similar to: strange algorithm needed

Hi, Just a quick query - if I'm creating a function to produce a number of histograms per page of output (one per column from a matrix), how can I pass the column name of the matrix into the title (or indeed to form part of the x-axis label)? TIA, Laura Laura Quinn Institute of Atmospheric Science School of Earth and Environment University of Leeds Leeds LS2 9JT tel: +44 113 343 1596 fax:

I have the code below which gives me what I want for temp based on logvec but I was wondering if there was a shorter way ( i.e : a one liner ) without having to initialize temp to zeros. This is purely for learning purposes. Thanks. logvec <- c(TRUE,FALSE,FALSE,TRUE,FALSE,FALSE,TRUE,FALSE) temp<-numeric(length(invec)) temp[invec]<-which(invec) temp [1] 1 0 0 4 0 0 7 0 obviously, the

I am constructing plots ( regular not lattice ) and my initial command is par(mar=c(3,4,2,2), mfcol=c(5,2)) and then I create 10 plots on the page. It looks great but the plots on the page go in the order 1 6 2 7 3 8 4 9 5 10 Where the numbers denote decile breakdowns. Is there an easy way to make them go from left to right so 1 2 3 4 5 6 7 8 9 10 I could try

does anyone know how to put a column name on a zoo object. I think achim and gabor are off line or they have gotten totally tired of me an decided to ignore me ( which is totalyy understandable ). logbidask<-log((aggfxdata[,"bid"] + aggfxdata[,"ask"])/2.0) logbidask doesn't have a name and I can't figure out how to get one on it ? aggfxdata is a zoo object.

Dear all R users, I have a small doubt about panel data analysis. My basic understanding on Panel data is a type of data that is collected over time and subjects. Vector Autoregressive Model (VAR) model used on this type of data. Therefore can I say that, one of statistical tools used for analysis of panel data is VAR model? If you clarify my doubt I will be very grateful. Thanks and regards,

I have two numeric vectors each of length 17 and each is named the exact same way. so obsnum ppppp ppppm pppmp . dot dot dot...... temp1 is 1417 52 63 85 obsnum ppppp ppppm pppmp . dot dot dot...... temp2 is 1213 41 50 97 what i want to have is a resultant matrix with 2 rows and 16 columns where the 16

Hi all, My question is not really urgent. I can write a loop and solve the problem. But I know that I'll be in a similar situation many more times so it would be useful to find out the answer Is there a fast way to perform linear fit to all the columns of a matrix? (or in the one dimension of a multi-dimensional array.) I'm talking about many single linear fits, not about a multiple fit.

Hi guys, It would be great if you could help me with this one... I'm looking to create a script to convert a matrix of species abundance e.g: <http://r.789695.n4.nabble.com/file/n4643978/species_matrix.jpg> into two vectors e.g: <http://r.789695.n4.nabble.com/file/n4643978/communitylist.jpg> ---------------- If you feel there is no easy answer to this and that it would be

I have index ( of a vector ) values of say tempin<-c(1 31 61 91 121 all the way upto 1411) What I want is a function that takes in a number say, x = 5, and gives me an new vector of tempout<-1 6 31 36 91 96 121 126 .......... 1411 1416 This can't be so hard but I can't get it and I've honestly tried. Obviously, tempin + 5 gives me the missing values but I

Dear R experts, I wonder how can one input a string variable in multiple lines in a R script. I've seen solution to the command line continuation in the non-string situation (just continute at the new line). However, that doesn't work for strings because the new line character, "\n", is included in the resultant string. For example, if I type the following in a script:

I just noticed something by accident with R syntax that I'm sure is correct but I don't understand it. If I have a simple numeric vector x and I subscript it, it seems that I can then subscript a second time with TRUE or FALSE, sort of like a 2 dimensional array in C. Does someone know if this is documented somewhere Because it's neat but I never knew it existed. To me it seems like a

Hi! I've made great progress in my R programming, but I am again stuck on a beginner's problem. I would like to start R with a command line that loads a file, and if possible, executes a function. Can anyone give me an example of how to do this? For example, in lisp, I would say: $ lisp -load toto.lisp -eval '(do-something $PORT)' to load the file "toto.lisp", then

Greetings, I'm learning R and I'm stuck on a basic concept: how to specify a logical condition once and then perform multiple transformations under that condition. The program below is simplified to demonstrate the goal. Its results are exactly what I want, but I would like to check the logical state of gender only once and create both (or any number of) scores at once.

i'm doing a bar plot and there are 16 column variables. is there a way to make the variable names go down instead of across when you do the barplot ? because the names are so long, the barplot just shows 3 names and leaves the rest out. if i could rotate the names 90 degrees, it would probably fit a lot more. or maybe i can use space to make the horizontal width longer ? I looed up ?barlot but

ng, I have a matrix (x) with binary content. Each row of the matrix holds exactly one 1, and the rest of the row is zeros. The thing is that I need to 'collapse' the matrix to one column where each row holds the original column index of the 1's (y). Sometimes, the matrix is quite large, so I have a perfomance problem. x <- matrix(c(1,0,0, 0,0,1, 0,1,0, 0,0,1, 0,1,0,

Hello R-ologists, Imagine you have a list "list" like so: >list [[1]] [1] "IPI00776145.1" "IPI00776187.1" [[2]] [1] "Something" "IPI00807764.1" "IPI00807887.1" [[3]] [1] "IPI00807764.1" [[4]] [1] "Somethingelse" What I need to achieve is a filtered list "list2" like so: >list2 [[1]] [1]

How can I extract only the time component from an POSIXlt object? For example if I try the following it still returns both the date and time... >as.POSIXlt(tr.date[1]) [1] "2010-10-18 21:46:53" >as.POSIXlt(tr.date[1],"%H:%M:%S") [1] "2010-10-18 21:46:53" round and trunc don't help... is there an "as.Time" equivalent to as.Date ? Thanks,

Dear all, I think that my question is very simple but I failed to solve it. I have a list which elements are matrices like this: >mylist [[1]] [,1] [,2] [,3] [1,] 1 3 5 [2,] 2 4 6 [[2]] [,1] [,2] [,3] [1,] 7 9 11 [2,] 8 10 12 I'd like to create a matrix M<-mylist[[1]]+mylist[[2]] [,1] [,2] [,3] [1,] 8 12 16 [2,] 10 14 18

I have the code below and it works fine if I print the xyplot but if I take the print out, then I just get a blank pdf. The same holds if I just send the plot to the console without the print ( I get nothing ). My question is whether this is always the case with xyplot or is there something wrong with my settings ? I am on linux ( redhat ) and using R.2.5.0. Thanks. load("stocks.dat")

I have a vector of character strings such as mainnames<-c("CAD","AUD") and another vector say checknames<-c("CAD.l1","AUD.l1","JPY.l1","EUR.l1","CAD.l2","AUD.l2","JPY .l2","EUR.l2") I want a new vector of character strings that is just