similar to: format of summary.lm for 2-way ANOVA

Hi everyone, every comment about this: http://xforce.iss.net/xforce/xfdb/16264 Didn't find any hint or patch on http://www.xfree86.org/security/. Best regards Konrad Heuer (kheuer2@gwdg.de) ____ ___ _______ GWDG / __/______ ___ / _ )/ __/ _ \ Am Fassberg / _// __/ -_) -_) _ |\ \/ // / 37077 Goettingen /_/ /_/

Well i haven't seen anyone talk about this, so i was just wondering if FreeBSD is affected by this. http://xforce.iss.net/xforce/xfdb/6508

I may be doing this wrong! but I have a function which I have simplified a lot below. I want to pass some 'field names' of a data-frame to the function for it to then do some manipulation of. Here's my code: #build a simple dataset mydataset = data.frame (

I tried to post this a few times last week and it seems to have got stuck somehow so I'm trying from a different email in the hope that works. If somehow this has appeared on the list 20 tiems and I never saw any of them I apologize ;-) I'm basically an R-newbie. But I am VERY computer literate. But this has me stumped... All the examples for using the rmeta package to create a

FYI, for those who may not have heard about this one. I got this from another mailing list as is evident by the headers. >Delivered-To: alert-out-link@iss.net >Delivered-To: alert-out@iss.net >Date: Wed, 9 Jun 1999 16:16:41 -0400 (EDT) >From: X-Force <xforce@iss.net> >To: alert@iss.net >cc: X-Force <xforce@iss.net> >Subject: ISSalert: ISS Security Advisory: KDE

Dear members of this list, I'd like to count missing values using the aggregate function. Something like this: count_nas <- function(arg1) { return(sum(is.na(arg1))) } aggregate(cbind(var1, var2, var3) ~ subject + time, data = mydataset, count_nas) It's not working: I end up with a matrix containing zeros, although there are missings in the data frame. I'd highly

Hi list, I am using the capscale function in vegan_2.0-7 to do a constrained principal coordinates analysis, and I kept getting the following error message: Error in Y.r[, oo, drop = FALSE] : subscript out of bounds I googled but I couldn't find an answer. Could anyone tell me why this error msg and what to do? Here is the command I used:

Recent proftpd security vulnerability release FYI. Ports has latest patched proftpd distribution. -- Jez http://www.munk.nu/ -------------- next part -------------- An embedded message was scrubbed... From: Dave Ahmad <da@securityfocus.com> Subject: ISS Security Brief: ProFTPD ASCII File Remote Compromise Vulnerability (fwd) Date: Tue, 23 Sep 2003 10:25:54 -0600 (MDT) Size: 4588 Url:

Hallo, in /sys/conf/NOTES there is a comment | # Use real implementations of the aio_* system calls. There are numerous | # stability and security issues in the current aio code that make it | # unsuitable for inclusion on machines with untrusted local users. | options VFS_AIO Are there still problems with aio? I only found http://xforce.iss.net/xforce/xfdb/7693, but no advisory or

We're being bitten an Outlook bug [1,2] that is triggered by a NUL character in a message being sent through POP3. I see that dovecot's imap implementation converts 0x00 to 0x80, but this conversion is not done for POP3. Would it be possible to add an option to do this mapping for POP3 as well? Matt [1] http://xforce.iss.net/xforce/xfdb/15859 [2]

Dear R users, I was wondering how I can replace the values of a vector with the values from in another vector in the same row For example, how can I replace the value of x below with NA when the value of Z in the same row is NA? x <-1:20 z<- c(11, 15, 17, 2, 18, 6, 7, NA, 12, 10,21, 25, 27, 12, 28, 16,17, NA, 12, 10) Many thanks Mintewab ________________________________________ Fr?n:

Hello all, I have a peculiar and particular bug that I stumbled across with ggplot2. I cannot seem to replicate it with anything other than my specific data set. Here is the problem: - when I try to plot a histogram, allowing for ggplot2 to decide the binwidths itself, I get the following error: - stat_bin: binwidth defaulted to range/30. Use 'binwidth = x' to

Hey R-users, I think I followed the steps but still couldn't figure this out.. I am creating a personal package and I want to include several datasets in the package. I created a subdirectory 'data' in the package, save a dataset 'test.rda' there, built the package, checked it, installed it. Then I loaded the package and tried load(test), data(test), attach(test), none of them

-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 ============================================================================= FreeBSD-SA-05:05.cvs Security Advisory The FreeBSD Project Topic: Multiple vulnerabilities in CVS Category: contrib Module: cvs Announced:

-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 ============================================================================= FreeBSD-SA-05:05.cvs Security Advisory The FreeBSD Project Topic: Multiple vulnerabilities in CVS Category: contrib Module: cvs Announced:

Dear R-helpers, In my dataset I have two continuous variable (A and B) and one factor. I'm investigating the regression between the two variables usign the command lm(A ~ B, ...) but now I want to know the regression coefficient (r2) of A vs. B for every factors. I know that I can obtain this information with excel, but the factor have 68 levels...maybe [r] have a useful command. Thanks,

? stato filtrato un testo allegato il cui set di caratteri non era indicato... Nome: non disponibile Url: https://stat.ethz.ch/pipermail/r-help/attachments/20070104/6e94ce08/attachment.pl

I am new on R, so I have a maybe naive question: if I have many large data.frames and I use only one or two per session, what's the best way? If all are stored in the actual .Rdata, the system gets slow. On the other hand, I wouldn't like to make a separate package for the data. Should I save it with save() and then remove it with rm() ? Could I reload it then? Thanks for suggestions

Dear all, I'm trying to use the lattice barchart function to obtain a bar plot of a variable for different values of two factors. The thing I'm trying to do is something like this: > barchart(MyVar ~ season | place, data=mydataset) My problem is that the column MyVar has some negative values and I would like them to be represented as bars stacking down from zero instead of what

Dear R-friends, I use optim(par=c(mystartingpoints), fn=myloglikelihoodfunction, gr=NULL, method=c("L-BFGS-B"), ## I would like to do not use any bounds control=list(trace=6, ## just to see what it's going on maxit=c(20000)), ## to be sure the it doesn't stop reaching the max iterations