similar to: random binary trees in R

Displaying 20 results from an estimated 30000 matches similar to: "random binary trees in R"

2010 Dec 14
1
rpart - how to estimate the “meaningful” predictors for an outcome (in classification trees)
Hi dear R-help memebers, When building a CART model (specifically classification tree) using rpart, it is sometimes obvious that there are variables (X's) that are meaningful for predicting some of the outcome (y) variables - while other predictors are relevant for other outcome variables (y's only). *How can it be estimated, which explanatory variable is "used" for which of
2009 Dec 17
1
Random Number Generation in a Loop
Dear R helpers   I am having following data   Name           Numbers A                  25 B                   3  C                  13 A                   5  B                   7 C                   0 A                   2 B                 10 C                   9   CONDITIONS   If Name is A, min_val = 1.05, max_val = 1.30 If Name is B, min_val = 1.30, max_val = 1.60 If Name is C, min_val =
2018 Mar 04
3
Random Seed Location
On Mon, Feb 26, 2018 at 3:25 PM, Gary Black <gwblack001 at sbcglobal.net> wrote: (Sorry to be a bit slow responding.) You have not supplied a complete example, which would be good in this case because what you are suggesting could be a serious bug in R or a package. Serious journals require reproducibility these days. For example, JSS is very clear on this point. To your question >
2008 Jul 28
2
Help with a loop
HI: I need ideas on how to make this code shorter (maybe with a second loop?). The code as it is works, but in this case I only have 14 samples, but it will become insane with more, so I need a way to make it more automatic. The problem is that the output from ts1, ts2, and so on is a vector with more than one value, so I do not know how to solve this. Thanks Prenewbie The code is the
2018 Feb 26
3
Random Seed Location
Hi all, For some odd reason when running na?ve bayes, k-NN, etc., I get slightly different results (e.g., error rates, classification probabilities) from run to run even though I am using the same random seed. Nothing else (input-wise) is changing, but my results are somewhat different from run to run. The only randomness should be in the partitioning, and I have set the seed before this
2018 Feb 27
0
Random Seed Location
In case you don't get an answer from someone more knowledgeable: 1. I don't know. 2. But it is possible that other packages that are loaded after set.seed() fool with the RNG. 3. So I would call set.seed just before you invoke each random number generation to be safe. Cheers, Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking
2007 Feb 20
1
contextstack overflow
Hello! I written several implementations in R of R?my's algorithm for generating random ordered strictly binary trees on 2n+1 vertices. One implementation involves manufacturing character strings like: "X <- list(0,list(0,0))" for the case n=2. If I perform the following two steps: cmd <- "X <- list(0,list(0,0))" eval(parse(text=cmd)) then X becomes a true
2018 Mar 04
0
Random Seed Location
Thank you, everybody, who replied! I appreciate your valuable advise! I will move the location of the set.seed() command to after all packages have been installed and loaded. Best regards, Gary Sent from my iPad > On Mar 4, 2018, at 12:18 PM, Paul Gilbert <pgilbert902 at gmail.com> wrote: > > On Mon, Feb 26, 2018 at 3:25 PM, Gary Black <gwblack001 at sbcglobal.net> >
2006 Mar 08
1
Want to fit random intercept in logistic regression (testing lmer and glmmML)
Greetings. Here is sample code, with some comments. It shows how I can simulate data and estimate glm with binomial family when there is no individual level random error, but when I add random error into the linear predictor, I have a difficult time getting reasonable estimates of the model parameters or the variance component. There are no clusters here, just individual level responses, so
2010 Aug 18
5
ifelse command
hello people, I want to make a biased dice using the sample() function and print out the results after n number of runs, I've successfully generated the dice using the following command: mydie2<-function(n=1000,y=NULL,...){ for(i in 1:n){ x<-sample(1:6,n,replace=TRUE,prob=c(1,1,2,3,2,1)/10) x=runif(n) if(x<=1/10){y[i]=1} else if(x<=2/10){y[i]=2} else if(x<=4/10){y[i]=3} else
2018 Mar 04
2
Random Seed Location
The following helps identify when .GlobalEnv$.Random.seed has changed: rng_tracker <- local({ last <- .GlobalEnv$.Random.seed function(...) { curr <- .GlobalEnv$.Random.seed if (!identical(curr, last)) { warning(".Random.seed changed") last <<- curr } TRUE } }) addTaskCallback(rng_tracker, name = "RNG tracker") EXAMPLE: >
2012 Jan 19
3
Establishing groups using something other than ifelse()
Hello all, This is one of those "Is there a better way to do this questions". Say I have a dataframe (df) with a grouping variable (z). This is my base data. Now I know that there is a higher order level of grouping that exist for my group variable. So what I want to do is create a new column that express that higher order level of grouping based on values in the sub-group (z in this
2013 Feb 02
1
Why replacement has length zero? And How can I fix it?
