similar to: fixed effects anova in lme lmer

Displaying 20 results from an estimated 10000 matches similar to: "fixed effects anova in lme lmer"

2009 Feb 08
1
sub() with "+" - invalid regular expression
Hi, can someone help me; I don't understand why this code doesn't do what it's supposed to do; x <- c("F+", "F+") x <- sub("F+", "F", x) x [1] "F+" "F+" (I want "F" "F") when I try this; x <- c("F+", "F+") x <- sub("+", "", x) x I get an error
2016 Apr 29
2
selecting columns from a data frame or data table by type, ie, numeric, integer
Good morning RGuru's I have a data frame of 575 columns.? I want to extract only those columns that are numeric(double) or integer to do some machine learning with.? I have searched the web for a couple of days (off and on) and have not found anything that shows how to do this.?? Lots of ways to extract rows, but not columns.? I have attempted to use "(x == y)" indices extraction
2007 Jun 01
2
how to specify starting values in varIdent() of lme()
I was reading the help but just did not get how to specify starting values for varIdent() of the lme() function, although I managed to do it for corSymm(). Do I specify the values just as they are printed out in an output, like c(1, 1.3473, 1.0195). Or do I need to take the residual and multiply it with these like c(0.2235, 0.2235*1.3473, 0.2235*1.0195) or any other form that I dont know of?
2016 Apr 29
0
selecting columns from a data frame or data table by type, ie, numeric, integer
> dt1[ vapply(dt1, FUN=is.numeric, FUN.VALUE=NA) ] a c 1 1 1.1 2 2 1.0 ... 10 10 0.2 Bill Dunlap TIBCO Software wdunlap tibco.com On Fri, Apr 29, 2016 at 9:19 AM, Carl Sutton via R-help < r-help at r-project.org> wrote: > Good morning RGuru's > I have a data frame of 575 columns. I want to extract only those columns > that are numeric(double) or integer to do
2023 Nov 03
2
Sum data according to date in sequence
Hi, I tried this: # extract date from the time stamp dt1 <- cbind(as.Date(dt$EndDate, format="%m/%d/%Y"), dt$EnergykWh) head(dt1) colnames(dt1) <- c("date", "EnergykWh") and my dt1 becomes these, the dates are replace by numbers. dt1 <- cbind(as.Date(dt$EndDate, format="%m/%d/%Y"), dt$EnergykWh) dput(head(dt1)) colnames(dt1) <-
2007 May 21
1
can I get same results using lme and gls?
Hi All I was wondering how to get the same results with gls and lme. In my lme, the design matrix for the random effects is (should be) a identity matrix and therefore G should add up with R to produce the R matrix that gls would report (V=ZGZ'+R). Added complexity is that I have 3 levels, so I have R, G and say H (V=WHW'+ZGZ'+R). The lme is giving me the correct results, I am
2017 Nov 27
0
How to extract coefficients from sequential (type 1) ANOVAs using lmer and lme
I wantto run sequential ANOVAs (i.e. type I sums of squares), and trying to getresults including ANOVA tables and associated coefficients for predictive variables(I am using the R 3.4.2 version). I think ANOVA tables look right, but believecoefficients are wrong. Specifically, it looks like that the coefficients arefrom ANOVA with ?marginal? (type III sums of squares). I have tried both lme
2023 Nov 03
1
Sum data according to date in sequence
Is this what you are after? library(tidyverse) library(lubridate) input <- structure(list(StationName = c("PALO ALTO CA / CAMBRIDGE #1", "PALO ALTO CA / CAMBRIDGE #1", "PALO ALTO CA / CAMBRIDGE #1", "PALO ALTO CA / CAMBRIDGE #1", "PALO ALTO CA / CAMBRIDGE #1", "PALO ALTO CA / CAMBRIDGE #1", "PALO ALTO CA / CAMBRIDGE
2006 Sep 20
1
seq.Date not accepting NULL length.out (PR#9239)
There seems to be a bug in seq.Date such that it will not allow the user to pass in length.out =3D NULL, despite the fact that this is the = default argument. For example: > dt1 <- as.Date("2004-12-31") > dt2 <- as.Date("2005-12-31") > seq.Date(dt1, dt2, length.out =3D NULL, by =3D "month") Error in seq.Date(dt1, dt2, length.out =3D NULL, by =3D
2017 Nov 29
0
How to extract coefficients from sequential (type 1), ANOVAs using lmer and lme
(This time with the r-help in the recipients...) Be careful when mixing lme4 and lmerTest together -- lmerTest extends and changes the behavior of various lme4 functions. >From the help page for lme4-anova (?lme4::anova.merMod) > ?anova?: returns the sequential decomposition of the contributions > of fixed-effects terms or, for multiple arguments, model >
2011 May 10
