similar to: negative number to positive number

Dear all, Thank you for any help. I have a data.frame and would like to plot it in 3D. I have tried wireframe() and cloud(), I got scatterplot3d(xs) Error: could not find function "scatterplot3d" > wireframe(xs) Error in wireframe(xs) : no applicable method for "wireframe" > persp(x=x, y=y, z=xs) Error in persp.default(x = x, y = y, z = xs) : (list)

Hi, I was wondering if there's a way in R to open a web browser (such as Internet Explorer, or Firefox or whatever). I'm doing some analyses that have associated urls, and it would be nice to have the ability to directly open the relevant page from within R. I was looking at the help for 'url' and I can see I can probably access the information I need and display it in my

Hi, after reading about it in the forum, I tried the Tinn-R editor (in WinXP) running R 2.5.0... nice one! However, I am trying to change the syntax-colouring from the default to my own preferences... and I can do that, but my options don't appear to be saved and get lost when I close Tinn-R. I've searched help menus, and google... and I can't find how to make sure my

Hi, I have been using 'read.table' regularly to read tab-delimited text files with data. No problem, until now. Now I have a file that appeared to have read fine, and the data inside looks correct (structure etc), except I only had 15000+ rows out of the expected 24000. Using 'readLines' instead, and breaking up the data by tabs, gives me the expected result. I do not

Hello, I'm doing some scripting and I've noticed that R doesn't seem to have an if (cond){ do }ifelse (cond) { do } else { do } type block. Is this correct or am I missing something. THX Paul -- Research Technician Mass Spectrometry o The / o Scripps \ o Research / o Institute

I'm trying something that I thought would be pretty simple, but it's proving quite frustrating... I want to display, for instance, the correlation coefficient "rho" in a graph. I can do something like: text(x, y, paste("rho =", cor)) where cor would be my previously calculated correlation coefficient, and x and y the coordinates. Obviously that displays

Hello list, I use R for microarray analysis. One procedure I use takes a large matrix, and loops through it looking for specific rows, does an operation with them, and outputs a result (single row) as a row of another matrix. The loop goes on about 25000 times. When I run the loop directly from the R console itself, it takes about 3 minutes in my computer. I'm ok with that. Now,

Dear list, is there a way to open a .zip folder so that one can extract and modify files inside and then save teh .zip folder again? thanks! Jose -- Dr. Jose I. de las Heras Email: J.delasHeras at ed.ac.uk The Wellcome Trust Centre for Cell Biology Phone: +44 (0)131 6507095 Institute for Cell & Molecular Biology Fax: +44 (0)131 6507360 Swann Building,

Hello, I hope this doesn't turn into a statistics question but here I go. I am using the nls function with a Gaussian distribution, see coding below. When I run the nls I get an error back saying that I have a linear gradient. I then, of course am unable to do anything else. The data that I am using are intensity values from some mass spectrometry data. Is there something I can

Dear All, I have a matrix with data that is not organised. I would like to go through this and extract it. Each feature has 2 vectors which express the data. I also have an index of the places where the data should be cut. eg. >class(cc) "matrix" >cc [,1] [,2] [1,] 1 26 [2,] 2 27 [3,] 3 28 [4,] 4 29 [5,] 5 30 [6,] 6 31 [7,] 7 32

Hello, Sorry to all for the lack of communication, and thanks to those with the suggestions. So I have two matrixes which are different sizes, same column number but different row number. What I would like to do is to compare A to B. In the 6 and 9th column there are ref numbers (molecular masses to be exact). I would like to check A and B by these columns. If I find that the number in A[9,x]

I have seen that the hist() function plots an histogram of the frequency but I cannot find the value of the object hist that contains theese values... how is possible to get out them? thank you very mutch best regards Manuele -- Manuele Pesenti manuele a inventati.org amicogodzilla a jabber.linux.it http://mpesenti.polito.it

Hello all Is there a way reducing the number of characters in a list so that just the left n numbers of characters is given? For example, If I have a list, listnames, which consists of 4 strings of 6 characters; >listnames [1] "item12" "item34" "item56" "item78" Is there a way to reduce this so only the 5 characters on the lefthand side are

Hello, I apologise if someone has already answered this but I searched and googled but didn't find anything. I have a matrix which gives me the similarity of each item to each other. I would like to turn this matrix into something like what they have in the graph package with the nodes and edges. http://cran.r-project.org/doc/packages/graph.pdf . However I cannot find a method to

To whom it may concern, I want to plot two or more graphics in the same window by the means of the "plot" command. To do that, I have tried the "add=TRUE" option, but this last one does not work! Do you have an hint for me please? Thank you very much for your attention. Bernard Colin Departement of Mathematics Faculty of Sciences Sherbrooke University Sherbrooke (Quebec)

Dear All, I am using the following commands to do the scatter plot of two vectors, say X and Y. plot(X,Y, col="blue") abline(a=1,b=1, col="red") abline(a=-1,b=1, col="green") I would like to split the scatter plot into 3 part with 3 different colors: (i) points lies between 2 lines, (ii) points above line 1, and (iii) points below line 2. I am struggling to do

Hi, I have been trying many of the suggested options to place a legend outside plotting area, including something like this: par(xpd=T, oma=par()$oma+c(4.5,0,1.5,0),mar=par()$mar+c(1,0,1,0) But the aspect of the four plots gets compromised when I change the margin settings. I cannot use mtext because I need to use colors for the text. I tried layout, but wouldn't let me include

Hello, I have been using scatter.smooth and been trying to format my plots and been unable to adjust the line type or color of the smooth curve. When I specify col in scatter.smooth, I can adjust the color of the scatter plot points, but the line always stays black and solid. lty has no effect. When I specify par prior to calling scatter.smooth, col will change the color of the points,

Hello again, I'm trying to purge the indexes in i.delete from frame and end up with more rows!? Please be so kind and let me know where I screw this up ... Joh > i.delete [1] 40 45 165 212 253 270 280 287 301 352 421 433 463 467 487 [16] 517 537 542 573 594 596 612 614 621 635 650 696 699 707 732 [31] 738 776 826 891 892 936 937 935 940 976

Hello all and thank you, I will try to make this as clear as I can. I have a matrix, at the top of the matrix are 4 time points, the first col describes the sample, then under each time point I have the intensity values of that sample. So : Samples 0 10 30 120 <- time A 200 300 400 1000 <- data B 100 400 200 100 C 500 400 200 1000 ^ | samples I would like to plot these however, all I