Displaying 20 results from an estimated 1000 matches similar to: "Scoping issue?"
2006 Jul 04
1
[Fwd: formatting using the write statement]
>I have a series of write statements because
>i am writing to a file
>where the characters strings are the column names of a dataframe
>and the numbers are the elements in a particular row.
>So, a file might look like
>
>AAA 2.1
>BB 3.1
>AHLZ 0.2
>
>and it would be named "rowname".mls.
>
>so, each time i get to a new row, i create a new file and
2006 Aug 08
3
Pairwise n for large correlation tables?
Hello,
I'm using a very large data set (n > 100,000 for 7 columns), for which I'm
pretty happy dealing with pairwise-deleted correlations to populate my
correlation table. E.g.,
a <- cor(cbind(col1, col2, col3),use="pairwise.complete.obs")
...however, I am interested in the number of cases used to compute each
cell of the correlation table. I am unable to find such a
2007 Jun 06
2
lookup in CSV recipe
I await Luke''s node settings implementation with interest. At the
moment however, I have this sort of ugliness:
$site = $hostname ? {
fred => "opsera",
barney => "bedrock",
default => "unknown site",
...
}
So I''ve knocked up this little function to use CSV files instead. Now
I can just do:
$site =
2011 May 18
4
Loop stopping after 1 iteration
Hi all,
This is a very basic question, but I just can't figure out why R is handling
a loop I'm writing the way it is.
Here is the script I have written:
grid_2_series<-function(gage_handle,data_type,filename)
series_name<-paste(gage_handle,data_type,sep="_")
data_grid<-read.table(file=paste(filename,".txt",sep=""))
2009 Jan 22
2
"latex" in Hmisc: cell formating
Hi list,
Could you explain the error I see here? Thanks!
## I'm using R 2.8.0 on WinXP, Hmisc_3.4-3
> table1 <- matrix(10, 180,7)
> cell.format <- matrix("", ncol=7, nrow=180)
> cell.format[c(seq(3,180,6),seq(4,180,6)),] <- "color{red}"
> cell.format[c(seq(5,180,6),seq(6,180,6)),] <- "color{green}"
>
> latex(table1,
2011 Apr 04
1
moving mean and moving variance functions
Hello
Lets say as an example I have a dataframe with the following attributes:
rownum(1:405), colnum(1:287), year(2000:2009), daily(rownum x colnum x year)
and foragePotential (0:1, by 0.01). The data is actually stored in a netcdf
file and I'm trying to provide a conceptual version of the data.
Ok. I need to calculate a moving mean and a moving variance for each cell on
the following
2011 Jun 23
2
Confidence interval from resampling
Dear R gurus,
I have the following code, but I still not know how to estimate and extract
confidence intervals (95%CI) from resampling.
Thanks!
~Adriana
#data
penta<-c(770,729,640,486,450,410,400,340,306,283,278,260,253,242,240,229,201,198,190,186,180,170,168,151,150,148,147,125,117,110,107,104,85,83,80,74,70,66,54,46,45,43,40,38,10)
x<-log(penta+1)
plot(ecdf(x),
2006 Aug 02
5
Finding the position of a variable in a data.frame
Simple problem but I don't see the answer. I'm trying
to clean up some data
I have 120 columns in a data.frame. I have one value
in a column named "blaw" that I want to change. How do
I find the coordinates. I can find the row by doing a
subset on the data.frame but how do I find out here
"blaw " is in columns without manually counting them
or converting names(Df) to a
2001 Jun 14
1
expand.model.frame() fails when subset is specified (PR#979)
Full_Name: Gregory R. Warnes
Version: 1.2.0, 1.2.3
OS: SunOS gsun124 5.8 Generic_108528-03 sun4u sparc SUNW,Ultra-5_10
Submission from: (NULL) (12.18.36.49)
When using expand.model.frame on a model that specifies a subset selection,
an error is generated on the variable used for the subset selection.
Example:
> data <- data.frame(x=1:10,y=1:10,z=1:10,m=1:10)
> model <- lm( y ~
2001 Jun 14
1
expand.model.frame() fails when subset is specified (PR# 979)
> Thanks. This is also present in the current pre-1.3.0. Your patch
> looks correct, but I wonder if the default for "enclos"
> should not be
> environment(formula(model)) rather than parent.frame() as it is now?
