similar to: Help on estimated variance in lme4

Hello! I would like to setup ssh on solaris7/x86 to use PAM authentication by pam_radius_auth. Neither openssh-1.2.2 nor ssh-1.2.27 with ssh-1.2.27.pam.patch work with it - I've got message: debug: RSA authentication for test failed. On remete radius server I've information in logs that authentication was accepted(!). When I connect by telnet all is right. My /etc/pam.conf: login

Dear R users and developers, Would any of you be interested in giving a lecture about R and/or R use cases at the following free software conference that takes place in Amiens, France, next summer? We already had a talk on R last year by Yves Croissant (http://2006.rmll.info/theme_26?lang=en) but are still open to any submission this year. We expect some talks this year (to be confirmed) about

Why is 19 March, 1947 a little longer than one day? x <- as.POSIXct("1947-04-16") julian(x, origin = as.POSIXct("1947-03-20")) Time difference of 27 days julian(x, origin = as.POSIXct("1947-03-19")) Time difference of 28.04167 days > julian(x, origin = as.POSIXct("1947-03-18")) Time difference of 29.04167 days I am running R-1.7.1 compiled on

I need help making a windows batch script work in wine. I a total newbie to wine. I copied the script from a windows machine where it runs correctly. The first line is supposed to discover the name of the DVD in drive D. The %vole% is being converted into the letter I. --This is in the cmd file. for /F "tokens=6" %%I in ( 'vol d: ^| find /i "volume in"' ) DO (SET

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Hello, I have a data frame with a factor column, which uniquely identifies the observations in the data frame and it looks like this: sample1_condition1_place1 sample2_condition1_place1 sample3_condition1_place1 . . . sample3_condition3_place3 I want to turn it into three separate factor columns "sample", "condition" and "place". This is what I did so far: #

Full_Name: Jerome Lemaitre Version: 2.6.0 OS: Windows XP Submission from: (NULL) (132.203.202.117) Hello, I have recently downloaded the 2.6.0 version of R and I experience troubles that never happened to me with previous versions. I open an R session with an R shortcut in "My documents/Analyses". However, when I want to open R files such script using "File/open script" R

I am attempting to model data with the following variables: timepoint - n=48, monthly over 4 years hospital - n=3 opsn1 - no of outcomes total.patients skillmixpc - skill mix percentage nurse.hours.per.day Aims To determine if skillmix affects rate (i.e. no.of.outcomes/total.patients). To determine if nurse.hours.per.day affects rate. To determine if rates vary between

What is the easiest way to extract a value from a 'mer' object from glmer? The first I need is the trtpair Std.Dev. which in this case is 0.17542? I've managed to get the fixed effects numbers from summary(fednmaout)@coeffs but no luck with the Random effects stuff. TIA Jim > fednmaout Linear mixed model fit by REML Formula: lor ~ as.factor(t2) + as.factor(t3) + (1 |

On 11/26/2017 08:42 PM, jim holtman wrote: > try this: > > ########################################## > > library(dplyr) > > input <- tribble( > ~station, ~from, ~to, ~record, > "07EA001" , 1960 , 1960 , "QMS", > "07EA001" , 1961 , 1970 , "QMC", > "07EA001" , 1971 , 1971 ,

Or with the Bioconductor IRanges package: df <- with(input, DataFrame(station, year=IRanges(from, to), record)) expand(df, "year") DataFrame with 24 rows and 3 columns station year record <character> <integer> <character> 1 07EA001 1960 QMS 2 07EA001 1961 QMC 3 07EA001 1962 QMC 4

try this: ########################################## library(dplyr) input <- tribble( ~station, ~from, ~to, ~record, "07EA001" , 1960 , 1960 , "QMS", "07EA001" , 1961 , 1970 , "QMC", "07EA001" , 1971 , 1971 , "QMM", "07EA001" , 1972 , 1976 , "QMC", "07EA001" , 1977 ,

int he example below I run facter looking for the fact "sp_serial_number". as you can see, the command facter sp_serial_number returns nothing, but the fact is there and is returned when just running facter and grepping for the fact. Some fact seem to work and others do not. any ideas? marcuspro:~ allan$ facter --version 1.5.7 marcuspro:~ allan$ facter sp_serial_number marcuspro:~

Hi, A benchmarking study with an additional (data.table-based) solution. Enjoy! ;) Cheers, Denes -------------------------- ## packages ########################## library(dplyr) library(data.table) library(IRanges) library(microbenchmark) ## prepare example dataset ########### ## use Bert's example, with 2000 stations instead of 2 d_df <- data.frame( station =

On 11/29/2017 04:15 PM, T?th D?nes wrote: > Hi, > > A benchmarking study with an additional (data.table-based) solution. I don't think speed is the right benchmark (I do agree that correctness is!). For the R-help list, maybe something about least specialized R knowledge required would be appropriate? I'd say there were some 'hard' solutions -- Michael (deep

Hi Martin, On 11/29/2017 10:46 PM, Martin Morgan wrote: > On 11/29/2017 04:15 PM, T?th D?nes wrote: >> Hi, >> >> A benchmarking study with an additional (data.table-based) solution. > > I don't think speed is the right benchmark (I do agree that correctness > is!). Well, agree, and sorry for the wording. It was really just an exercise and not a full

> On 9 Nov 2017, at 14:58, PIKAL Petr <petr.pikal at precheza.cz> wrote: > > Hi > > Thanks for working example. > > you could use split/ lapply approach, however it is probably not much better than dplyr method. > > sapply(split(mydf, mydf$type), function(speed, n_vehicles) sum(mydf$speed*mydf$n_vehicles)/sum(mydf$n_vehicles)) > gives you averages > The

Hi Thanks for working example. you could use split/ lapply approach, however it is probably not much better than dplyr method. sapply(split(mydf, mydf$type), function(speed, n_vehicles) sum(mydf$speed*mydf$n_vehicles)/sum(mydf$n_vehicles)) gives you averages aggregate(mydf$n_vehicles, list(mydf$type), sum)$x gives you sums Cheers Petr > -----Original Message----- > From: R-help