similar to: help comparing two median with R

I am sure I am opening myself up to looking stupid, but I have two samples with medians of 613.5 and 189 (difference in location of 424 compared to the difference suggested from the wilcoxon of 291.5) > wilcox.test(pipwtCount,pipwdCount, conf.int=TRUE, na.rm=TRUE) Wilcoxon rank sum test data: pipwtCount and pipwdCount W = 822, p-value = 0.01227 alternative hypothesis: true location

Dear list! I work with multiple Kruskal-Wallis test (kruskalmc, package pgirmess), which evaluates differences in medians among groups (5 groups). A result of a test is significant differences among some groups, while median values are the same for 4 groups (using tapply). Why? p.s.: number of samples in groups vary from 50 to 4900. Thanks to all, OV .

Hola Pedro. El INE cambió los ficheros de microdatos no hace mucho, aquí dejo como se haría ahora, (utilizando MicroDatosEs). Lo que cambia es la función para recodificar. http://rpubs.com/joscani/unemplrate El 15/10/14 a las #4, Carlos Ortega escribió: > Hola Pedro, > > Acabo de recordar que hace poco José Luis Cañadas (participa en esta lista) > publicó un enlace suyo a un

Hi, I tried looking through google search on whether there's a way to computer the median for each row of a nxn matrix and return the medians for each row for further computation. And also if the number of columns in the matrix are even, how could I specify which median to use? Thank you very much! -- Edward Chen [[alternative HTML version deleted]]

Hi, A client has a consumption measure on each of four products. The sample size is 75. The consumption distributions are highly skewed for each product. He would like a pairwise comparison test of the products, much like Tukey's HSD but using medians rather than means. Is there such a median comparison test in R? Thanks, Walt ________________________ Walter R. Paczkowski, Ph.D.

Por cierto data.table tiene implementadas las funciones de reshape2 melt y dcast pero mucho m?s r?pidasen ejecuci?n Obtener Outlook para Android<https://aka.ms/ghei36> ________________________________ From: R-help-es <r-help-es-bounces en r-project.org> on behalf of V?ctor Granda Garc?a <victorgrandagarcia en gmail.com> Sent: Monday, June 25, 2018 4:23:52 PM To: Fernando Reche

Pues parece que el problema si es de lme4, cuya versión 1.0-4 se publicó en septiembre de este año. En la página en cran del paquete pone "The core computational algorithms are implemented using the Eigen C++ library for numerical linear algebra and RcppEigen "glue" " . El tema es que al utilizar esta versión junto con la librería boot, el tiempo de cálculo se incrementa

Hi, I'm sure this should be simple but I can't figure it out! I want to get the median survival calculated by the survfit function and use the value rather than just be able to print it. Something like this: library(survival) data(lung) lung.byPS = survfit(Surv (time, status) ~ ph.ecog, data=lung) # lung.byPS Call: survfit(formula = Surv(time, status) ~ ph.ecog, data = lung) 1

Hello everyone, I am new to R, I have been using SAS for a while. Not surprisingly, I find R much better in graphics, which is publication ready right away. Recently, I have been trying to calculate some basic statistics using R. I have a dataset of multiple rows per subject. For example: Subject Date Factor1 Factor2 Factor3 P1 0.5 1 1 3 P1 1 3 2 5 P1 2 3 5 NA ... P2 0.5 1 6 4 P2 1 2 NA 7 P2

Hola: El 02/07/14 a las #4, Jose Luis Cañadas Reche escribió: > [...] > Ya de paso pregunto si alguien está interesado en > hacer un GIL (Grupo de Interés Local) en Andalucía.. ¿En que zona tienes interés? En Almería no hay muchos eRReros pero alguno que otro estamos. Salud y Revolución. Lobo. -- Libertad es poder elegir en cualquier momento. Ahora yo elijo GNU/Linux, para no

Hola, Ya está disponible el material que utilizamos en la reunión de ayer (videos y presentaciones) en la página del grupo: http://r-es.org/GILMadrid (Disculpas por adelantado por el video de la píldora sobre el paquete "pipeR" que por un problema técnico ha salido sin sonido). Saludos, Carlos Ortega www.qualityexcellence.es El 29 de junio de 2014, 1:44, Carlos Ortega

Does anyone can provide a code to implement least median squares regression in R (not using the lqs function or calling C functions)? Reason: teaching/learning purposes Thanks PM

loess() should be able to do robust 2D smoothing. There's no natural ordering in 2D, so defining running medians can be tricky. I seem to recall Prof. Koenker talked about some robust 2D smoothing method at useR! 2004, but can't remember if it's available in some packages. Andy From: Vladislav Petyuk > > Hi, > Are there any multidimenstional versions of runmed() and >

R gurus, On Aug 20, 2002, I asked in R-help about calculating a running 5-day median on a large matrix. Thanks to Martin Maechler <maechler@stat.math.ethz.ch> and Ray Brownrigg <Ray.Brownrigg@mcs.vuw.ac.nz> for responding. I ended up writing C code (and an R interface) to do it, which is about 1000x faster than the naive method! (72s became .09s on a 223 x 520 matrix). I added a

Dear R-users, Does anyone knows how I can order my serie of boxplots from lowest to highest median (which is much better for visualization purposes). thanks in advance, willem [[alternative HTML version deleted]]

I apologize for this post. I am new to R (two days) and I have tried and tried to calculated confidence intervals for medians. Can someone help me? Here is my data: institution1 0.21 0.16 0.32 0.69 1.15 0.9 0.87 0.87 0.73 The first four observations compose group 1 and observations 5 through 9 compose group 2. I would like to create a bootstrapped 90% confidence interval on the difference of

Muy interesante. Gracias Carlos. Estaba indagando en los orígenes, más que nada como referencia en un documento, pero dan ganas de probar la R 0.49. Creo que la primera que instalé fue R 1.2.0, en un curso que dieron en la universidad allá por el 2000. ¿y vosotros? Saludos El 13/06/13 15:12, Carlos J. Gil Bellosta escribió: > Hola, ¿qué tal? > > Richard A. Becker tiene un

Puedes probar con la función dummy del paquete dummies. Un saludo Fernando Reche Lorite Departamento de Matemáticas Universidad de Almería El 25 de junio de 2018, 15:55, Carlos J. Gil Bellosta <cgb en datanalytics.com> escribió: > ¿No te vale model.matrix? > > El lun., 25 jun. 2018 a las 15:49, Juan Abasolo (<juan.abasolo en ehu.eus>) > escribió: > > > Buenas,

Dear all, What is the right test to test whether the median of two groups are statistically significant? Is it the wilcox.test, mood.test or the ks.test? In the text book I have got there is explanation for the Wilcoxon (Mann Whitney) test which tests ob the two variable are from the same population and also ks.test! Regards, Cheba [[alternative HTML version deleted]]

Suppose you have the following code: ########## Start code########## data(Chem97, package="mlmRev") densityplot(~gcsescore | factor(score), groups=gender, data=Chem97, auto.key=TRUE, plot.points=FALSE, ref=TRUE, panel=function(x,...){ panel.densityplot(x,...) median.values <- median(x)