similar to: Row wise solving an equation

On 06/10/2020 11:00 a.m., Sorkin, John wrote: > Colleagues, > I am trying to learn to use uniroot to solve a simple linear equation. I define the function, prove the function and a call to the function works. When I try to use uniroot to solve the equation I get an error message, > Error in yfu n(x,10,20) : object 'x' not found. > > I hope someone can tell we how I can fix

Colleagues, I am trying to learn to use uniroot to solve a simple linear equation. I define the function, prove the function and a call to the function works. When I try to use uniroot to solve the equation I get an error message, Error in yfu n(x,10,20) : object 'x' not found. I hope someone can tell we how I can fix the problem

Hello all, I was going to solve (n-m)! * (n-k)! = 0.5 *n! * (n-m-k)! for m when values of n and k are provided n1<-c(10,13,18,30,60,100,500)         # values of n kx<-seq(1,7,1);                               # values of k slv2<-lapply(n1,function(n){    slv1<-lapply(kx,function(k){              lhs<-function(m)              {                

Hi , I would like to know if a R function have the same behaviour than the matlab solve function. I tried something with uniroot but I have some problems: The equation I need to solve is : exp(c0-r0)*(bb0+x)*(bb1-x)=(bb0+x+1)(bb1-x-1) So I tried this: STEP 1: my function test test <- function(x,bb0=-3,bb1=5,c0=2,r0=0) { + ((exp(c0-r0)*(bb0+x)*(bb1-x))/((bb0+x+1)(bb1-x-1))-1)} STEP 2: >

Hi, Created a zpool with 64k recordsize and enabled dedupe on it. zpool create -O recordsize=64k TestPool device1 zfs set dedup=on TestPool I copied files onto this pool over nfs from a windows client. Here is the output of zpool list Prompt:~# zpool list NAME SIZE ALLOC FREE CAP DEDUP HEALTH ALTROOT TestPool 696G 19.1G 677G 2% 1.13x ONLINE - When I ran a

Hello, I want to solve: x*(3^x)*log(4)-x*log(4/3)-(3^x)+1=0 for x. I used the following code, uniroot(function(x) x*(3^x)*log(4)-x*log(4/3)-(3^x)+1, lower = -2, upper = 2, tol = 0.001 ) While using this I am getting the following error. Can anyone please help me out. Error in uniroot(function(x) x * (3^x) * log(4) - x * log(4/3) - (3^x) + : f() values at end points not of opposite sign.

Hello all, I am not sure my original mail got through to the list (I haven''t received it back), so I attach it below. Anyhow, now I have a saved kernel crash dump of the system panicking when it tries to - I believe - deferred-release the corrupted deduped blocks which are no longer referenced by the userdata/blockpointer tree. As I previously wrote in my thread on unfixeable

Dear R forum I have following variables - EAD = 10000 LGD = 0.45 PD = 0.47 M = 3 # Equation 1 R = 0.12*(1-exp(-50*PD))/(1-exp(-50)) + 0.24*(1-(1-exp(-50*PD))/(1-exp(-50))) b = (0.11852 - 0.05478 * log(PD))^2 K = (LGD * pnorm((1 - R)^(-0.5) * qnorm(PD) + (R / (1 - R))^0.5 * qnorm(0.999)) - PD * LGD) * (1 - 1.5 * b)^(-1) * (1 + (M - 2.5) * b) RWA = K * 12.5 * EAD > RWA [1] 22845.07 #

Hi So, I have a dataset and I'm trying to solve for a parameter in an equation using the dataset. Before applying more sophisticated statistical techniques, I want to tell R to solve it out for each observation. I know I have to use a loop for it (and I have done that before, but am a bit rusty), but before I do that, I'm trying to get R to solve it for just one observation, to make sure

Hi, I'm looking to see what's the best way to solve the fact that these two utils mostly do the same thing: 1. lib/Transforms/Utils/Local.cpp : MergeBasicBlockIntoOnlyPred 2. lib/Transforms/Utils/BasicBlockUtils.cpp : MergeBlockIntoPredecessor (+cc some of the folks who touched at least one of these either originally or recently) Brief overview: 1. MergeBasicBlockIntoOnlyPred 2.

