Displaying 20 results from an estimated 10000 matches similar to: "fixed effects anova in lme lmer"
2009 Feb 08
1
sub() with "+" - invalid regular expression
Hi,
can someone help me;
I don't understand why this code doesn't do what it's supposed to do;
x <- c("F+", "F+")
x <- sub("F+", "F", x)
x
[1] "F+" "F+"
(I want "F" "F")
when I try this;
x <- c("F+", "F+")
x <- sub("+", "", x)
x
I get an error
2016 Apr 29
2
selecting columns from a data frame or data table by type, ie, numeric, integer
Good morning RGuru's
I have a data frame of 575 columns.? I want to extract only those columns that are numeric(double) or integer to do some machine learning with.? I have searched the web for a couple of days (off and on) and have not found anything that shows how to do this.?? Lots of ways to extract rows, but not columns.? I have attempted to use "(x == y)" indices extraction
2007 Jun 01
2
how to specify starting values in varIdent() of lme()
I was reading the help but just did not get how to specify starting values for
varIdent() of the lme() function, although I managed to do it for corSymm().
Do I specify the values just as they are printed out in an output, like c(1,
1.3473, 1.0195). Or do I need to take the residual and multiply it with these
like c(0.2235, 0.2235*1.3473, 0.2235*1.0195)
or any other form that I dont know of?
2016 Apr 29
0
selecting columns from a data frame or data table by type, ie, numeric, integer
> dt1[ vapply(dt1, FUN=is.numeric, FUN.VALUE=NA) ]
a c
1 1 1.1
2 2 1.0
...
10 10 0.2
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Fri, Apr 29, 2016 at 9:19 AM, Carl Sutton via R-help <
r-help at r-project.org> wrote:
> Good morning RGuru's
> I have a data frame of 575 columns. I want to extract only those columns
> that are numeric(double) or integer to do
2023 Nov 03
2
Sum data according to date in sequence
Hi,
I tried this:
# extract date from the time stamp
dt1 <- cbind(as.Date(dt$EndDate, format="%m/%d/%Y"), dt$EnergykWh)
head(dt1)
colnames(dt1) <- c("date", "EnergykWh")
and
my dt1 becomes these, the dates are replace by numbers.
dt1 <- cbind(as.Date(dt$EndDate, format="%m/%d/%Y"), dt$EnergykWh)
dput(head(dt1))
colnames(dt1) <-
2007 May 21
1
can I get same results using lme and gls?
Hi All
I was wondering how to get the same results with gls and lme. In my lme, the
design matrix for the random effects is (should be) a identity matrix and
therefore G should add up with R to produce the R matrix that gls would report
(V=ZGZ'+R). Added complexity is that I have 3 levels, so I have R, G and say H
(V=WHW'+ZGZ'+R). The lme is giving me the correct results, I am
2017 Nov 27
0
How to extract coefficients from sequential (type 1) ANOVAs using lmer and lme
I wantto run sequential ANOVAs (i.e. type I sums of squares), and trying to getresults including ANOVA tables and associated coefficients for predictive variables(I am using the R 3.4.2 version). I think ANOVA tables look right, but believecoefficients are wrong. Specifically, it looks like that the coefficients arefrom ANOVA with ?marginal? (type III sums of squares). I have tried both lme
2023 Nov 03
1
Sum data according to date in sequence
Is this what you are after?
library(tidyverse)
library(lubridate)
input <- structure(list(StationName = c("PALO ALTO CA / CAMBRIDGE #1",
"PALO ALTO CA / CAMBRIDGE #1", "PALO ALTO CA / CAMBRIDGE #1",
"PALO ALTO CA / CAMBRIDGE #1", "PALO ALTO CA / CAMBRIDGE #1",
"PALO ALTO CA / CAMBRIDGE #1", "PALO ALTO CA / CAMBRIDGE
2006 Sep 20
1
seq.Date not accepting NULL length.out (PR#9239)
There seems to be a bug in seq.Date such that it will not allow the user
to pass in length.out =3D NULL, despite the fact that this is the =
default
argument.
For example:
> dt1 <- as.Date("2004-12-31")
> dt2 <- as.Date("2005-12-31")
> seq.Date(dt1, dt2, length.out =3D NULL, by =3D "month")
Error in seq.Date(dt1, dt2, length.out =3D NULL, by =3D
2017 Nov 29
0
How to extract coefficients from sequential (type 1), ANOVAs using lmer and lme
(This time with the r-help in the recipients...)
