similar to: Can one set box line width within the matplot command?

Full_Name: Christophe Genolini Version: 2.8.1, but also 2.9 OS: Windows XP Submission from: (NULL) (82.225.59.146) I am using matplot with the option lend="butt", but only the first line (the black) is printed correctly : > matplot(matrix(1:9,3),type="c",lwd=10,lty=1,lend="butt") Gabor Grothendieck find the problem in matplot code: the ... is passed to plot

Hi, I was trying to get error bars in my matplot. I looked at an earlier thread, and the sample code that I made is: #------------------ library(plotrix) mat1 <- matrix(sample(1:30,10),nrow=5,ncol=2) ses <- matrix(sample(1:3,10,replace=T),nrow=5,ncol=2) vect <- seq(20,100,20) rownames(mat1) <- rownames(ses) <- vect colnames(mat1) <- colnames(ses) <- letters[1:2]

I raised this question quite some time ago but it quitly went down the river. I'll give it a second try (before keeping my modified version of matplot for ever...): matplot supports vectors (and/or character strings) for a number of arguments namely `type', `lty', `lwd', `pch', `col', `cex'. all of them act consistently in such a way that the first entries are used

Hi, I have the following script for matplot matplot(battingagg$X, battingagg[, c("HR","RBI","X2B", "BB", "R", "SB")], type="b",lty=4,lwd=2, col=1:4,xlab = "Year", ylab "(1)HRs, (2)RBIs, (3)DOUBLES,(4)BB,(5)Runs,(6) BB", pty="m",sub = "Figure 2. Plot of Selected Offensive Baseball

matplot doesn't seem to pass through options like lwd, cex, etc. quite the way I'd like. I've thought of two ways to fix this, I don't know which is better. The first is to treat lwd, cex, etc., exactly like the other options (col, lty ...) -- (these diffs are long, skip down two pages if you want to see the other way) *** matplot.orig Tue Jan 13 18:17:54 1998 ---

The Blue Book allows the 'type' argument to be used in matpoints and matlines. matlines(x, y, type="l", lty=1:5, pch=, col=1:4) R-1.0.0 does not. Thus, type="h", "b", must be invoked thru matplot( x, y, type = "h", add=TRUE) For the sake of consistency with S, it would be nice to have matlines defined as: "matlines" <-

Dear all, I want to make three plot below to only one plot together with legend, how can I do that? I have tried with matplot function but I did not succeed. Thanks for your help. Sincerelly, Jan Sabee test.five.x <- c(0.02,0.05,0.07,0.09,0.10,0.12,0.13,0.14,0.16,0.17,0.20,0.21,0.34,0.40) test.five.y <- c(18,12,17,12,3,15,1,5,1,1,3,10,15,10) plot(test.five.x, test.five.y,

example code: P = function(whichday,columns){ y = which(pvalue[,whichday]<Pvaluetest, arr.ind=TRUE) dayarb = raw_urine[y,day1_ind] daystand = raw_urine[y,columns] meandayxx = geometricmeanRow(dayarb) meandayyy = geometricmeanRow(daystand) diff = meandayyy - meandayxx for(i in 1:nrow(diff)){ if(diff[i]>0){ #diffbig = meandayxx<meandayyy x_index[i] = which(diff[i]>0) x[i] =

Hi Anupam, Haven't heard from you in a long time. Perhaps you want something like this: at_df<-read.table(text= "Income MF MF_None MF_Equity MF_Debt MF_Hybrid Bank_None Bank_Current Bank_Savings Bank_NA $10 1 3.05 29.76 31.18 36.0 46.54 24.75 25.4 3.307 $25 2 2.29 28.79 32.64 36.27 54.01 24.4 18.7 2.891 $40 3 2.24 29.51 34.31 33.94 59.1 25.0 29 13.4 $75 4 1.71 28.90 35.65 33.74

Hello, All: ????? Roughly a decade ago, I added "matplot.Date" and "matplot.POSIXct" to the "fda" package, so we could get reasonable labeling of the horizontal axis when "x" was class "Date" or "POSIXct".? I also added a local version of "matplot.default" that just changes the defaults for "xlab" and

On 2020-01-28 05:13, Martin Maechler wrote: >>>>>> Spencer Graves >>>>>> on Mon, 27 Jan 2020 23:02:28 -0600 writes: <snip> > > Still, as Abby mentioned, turning a simple function into the > default method of an S3 generic is easy to do, but comes with a > bit of cost, not just S3 dispatch which typically is negligable in > graphics,

Okay. Here is a modification that does four single line plots. at_df<-read.table(text= "Income MF MF_None MF_Equity MF_Debt MF_Hybrid Bank_None Bank_Current Bank_Savings Bank_NA $10 1 3.05 29.76 31.18 36.0 46.54 24.75 25.4 3.307 $25 2 2.29 28.79 32.64 36.27 54.01 24.4 18.7 2.891 $40 3 2.24 29.51 34.31 33.94 59.1 25.0 29 13.4 $75 4 1.71 28.90 35.65 33.74 62.17 24.61 11.48 1.746

Does R provide a function analogous to LS() or str() that reports the storage space, on disk or in memory, required by objects? Ben Fairbank

????? Thanks for the reply. On 2020-01-27 19:56, Abby Spurdle wrote: > Maybe I'm missing something really obvious here, but I was unable to > create a matrix out of POSIXct object(s). > Perhaps that deserves a separate discussion...? ????? Can you provide an example? ????? The standard matplot application that concerns me is with matplot(x, y, ...) where x has class Date or

Hi, Matplot works with x being Date class but not POSIXt. Here is the example with R version 2.5.0 Under development (unstable) (2006-12-06 r40129) Example: x <- Sys.Date() - c(1:10) y <- cbind(1:10, 10:1) class(x) ## [1] "Date" matplot(x, y) x <- strptime(as.character(x), format="%Y-%m-%d") ## [1] "POSIXt" "POSIXlt" matplot(x, y) Error in

Thanks, Pikal and Jim. Yes, it has been a long time Jim. I hope you have been well. Pikal, thanks. Your solution may be close to what I want. I did not know that I was posting in HTML. I just copied the data from Excel and posted in the email in Gmail. The data is still in Excel, because I have not yet figured out what is a good way to organize it in R. I am posting it again below as text. These

Hi list, I know that points involving NAs are not plotted in 'matplot', but when I plot them as lines, I still want the lines to connect all the points (i.e. not broken where there are NAs).? Please see the example below.? How can I achieve this in 'matplot'?? If I can't, any good alternatives so I don't have to use 'plot' + 'lines' and loop through all the

Hi all, I'm building a plot of the values in tmeant (below) against positions 1 to 5, using matplot. tmeant looks like this: case1 case2 pos1 861.8466 818.5909 pos2 961.2841 976.3466 pos3 878.6080 1262.8523 pos4 950.8011 1129.6080 pos5 968.1080 1063.3920 I also have lower (object tl) and upper (object tu) bounds on the confidence intervals as follows: tl: pos1

Hi, I apologise in advance for the na?ve question. I have large matrices that I want to plot. I currently use color2D.matplot. However, these matrices contain many values of no interest (i.e. where there is no data, the figure -999 is automatically displayed). Is there any way of removing these from the matrices to be plotted by matplot? An obvious possibility is setting them all to 0, but that

Hi, I finally came up with a nice colored matrixplot, using the color2D.matplot function of the plotrix package. But I can't assign xtics and ytics to this plot. I made sure that the matrix has correct colnames() and rownames(). Here's what I do: a=matrix(1:16, 4, 4) colnames(a) <- c("X1", "X2", "X3", X4) rownames(a) <- c("Y1",