>
> (And wouldn't it be better named "envir"?)
Peter,
I was merely making an incremental improvement, your suggestions provide
1999 Jun 29
3
S v. 5
Does R, or will R, be integrating the changes to the Chambers/Lucent S
language under their version 5.0? If not already, then when?
John Thaden
Little Rock, Arkansas, USA
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2006 Jul 02
1
sparse matrix tools
Dear R-Help list:
I'm using the Matrix library to operate on 600 X ~5000 element
unsymmetrical sparse arrays. So far, so good, but if I find I need more
speed or functionality, how hard would it be to utilize other sparse
matrix toolsets from within R, say MUMPS, PARDISO or UMFPACK, that do
not have explicit R interfaces? More information on these is available
here
2017 Dec 04
0
Dynamic reference, right-hand side of function
The generic rule is that R is not a macro language, so looping of names of things gets awkward. It is usually easier to use compound objects like lists and iterate over them. E.g.
datanames <- paste0("aa_", 2000:2007)
datalist <- lapply(datanames, get)
names(datalist) <- datanames
col1 <- lapply(datalist, "[[", 1)
colnum <- lapply(col1, as.numeric)
(The 2nd
2008 Jul 10
2
Position in a vector of the last value > n
This shouldn't be hard, but it's just not
coming to me:
Given a vector, e.g.,
v <- c(20, 134, 45, 20, 24, 500, 20, 20, 20)
how can I get the index of the last value in
the vector having a value greater than n, in
this case, greater than 20? I'm looking for
an efficient function I can use on very large
matrices, as the FUN argument in the apply()
command.
Confidentiality
2008 Oct 07
3
vectorized sub, gsub, grep, etc.
R pattern-matching and replacement functions are
vectorized: they can operate on vectors of targets.
However, they can only use one pattern and replacement.
Here is code to apply a different pattern and replacement
for every target. My question: can it be done better?
sub2 <- function(pattern, replacement, x) {
len <- length(x)
if (length(pattern) == 1)
pattern <-
2017 Dec 04
3
Dynamic reference, right-hand side of function
Hi!
Thanks for the replies!
I understand people more accustomed to R doesn't like looping much, and that thinking about loops is something I do since I worked with Stata a lot. The syntax from Peter Dalgaard was really clever, and I learned a lot from it, even though it didn't solve my problem (I guess it wasn't very well explained). My problem was basically that I have a data matrix
2006 Jul 09
1
package:Matrix handling of data with identical indices
In the Matrix package v. 0.995-11 I see that the dgTMatrix
Class for compressed, sparse, triplet-form matrices handles
Identically indexed data instances by summing their values,
e.g.,
library(Matrix)
(Mt <- new("dgTMatrix",
i = as.integer(c(0,0,1,1,4)),
j = as.integer(c(0,1,2,2,4)),
x = as.double(1:5),
Dim = as.integer(c(5,5))))
## 5 x 5 sparse Matrix of class
2006 Jul 09
1
package:Matrix handling of data with identical indices
In the Matrix package v. 0.995-11 I see that the dgTMatrix
Class for compressed, sparse, triplet-form matrices handles
Identically indexed data instances by summing their values,
e.g.,
library(Matrix)
(Mt <- new("dgTMatrix",
i = as.integer(c(0,0,1,1,4)),
j = as.integer(c(0,1,2,2,4)),
x = as.double(1:5),
Dim = as.integer(c(5,5))))
## 5 x 5 sparse Matrix of class
2002 Nov 02
1
problem with expand.model.frame
Dear R list members,
I'm encountering a problem with expand.model.frame(): Suppose that I define
the following simple function (meant
just to illustrate the problem):
> fun <- function(model){
+ expand.model.frame(model, all.vars(formula(model)))
+ }
>
and I have the following model, created with an explicit data argument:
> mod
Call:
2007 Feb 20
1
baseline fitters
I am pretty pleased with baselines I fit to chromatograms using the
runquantile() function in caTools(v1.6) when its probs parameter is
set to 0.2 and its k parameter to ~1/20th of n (e.g., k ~ 225 for n ~
4500, where n is time series length). This ignores occasional low-
side outliers, and, after baseline subtraction, I can re-adjust any
negative values to zero.
But runquantile's