Hi for the loop section runif needs curved brackets Try IAP <-NA for (i in 1:Sample.Size){ if (DataSet$SES[i]>0) { IAP[i] <- ifelse(runif(1)>0.75, 1, 0) # High SES, higher chance to be in Treatment # } else { IAP[i] <- ifelse(runif(1)<=0.25, 1, 0) # Low SES, lower chance to be in Treatment # } } # End loop # IAP IAP zjiaqi19880219 wrote > Hi,
2012 Nov 27
2
Stuck trying to modify a function
Hi, I have the following data: Path_Number <- 5 ID.Path <- c(1:Path_Number) # Make vector of ID's. No_of_X <- sample(50:550, length(ID.Path), replace=TRUE) # X <- split(sample(1:10000, sum(No_of_X), replace=TRUE), rep(ID.Path, No_of_X)) Y <- lapply(X,function(x) sample(x, round(runif(1, min=10, max=50)))) X and Y are both lists, and I've made the following function to
2003 Feb 05
2
Minor races in sftp-server.c
There are a couple of races in sftp-server as this patch shows: --- sftp-server.c 28 Jan 2003 18:06:53 -0000 1.1.1.2 +++ sftp-server.c 5 Feb 2003 19:19:42 -0000 @@ -832,19 +832,22 @@ process_rename(void) { u_int32_t id; - struct stat st; char *oldpath, *newpath; - int ret, status = SSH2_FX_FAILURE; + int status; id = get_int(); oldpath = get_string(NULL); newpath = get_string(NULL);
2008 Jan 29
1
for loop help
Hi, I have written the following code which works fine step<-5 numSim<-15 N<-double(numSim) A<-double(numSim) F<-double(numSim) M<-double(numSim) genx<-double(numSim) for (i in 1:numSim) { N[i]<-20 PN<-(runif(N[i], 0, 1)) A[i]<-sum(ifelse(PN>0.2, 1, 0)) PF<- runif((A[i]*0.5), 0, 1) F[i]<-sum(ifelse(PF>0.2, 1, 0)) PM<-
2013 Oct 18
1
crr question‏ in library(cmprsk)
Hi all I do not understand why I am getting the following error message. Can anybody help me with this? Thanks in advance. install.packages("cmprsk") library(cmprsk) result1 <-crr(ftime, fstatus, cov1, failcode=1, cencode=0 ) one.pout1 = predict(result1,cov1,X=cbind(1,one.z1,one.z2)) predict.crr(result1,cov1,X=cbind(1,one.z1,one.z2)) Error: could not find function
2009 Nov 23
2
categorisation of continuous variables in R
Dear all, I'm looking for a function comparable to switch, to categorize a continuous variable in a few levels. Off course that can be done with a series of ifelse statements, but that looks rather clumsy. I looked at switch, but couldn't figure out how to use it for this. I guess that's not possible, as it only works with characters or integers, not with intervals. Basically,
2018 Mar 04
0
Random Seed Location
On 04/03/2018 5:54 PM, Henrik Bengtsson wrote: > The following helps identify when .GlobalEnv$.Random.seed has changed: > > rng_tracker <- local({ > last <- .GlobalEnv$.Random.seed > function(...) { > curr <- .GlobalEnv$.Random.seed > if (!identical(curr, last)) { > warning(".Random.seed changed") > last <<- curr
2018 Mar 08
3
add single points to a level plot
Hi all, I'm trying to add single points with known coordinates to a level plot, but could not find the proper answer. I got to know that layer() function is good for this, but I don't know which package is related to this function. The source is here: https://stackoverflow.com/questions/28597149/add-xy-points-to-raster-map-generated-by-levelplot but my question is a little different as I