similar to: symbolic matrix elements...

While I recently received some very helpful files and email from Kevin Hendricks for compiling with ATLAS, thought I'd first have a stab at ACML. Having problems, which I suspect are trivial to solve: 1. machine is running RHEL 4, meaning, it uses gcc 3.4.5 out of the box, and g77. In my experience, over-riding RHEL's choice, and manually upgrading to gcc 4.x.x (and, as a consequence

Well, that's a bit like driving from Boston to New York by way of Chicago. See ?structure test <- list(a=1,b=2,c=3) new <- c(4,5,6) test.new <- structure(as.list(new), names=names(test)) test.new $a [1] 4 $b [1] 5 $c [1] 6 Cheers, Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka

Hi I?aki and Evan, Thank you for checking this. My version of CentOS was installed by the Federal Government, and there is disk encryption. I am able to regularly update CentOS. Anyway, the problem seems to be on my end. For me, the code just hangs... my R scripts never run if they are too long. So, I created that script, which fails on my computer. I have a personal computer with Ubuntu,

Please, see spot's comment in the BZ I linked in my previous comment. The thing is not that it can't be done (you could install a newer devtoolset, v8 or v9, build R and use it), the thing is that it cannot be distributed in EPEL, because we're allowed to build against a devtoolset, but not depend on it, so the distribution would be broken (you could not install packages unless you

Apart from the fact that the statement "such that t1+t2+t3+t4=2970 (as it must)" is not correct, the LP can be implemented as follows: library(lpSolve) LHS <- rbind( c(0,0,0,0, 1, 0, 0,0), c(1,0,0,0,-1, 1, 0,0), c(0,1,0,0, 0,-1, 1,0), c(0,0,1,0, 0, 0,-1,1), cbind(-diag(4),diag(4)), c(0,0,0,0,0,1,0,0), c(0,0,0,0,0,0,1,0), c(0,0,0,0,0,0,0,1) ) RHS <-

> t(t(NN)/lambda) [,1] [,2] [,3] [1,] 0.5 0.6666667 0.75 [2,] 2.0 1.6666667 1.50 > R matrices are column-based. MATLAB matrices are row-based. > On Feb 27, 2024, at 14:54, Evan Cooch <evan.cooch at gmail.com> wrote: > > So, trying to convert a very long, somewhat technical bit of lin alg > MATLAB code to R. Most of it working, but raninto a stumbling block

Solved it: test <- list(a=1,b=2,c=3) new <- c(4,5,6) hold <- as.list(new) updated_test <- replace(test,c(1:3),hold) $a [1] 4 $b [1] 5 $c [1] 6 mean.parms <- as.list(mean.parms) mm.parms <- replace(far.parms,c(1:length(far.parms)),mean.parms) On 9/22/2017 10:34 AM, Evan Cooch wrote: > Suppose I have the following: > > test <- list(a=1,b=2,c=3) > > I

> On Jun 21, 2017, at 9:11 AM, Evan Cooch <evan.cooch at gmail.com> wrote: > > Suppose I have the following sort of dataframe, where each column name has a common structure: prefix, followed by a number (for this example, col1, col2, col3 and col4): > > d = data.frame( col1=runif(10), col2=runif(10), col3=runif(10),col4=runif(10)) > > What I haven't been able to

Sure -- thanks -- only took me 3-4 attempts to get aperm to work (as opposed to really thinking hard about how it works ;-) On 9/28/2017 11:55 AM, Duncan Murdoch wrote: > On 28/09/2017 9:10 AM, Evan Cooch wrote: >> Thanks for both the mapply and array approaches! However, although >> intended to generate the same result, they don't: >> >> # mapply approach

Thanks very much. I had more or less reached the same conclusions -- I was just about to rebuild RPMs for source for zlib, etc, and update those, and try again, but I've had mixed success in doing that in past. Its easy enough to roll back to 3.2.5 (which compiles perfectly against all the CentOS 6.x.x libs), but 3.30 plays nice with a few other things I work with. Hence my interest in

Why anything but sweep? The fundamental data type in Matlab is a matrix... they don't have vectors, they have Nx1 matrices and 1xM matrices. Vectors don't have any concept of "row" vs. "column". Straight division is always elementwise with recycling as needed, and matrices are really vectors in row-major order: 1 2 3 4 5 6 is really 1 4 2 5 3 6 and when you do

On 28/09/2017 9:10 AM, Evan Cooch wrote: > Thanks for both the mapply and array approaches! However, although > intended to generate the same result, they don't: > > # mapply approach > > n = 3 > sa <- rnorm(n,0.8,0.1) > so <- rnorm(n,0.5,0.1) > m <- rnorm(n,1.2,0.1) > mats = mapply(function(sa1, so1, m1) > matrix(c(0,sa1*m1,so1,sa1),2,2,byrow=T),

So, trying to convert a very long, somewhat technical bit of lin alg MATLAB code to R. Most of it working, but raninto a stumbling block that is probaably simple enough for someone to explain. Basically, trying to 'line up' MATLAB results from an element-wise division of a matrix by a vector with R output. Here is a simplified version of the MATLAB code I'm translating: NN = [1,

Hi all, Can anyone tell me why this line of code works in FF but not IE?? function stuff(id){ record_id=$(id); record_id.innerHTML = "foo"; } I get a ''Runtime Error''. -- ----------------------- Iggy Sandejas Web Developer 0419 485 252 D-Frag Solutions http://www.dfrag.com.au -----------------------

Suppose I have the following sort of dataframe, where each column name has a common structure: prefix, followed by a number (for this example, col1, col2, col3 and col4): d = data.frame( col1=runif(10), col2=runif(10), col3=runif(10),col4=runif(10)) What I haven't been able to suss out is how to efficiently 'extract/manipulate/play with' columns from the data frame, making use

Hi all, Firstly is there a way to search the archives? Second I was wondering if there is a way to implement a scrollbar on the list that occurs when you use autocomplete. I have some lists that are very long so I would like to shorten them but still have all the options. Regards, ----------------------- Iggy Sandejas D-Frag Solutions http://www.dfrag.com.au -----------------------

The use of aperm is unnecessary if you call array() properly. ms <- array(c(rep(0, 5),so,sa*m,sa), c(5, 2, 2)) -- Sent from my phone. Please excuse my brevity. On September 28, 2017 9:10:26 AM PDT, Evan Cooch <evan.cooch at gmail.com> wrote: >Sure -- thanks -- only took me 3-4 attempts to get aperm to work (as >opposed to really thinking hard about how it works ;-) > >On

Suppose I have the following: test <- list(a=1,b=2,c=3) I also have a vector (or list, or something else...) with new numbers new <- c(4,5,6) What I'm trying to figure out is how to take the list, and update the numbers from {1,2,3} to {4,5,6} So, in the end,I want the 'update' test list to look like (a=4,a=5,a=6) I tried a bunch of obvious things I know about

Question for 'experts' in LP using R (using the lpSolve package, say) -- which does not apply to me for the sort of problem I describe below. I've run any number of LP's using lpSolve in R, but all of them to date have objective and constraint functions that both contain the same variables. This lets you set up a LHS and RHS matrix/vector that are symmetrical. But, for a

Greetings - After 20+ years of using SAS, for a variety of reasons, I'm using [R] for a bunch of things - while I'm getting a pretty good a handling [R] for script programming, and statistical analysis, I'm struggling with 'pulling data into [R]'. For reasons beyond my control, a number of the files I get sent to 'work with' are in Dbase format (*.dbf). For