtext(side=2)' but the text should be 'left-to-right'. I couldn't find an argument for that in the help files. Thanks for any suggestions Tobias -- View this message in context: http://www.nabble.com/changing-text-direction-of-mtext-tf4321931.html#a12307342 Sent from

Hi R users, I am a new user, still learning basics of R. Is there anyway to extract y (or x) value for a known x (or y) value from ecdf (empirical cumulative distribution function) curve? Thanks in advance. Mano. [[alternative HTML version deleted]]

I have the following code: mtext(text="X[1]") How can I change "[1]" to be subscript? (see picture below) http://www.nabble.com/file/p12241351/subscript.gif subscript.gif Thanks for any help Tobias -- View this message in context: http://www.nabble.com/Subscript-tf4300665.html#a12241351 Sent from the R help mailing list archive at Nabble.com.

Hello, I'm trying to create the following graph: http://www.nabble.com/file/p12974686/bar.gif Is there a command (like pie(...) or barplot(...)) or is this just a special case of eg barplot? I'd be glad if someone could give me a hint on where to start. Regards, Tobias -- View this message in context: http://www.nabble.com/how-to-create-this-graph--tf4546742.html#a12974686 Sent from

Hi. I have the following two ecdf plots in one graph: plot( ecdf(....), do.points=FALSE, verticals=TRUE, main=paste("Ecdf of distances ",DIM,sep=""), col="red" ); lines( ecdf(....), do.points=FALSE, verticals=TRUE ); How do I change the color of the resulting graph? Adding col="red" to either plot or lines results in an error

Hi list members I have a vector of strings x=c("w","ex","ee") And I want to get a logical vector showing the positions where my search string "e" matches the elements partially, i.e. is at least the left-hand part of the target strings, i.e. I want to get a vector FALSE TRUE TRUE. Any ideas? Thanks Steve Powell proMENTE social research research |

hello, if i start a transient guest doamin via "virsh create abcd.xml" i see an additional libvirt thread and also some open files: pstree -h `pgrep libvirtd` libvirtd───11*[{libvirtd}] libvirtd 3016 root 21w REG 253,0 6044 1052094 /var/log/libvirt/libxl/abcd.log libvirtd 3016 root 22r FIFO 0,8 0t0 126124 pipe libvirtd 3016 root

Hello all, I would like to plot the emperical CDF, normal CDF and pareto CDF in the same graph and I amusing the following codes. "z" is a vector and I just need the part when z between 1.6 and 3. plot(ecdf(z), do.points=FALSE, verticals=TRUE, xlim=c(1.6,3),ylim=c(1-sum(z>1.6)/length(z), 1)) x <- seq(1.6, 3, 0.1) lines(x,pgpd(x, 1.544,0.4373,-0.2398), col="red") y

Hi all, given this example #start a<-c(0,70,50,100,70,650,1300,6900,1780,4930,1120,700,190,940, 760,100,300,36270,5610,249680,1760,4040,164890,17230,75140,1870,22380,5890,2430) length(a) b<-c(0,0,10,30,50,440,1000,140,70,90,60,60,20,90,180,30,90, 3220,490,20790,290,740,5350,940,3910,0,640,850,260) length(b) out<-ks.test(log10(a+1),log10(b+1)) # max distance D

Hello, if I plot a horizontal line, e.g., plot(c(1,2),c(1,1),xlim=c(0,3),lwd=2,type="l") or plot(c(1,2),c(1,1),xlim=c(0,3),lwd=4,type="l") then the left end (1st example) or both ends (2nd example) of the lines are not rectangular but slanted on the graphical display (screen). That behavour first occurred when I was trying to plot a stepfun, e.g., y <-