Be careful when mixing lme4 and lmerTest together -- lmerTest extends
and changes the behavior of various lme4 functions.
>From the help page for lme4-anova (?lme4::anova.merMod)
> ?anova?: returns the sequential decomposition of the contributions
> of fixed-effects terms or, for multiple arguments, model
>
2011 May 10
1
Saving multiple 3x3 TIFF graphics inside a loop
Dear Friends,
I have been trying to save multiple 3x3 (mfrow=c(3,3) graphics inside a loop
using tiff figure format (not using PDF or savePlot functions) with no
success. Could you please help?
Here is a simplified example code:
dat=data.frame (ID=rep(1:10,each=10),IDV=rep(seq(1:10),times=10))
dat$DV <- with(dat, 50+15*IDV)
dat=dat[order(dat$ID,dat$IDV),]
for(i in 1:10){
dt1 =
2008 Aug 11
1
Simple lme/lmer random effects questions
Hello,
I have two very rudimentary questions regarding the random effects terms
in the lme and lmer functions. I apologize if this also partly strays
into a general statistics question, but I'm a bit new to this all. So
hopefully it'll be a quick problem to sort out...
Here is my experimental setup: I raised butterflies in 5 different
testing chambers all set to different
2000 Dec 25
2
Modification requests / question
Hello!
1.
You should modify the 'vorbis_ftoi(f)' for the undefinied OS/compiler
in the 'os.h' on this way:
old:
static int vorbis_ftoi(double f){
return (int)(f+.5);
}
new:
#define vorbis_ftoi(f) ((int)(f+.5f))
Because in some cases we don't use this function, and the compiler writes
many error messages.
2. Could you write a frequency and bitrate independent
2012 Jun 26
1
How to estimate variance components with lmer for models with random effects and compare them with lme results
Hi,
I performed an experiment where I raised different families coming from two
different source populations, where each family was split up into a
different treatments. After the experiment I measured several traits on each
individual.
To test for an effect of either treatment or source as well as their
interaction, I used a linear mixed effect model with family as random
factor, i.e.
2017 Dec 01
0
How to extract coefficients from sequential (type 1), ANOVAs using lmer and lme
Please reread my point #1: the tests of the (individual) coefficients in
the model summary are not the same as the ANOVA tests. There is a
certain correspondence between the two (i.e. between the coding of your
categorical variables and the type of sum of squares; and for a model
with a single predictor, F=t^2), but they are not the same in general.
The t-test in the model coefficients is simply
2013 Aug 16
1
as.Date.character speed improvement suggestion
R-Devel,
I store and retrieve a large amount of financial data (millions of rows) in a PostgreSQL database keyed by date (and represented in R by class Date). Unfortunately, I frequently find that a great deal of processing time is spent converting dates from character representations to Date class representations in R, presumably because strptime is not fast for large vectors (>10,000
2008 May 08
2
Microseconds for a zoo object?
Hello
I have a string which contains microseconds, can anyone help on
constructing this in to a time object, with the microseconds, that I can
take to a ZOO file?
Thanks
Sean
> UK[1,3]
[1] "17:09:53.824"
> UK[1,1]
[1] "2007-12-11 00:00:00"
> mydates <- paste( substr(UK[,1], 1, 10), UK[,3])
> mydates[1]
[1] "2007-12-11 17:09:53.824"
>
2011 Sep 29
1
How to Code Random Nested Variables within Two-way Fixed Model in lmer or lme
Hi All,
I am frustrated by mixed-effects model! I have searched the web for
hours, and found lots on the nested anova, but nothing useful on my
specific case, which is: a random factor (C) is nested within one of the
fixed-factors (A), and a second fixed factor (B) is crossed with the
first fixed factor:
C/A
A
B
A x B
My question: I have a functioning model using the aov command (see
2006 Jul 28
3
random effects with lmer() and lme(), three random factors
Hi, all,
I have a question about random effects model. I am dealing with a
three-factor experiment dataset. The response variable y is modeled
against three factors: Samples, Operators, and Runs. The experimental
design is as follow:
4 samples were randomly chosen from a large pool of test samples. Each
of the 4 samples was analyzed by 4 operators, randomly selected from a
group of
2012 Jun 13
1
histogram fill lattice
Dear all,
I would like to change the "fill" pattern of a histogram using histogram() in the lattice package. I know how to do so using hist(), but would prefer to stay within lattice.
dt1 <- rnorm(100,0,1)
hist(dt1, density=3, angle=45)
library(lattice)
histogram(dt1,
xlab = "Histogram of rnorm(0,1)",
type = "count",