similar to: chronological scatterplots

Hi all. I have defined a plot thus: par(mar=c(5,5,4,5),las=1, xpd=NA) plot(Day, Ym1Imp, ylim=c(0,100), type="b", bty="l", main="Ym1 Expression", cex=1.3, xaxt="n", yaxt="n") #plot implant data axis(side=1, at=c(0,1,3,5,7,10,14,21), labels=c(0,1,3,5,7,10,14,21)) # label x axis mtext("Day", side =1, at=10, line=3, cex=1.2) # title x

Hello everyone, I have a data generated in a way similar to the following library(chron);library(zoo) date<- seq(as.Date("1990-01-01"),, as.Date("2000-12-31"), by = 1) obs<- zoo(rnorm(length(date), mean = 10, sd = 2.5), order.by = date) monthly<- function(date) as.Date(as.yearmon(Date)) result<- data.frame ( Date = obs = aggregate(obs, monthly, sum)) Now, I want

I'm quite new to R. I have a time series of annual state population estimates from census.gov, and I'd like to get a time series of monthly estimates, by a nonlinear interpolation. How can I do this in R? Thanks! [[alternative HTML version deleted]]

Dear Gabor, Thanks for your reply. however: > tail(DJd) ^DJI.Close 2010-04-01 10927.07 2010-04-05 10973.55 2010-04-06 10969.99 2010-04-07 10897.52 2010-04-08 10927.07 *2010-04-09 10997.35* > tail(ag) 2009-11-30 10344.84 2009-12-31 10428.05 2010-01-31 10067.33 2010-02-28 10325.26 2010-03-31 10856.63 *2010-04-30 10997.35 * It seems the script "makes up"

Hello, I'm trying to develop a box plot of time series data to look at the range in the data values over the entire period of record. My data initially starts out as a list of hourly data, and then I've been using this code to make this data into the final ts array. # Read in the station list stn.list <- read.csv("/home/kbennett/fews/stnlist3", as.is=T, header=F) # Read in

HI, R-Users: I got a questions. have been struggling so long time.... I have this data: > m1$Year_Month 201009 201010 201011 201101 201102 > min(m1$Year_Month) 201009 I want to calculate the following two answers, how do I program it? > difference in Month????? [1] 0 1 2 4 5 >difference in Days????? 0 31 61 .... Thank you in advance!!! Tammy [[alternative

Hello, If I have a character string like d <- c("1990m3", "1992m8") #March 1990 and Aug 1992 what is the easiest way to convert it into any standard date form; for example, d <- c("01/03/1990", "01/08/1992") I looked at as.Date but it doesn't seem to address my problem as I have an "m" stuck in the middle of my character string

Is it easy or difficult to label the abscissa of a scatter graph as 1/trueScaleValue at that point? -- View this message in context: http://r.789695.n4.nabble.com/labeling-abscissa-using-a-function-of-the-plotted-scale-tp4678075.html Sent from the R help mailing list archive at Nabble.com.

dear All, i'm trying to calculate the number of Mondays, Tuesdays, etc that each month within a date range has. I have time series data that spans 60 months and i want to calculate the number of Mondays, Tuesdays, Wed, etc of each month. (I want to control for weekly seasonality but my data is monthly). Is there an easy way to to this in R? or is there a package i could use? i did

Hello, I would like to implement a "turn-of-the-month' trading strategy in R. Given a daily series of stock market return data as a zoo object, the strategy would go long (buy) four trading days before the end of the month, and sell the third trading day of the following month. How can I select these days, particularly the fourth day before and the third day after the turn of the

First of all, thanks to everyone who answers these questions - it's most helpful. I'm new to R and despite searching have not found an example of what I want to do (there are some good beginner's guides and a lot of complex plots, but I haven't found this). I would like to plot two variables against the same abscissa values. They have different scales. I've found how to make

I have the following timeseries "tab" ===================================== > str(tab) mts [1:23, 1:2] 79.5 89.1 84.9 75.7 72.8 ... - attr(*, "dimnames")=List of 2 ..$ : NULL ..$ : chr [1:2] "Ipex...I" "Omel...E" - attr(*, "tsp")= num [1:3] 2006 2008 12 - attr(*, "class")= chr [1:2] "mts" "ts" > tab

Hello, I have a date in the format Year-Month Name (e.g. 1990-January) and R classes it as a character. I want to convert this character into a date format, but when I try as.Date(1990-January, "%Y-%B"), I get back NA. The function strptime also gives me NA back. Thanks. [[alternative HTML version deleted]]

Hi-- I have three columns in an input file: MONTH QUARTER YEAR 2012-07 2012-3 2012 2001-07 2001-3 2001 2002-01 2002-1 2002 I want to make output like so: MONTH QUARTER YEAR 07 3 2012 07 3 2001 01 1 2002 I was having some trouble getting the regular expression to work. I think it should

Readers, I have looked at various documents hosted on the web site; I couldn't find anything on interpolation. So I started r and accessed the help (help.start()). (by the way is it possible to configure r to open help in opera instead of firefox?) Initially I read the help for the akima package but couldn't understand it. Next I tried the asplines package help. I tried to copy the

New user here. My goal is pull daily averages from a long dataset. I've been working with some code I got from this list from https://stat.ethz.ch/pipermail/r-help/2009-March/191302.html The code how I have been using it is as follows: library(zoo) library(chron) DB<-read.table("/Users/me/Desktop/R/data.csv", sep=",", header=TRUE, as.is =TRUE) z<-zoo(LTER6$temp,

Dear list, I would like to study the dynamics of functions using R (instead of mathematica e.g.), i.e. the behavior of points under iteration of a function. So I tried (in vain) writing a function myfunction <- function(f,n,x){...} in order to compute f^{n}(x), f^{n}(x) being the function f composed with itself n-1 times. n is a natural number, and the argument x is the abscissa of the point I

Suppose I do a psychology experiment in which each of six subjects does several items in each of five fixed conditions, A, B, C, D, and E. The items are randomized separately for each subject, so I can ignore order. All I want to know is whether the five conditions differ. The data look like this. Each row is a subject, and each number is the score in the given condition. A B C D E 4 1

>From owner-r-help at stat.math.ethz.ch Tue Jan 29 06:13:23 2002 >I've got a data-frame contining variables i columns named after the >specified subject and with data which represents time of observation. > >What I would like to do is to get a plot with observation time on the >ordinate and subject on the abscissa -- kind of a "at what time did I >observe the

Dear all, I've got a problem with the function atan2. For a couple of coordinates x and y, This function returns the angle between the vector of coordinates (x, y) and the abscissa axis, i.e. it is the same as atan(y/x) (as indicated on the help page). If we consider the vector with coordinates x = 0 and y = 0, we have the following result: > atan(0/0) [1] NaN This is expected.