similar to: Colour-coding intervals on a line

Hi, how can I create a rainbow gradient in R? For example, let's say I have a plot of y = x...and I want the plot to go from red -> orange -> yellow -> green -> blue -> etc. Right now, I know how to do something like go from red to blue, using the plotrix library: library(plotrix) redToBlue <-

Dear R users, I'm interested in a combination of a scatterplot and an image graph. I have two large vectors. Because in the scatterplot some areas are sparsely and others densely populated, I want to see the points, and I also want their color to be changed based on their density (similar to a heat map). Is there a function that can do that? Thank you, b.

Dear all I am using color2D.maplot to map some matrixes to plot. everything works fine. It seems that when my matrix contains only the same value color2D.maplot returns the following error: color2D.matplot(estimatedsr,redrange=c(0,1),greenrange=c(0,.5),bluerange=c(0,.5),xlab="x",ylab="y",main=sprintf('Estimated'),show.legend=TRUE,show.values=TRUE) Error in rgb(reds,

Hi, I do not have much R experience just the basics, so please excuse any obvious questions. I would like to create bubble plot that have Categorical data on the x and y axis and then the diameter if the bubble the value related to x and y. Attached to the email is a pic of what I would like to do. I do hope someone can help me. -- Regards/Groete/Mit freundlichen Gr??en/recuerdos/meilleures

Considering the R function/plot shown below, I wonder whether it is possible to do the following changes: (1) Change the color of each point to be picked from list of colors according to its z-value. (The range should be from blue (z=0) to red (z=1).) The grid should then be omitted. [I have seen "terrain.colors", but don't know how to use it for this purpose.] (2) Add two lines to

Dear All! How can I cope with overlapping or covered labels (covered by labels from other data points) in plots? Martina Renninger [[alternative HTML version deleted]]

Hi, all. I'm using hist() to obtain a vector of break values in an interval. I then want to be able to identify which cell any value from another vector falls in. E.g. applying > breaks [1] -3.5 -3.0 -2.5 -2.0 -1.5 -1.0 -0.5 0.0 0.5 1.0 1.5 2.0 to > x [1] -3.74519666 -0.38183630 -1.22884247 -0.20971824 -0.30533939 -0.36271207 [7] -2.27513499 -2.23688653 -1.98827155 -1.48666274

Hi all, plotrix 3.2 has arrived. The reason for this announcement is that there have been a couple of major rewrites. The barNest family of functions has had an overhaul that began as a fix for an apparently trivial bug that caused problems with empty subcategories. So far, testing has not found anything that will break code written for the former version. color.scale will now convert

Dear All, Sorry to bother I want to write a function in R using if Say I have a dataset x, if x[i]<0, then x[i]=x[i], if x[i]>0, then x[i]=0 for example, x=-3:3, then using the function, x becomes [-3,-2,-1,0,0,0,0] I write the codes as follows, gjr=function(x) {lena=length(x) for(i in 1:lenx) if (x[i]<0) return (x[i]) if (x[i]>0) return (0) x} but then, doing gjr(x? it only

With the introduction of indirect segments we can receive requests with a number of segments bigger than the maximum number of allowed iovecs in a bios, so make sure that blkback doesn't try to allocate a bios with more iovecs than BIO_MAX_PAGES Signed-off-by: Roger Pau Monné <roger.pau@citrix.com> Cc: Konrad Rzeszutek Wilk <konrad.wilk@oracle.com> ---

Dear list, I just tried to do the same thing, and did not find anything on a weighted qqplot. My weights are actually counts (positive integers). Here is a modification of qqplot, following Duncan Murdoch's suggestion. Any feedback would be welcome! Thanks, Jean-Christophe weighted.qqplot <- function (x, y, plot.it = TRUE, xlab = deparse(substitute(x)), ylab = deparse(substitute(y)),

I am currently developing a blkfront.c for a custom OS over Xen 3.0.2-2. Typical I/O is working, however, I ran into an error while testing a corner case. On standard I/O, where { 1 <= nr_segments < BLKIF_MAX_SEGMENTS_PER_REQUEST } blkif_int()''s bret->status returns BLKIF_RSP_OKAY. Yet when { nr_segments == 0 } blkif_int''s bret->status is non-zero. (Yes

Hi dear all, the following code is correct. but I want to use non-numeric x-axis, for example if I replace time <- seq(0,72,6) by month <- c("Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec","Pag") Ofcourse I use factor(month) instead of

Buenas tardes, Solicito por favor ayuda con este error: Error: OutOfMemoryError (Java): Java heap space Estoy trabajando con matrices de grandes dimensiones y el programa no logra completarse porque dice le falta memoria. Gracias [unnamed] Sara Suarez Zapata Estudiante en práctica - Unidad Gestion Bolsa de Energia. Tel: (574) 380 61 18 Correo: sara.suarez en

Hi! We have run a linear regression model with 3 explanatory variables and get the output below. Does anyone know what type of test the anova model below does and why we get so different result in terms of significant variables by the two tables? Thanks! /Sara > summary(model) Call: lm(formula = log(HOBU) ~ Vole1 + Volelag + Year) Residuals: Min 1Q Median 3Q Max

Hello! Could anyone please tell me how should I include R in a text section for References? Regards, Sara Mouro [[alternative HTML version deleted]]

Actually what I meant in my original loop, that there is a dependency between every two consecutive iterations. So, how the loop vectorizer says 'we can vectorize this loop'? for(int k=20;k<50;k++) dataY[k] = dataY[k-1]; From: Henrique Santos [mailto:henrique.nazare.santos at gmail.com] Sent: Sunday, November 03, 2013 4:28 PM To: Sara Elshobaky Cc: <llvmdev at

Hey there I have two vectors: y<- c(0.4, 0.0, 0.2, -0.2, -0.6, 0.2, 0.0, 0.0, 0.4, 0.4, 0.2) In the vector y, I want to access (in the order given) all of the values in between each of the specific values of given. I understand subsetting with y[i], but how do I get to ssomewhere in between -0.6 and 0.2? Thanks Eric Jennings matheric at myuw.net

Dear all I can not understand how to install the package lpsolve_1.1.9.zip I have read the FAQ and the help pages carefully, but it still not clear for me. I have tried the following (and obtained the respective error messages): >install.packages("c:/ProgramFiles/R/rw2011/library/lpSolve_1.1.9",destdir=" c:/ProgramFiles/R/rw2011/library/lpSolve") Mensagem de aviso:

Dear all, I have one Model (M3) fitted using the lme package, and I have checked the correlation structure of within-group errors using plot(ACF (M3,maxLag=10),alpha=0.05) But now I am not sure how to interpret this plot for the empirical autocorrelation function. The problem is that I am used to see/interpret diagrams in which all the autocorrelation Lags, except lag-1, are inside the