1
Saving multiple 3x3 TIFF graphics inside a loop
Dear Friends, I have been trying to save multiple 3x3 (mfrow=c(3,3) graphics inside a loop using tiff figure format (not using PDF or savePlot functions) with no success. Could you please help? Here is a simplified example code: dat=data.frame (ID=rep(1:10,each=10),IDV=rep(seq(1:10),times=10)) dat$DV <- with(dat, 50+15*IDV) dat=dat[order(dat$ID,dat$IDV),] for(i in 1:10){ dt1 =
2008 Aug 11
1
Simple lme/lmer random effects questions
Hello, I have two very rudimentary questions regarding the random effects terms in the lme and lmer functions. I apologize if this also partly strays into a general statistics question, but I'm a bit new to this all. So hopefully it'll be a quick problem to sort out... Here is my experimental setup: I raised butterflies in 5 different testing chambers all set to different
2000 Dec 25
2
Modification requests / question
Hello! 1. You should modify the 'vorbis_ftoi(f)' for the undefinied OS/compiler in the 'os.h' on this way: old: static int vorbis_ftoi(double f){ return (int)(f+.5); } new: #define vorbis_ftoi(f) ((int)(f+.5f)) Because in some cases we don't use this function, and the compiler writes many error messages. 2. Could you write a frequency and bitrate independent
2012 Jun 26
1
How to estimate variance components with lmer for models with random effects and compare them with lme results
Hi, I performed an experiment where I raised different families coming from two different source populations, where each family was split up into a different treatments. After the experiment I measured several traits on each individual. To test for an effect of either treatment or source as well as their interaction, I used a linear mixed effect model with family as random factor, i.e.
2017 Dec 01
0
How to extract coefficients from sequential (type 1), ANOVAs using lmer and lme
Please reread my point #1: the tests of the (individual) coefficients in the model summary are not the same as the ANOVA tests. There is a certain correspondence between the two (i.e. between the coding of your categorical variables and the type of sum of squares; and for a model with a single predictor, F=t^2), but they are not the same in general. The t-test in the model coefficients is simply
2013 Aug 16
1
as.Date.character speed improvement suggestion
R-Devel, I store and retrieve a large amount of financial data (millions of rows) in a PostgreSQL database keyed by date (and represented in R by class Date). Unfortunately, I frequently find that a great deal of processing time is spent converting dates from character representations to Date class representations in R, presumably because strptime is not fast for large vectors (>10,000
2008 May 08
2
Microseconds for a zoo object?
Hello I have a string which contains microseconds, can anyone help on constructing this in to a time object, with the microseconds, that I can take to a ZOO file? Thanks Sean > UK[1,3] [1] "17:09:53.824" > UK[1,1] [1] "2007-12-11 00:00:00" > mydates <- paste( substr(UK[,1], 1, 10), UK[,3]) > mydates[1] [1] "2007-12-11 17:09:53.824" >
2011 Sep 29
1
How to Code Random Nested Variables within Two-way Fixed Model in lmer or lme
Hi All, I am frustrated by mixed-effects model! I have searched the web for hours, and found lots on the nested anova, but nothing useful on my specific case, which is: a random factor (C) is nested within one of the fixed-factors (A), and a second fixed factor (B) is crossed with the first fixed factor: C/A A B A x B My question: I have a functioning model using the aov command (see
2006 Jul 28
3
random effects with lmer() and lme(), three random factors
Hi, all, I have a question about random effects model. I am dealing with a three-factor experiment dataset. The response variable y is modeled against three factors: Samples, Operators, and Runs. The experimental design is as follow: 4 samples were randomly chosen from a large pool of test samples. Each of the 4 samples was analyzed by 4 operators, randomly selected from a group of
2012 Jun 13
1
histogram fill lattice
Dear all, I would like to change the "fill" pattern of a histogram using histogram() in the lattice package. I know how to do so using hist(), but would prefer to stay within lattice. dt1 <- rnorm(100,0,1) hist(dt1, density=3, angle=45) library(lattice) histogram(dt1, xlab = "Histogram of rnorm(0,1)", type = "count",