Hi!! Can anyone help me, i have problems to converge the following data with 5 nonlinears models that i evaluated. Firtly, i send my data (totalsinatipicos) that i just try to fit with the nonlinear models. Next, i have the following script where i called the data as totalsinatipicos. I made selfstarting each nonlinear model. ###Library library(NRAIA) ###Data d<-totalsinatipicos

Hi everyone, First of all, could you please CC me, I am not (yet) subscribed to this list. Now my problem: I created a test setup at my office that uses winbind to authenticate linux users to a Windows NT server (they log in with DOMAIN+username), as described in the winbindd manpage. I followed their setup completely. (at my work I am using RedHat 7.1 and the winbindd daemon found in the

Dear R Helpers, I need to find the root of following equationy=x^2+3*x-1 by substitution a random number from less to more in the certain segment.I had tried using this codef <- function (x) x^2+x-12str(xmin <- uniroot(f, c(2, 4), tol = 0.0001)) but $ f.root : num -7.85e-07not 0, and so I'm not shure it's right code and satisfactory answer. Please guide. sveta -- View this

|................. | This would *possibly* map to the files of your | driver like this: | | Long Printer Name:\ --> lp:\ |........................... | missing: should be "RAW" !! ##### | | Yeah, you're right. I've missed the RAW DDT. Now | when I complied I got the error from the subject | line. | | Sorry? I didn't

Hi there, I would like to solve a simple equation in R a^2 - a = 8.313 There is no real solution to this problem but I would like to get an approximate numerical solution. Can someone suggest how I can set this up? Thanks in advance, Diviya [[alternative HTML version deleted]]

This below is not solvable with uniroot to find "a": fn=function(a){ b=(0.7/a)-a (1/(a+b+1))-0.0025 } uniroot(fn,c(-500,500)) gives "Error in uniroot(fn, c(-500, 500)) : f() values at end points not of opposite sign" I read R-help posts and someone wrote a function: http://finzi.psych.upenn.edu/R/Rhelp02a/archive/92407.html but it is not very precise. Is there any

Hi R, I have a 100th order equation for which I need to solve the value for x. Is there a package to do this? For example my equation is: (x^100 )- (2*x^99) +(10*x^50)+.............. +(6*x ) = 4000 I have only one unknown value and that is x. How do I solve for this? BR, Shubha Shubha Karanth | Amba Research Ph +91 80 3980 8031 | Mob +91 94 4886 4510 Bangalore *

Hi all, I've a linear equation of the form: 0.95=2 ( [3+ln(x/3)]^-13  + 4 [3+2ln(x/3)]^-13  + [3+4ln(x/3)]^-13 ) and I want to solve it for x, can I do this using R? Thanks in advance. Maram. [[alternative HTML version deleted]]

Hi all, I have the following two function f1 and f2. f1 <- function(lambda,z,p1){ lambda*(p1*exp(-3*z-9/2)+(0.2-p1)*exp(4*z-8))-(1-lambda)*0.8} f2 <- function(p1,cl, cu){ 0.8*(pnorm(cl)+(1-pnorm(cu)))/(0.8*(pnorm(cl)+(1-pnorm(cu)))+p1*(pnorm(cl+3)+(1-pnorm(cu+3)))+(0.2-p1)*(pnorm(cl-4)+(1-pnorm(cu-4))))}-0.05 First fix p1 to be 0.15. (i) choose a lambda value, say lamda=0.6, (ii)

Two related questions: - given an existing pool with dedup''d data, how can I find the current size of the DDT? I presume some zdb work to find and dump the relevant object, but what specifically? - what''s the expansion ratio for the memory overhead of L2ARC entries? If I know my DDT can fit on a ssd of size X, that''s good - but how much RAM do I need