similar to: apologies if you aready received this ?

>Hi Everyone : As I mentioned earlier, I am taking a lot >of Splus code and turning into R and I've run into >another stumbling block that I have not been >able to figure out. > >I did plotting in a loop when I was using Splus on unix >and the way I made the plots stop so I could >lookat them as they got plotted ( there are hundreds >if not thousands getting plotted

Hi All : I am attempting tomove a large amount of code from Splus to R and I was hoping that there was an equivalent in R of the Splus functions timeSeq and timeDate ? I did an RSiteSearch but nothing came up ? If the equivalent functions are part of some package, that's fine. Thanks a lot. Mark

Hi : I have old Splus code that I am trying to turn into R ( I am using windows Xp and R 2.20 ) and I am getting a warning from one of my statements because the behavior of R is different from Splus. below, tempdata is a matrix of numbers and I have the following command which basically runs through the columns and returns the minimum index of the column where an NA occurs.

I have a large R program that I am constantly running over and over again. At the beginning of this program, I create a hige matrix and a huge dataframe but these are constant. What I mean by constant is that, if I run the program over later, I really should just use the old matrix and dataframe ( if they exist ) that were created in a previous run so that the program doesn't have to spend

hi everyone : i'm not sure if my previous mail about this got sent. i was typing and erroneosuyl hit a button and lost what i was typing. anyway, i have the code below ( it works ) in which i run through the rows of a dataframe, taking out the first two fields which are characters strings ( with some extra spacing so i yuse gsub) and appending these character strings to a list so that i can

i have two vectors of numbers x and y and of course i can do the standard scatterplot plot(x,y) and it looks fine. But, I was hoping there was a way to do the scatterplot so that each point plotted is a number where the number represents the index in the dataset. so, if it was x[3] and y[3], then the point would be a 3 or if it was x[4] and y[4], then the point would be a 4 etc. i doubt this is

uugh : i promise that this will be my last question of the day. i hate to constantly bother this group but it takes me time to get familar with all of these functions, tricks and and manipulations. i appreciate everyone's patience. i used too splus a lot but i've gotten rusty. i have a matrix of say 200 rows and 600 columns. i have a function "getprofit" that takes two series

I got a vector of probabilities like, probs<-c(0.001,0.5,0.02,1,.....) Is there any nice and easy builtin function to get the number of occurences within some specified probabality range. Like with 2% it would be occur[1] = sum(probs[probs>0&probs<0.02]) occur[2] = sum(probs[probs>0.02&probs<0.04]) ... occur[50] =sum(probs[probs>0.09] & probs<1) (If it was a

Hi Everyone: I've been going through Alan Lenarcic's package tutorial but when I did R CMD SHLIB Xdemo.cc Xdemo_main.cc -o Xdemo.dll I got the following error: XDemo_res.rc:15:38: warning: missing terminating " character XDemo_res.rc:23:34: warning: missing terminating ' character c:\mark\research\Rtools\MinGW\bin\windres.exe: XDemo_res.rc:16: syntax error

Hello, Below is some example code that should reproduce an error I'm encountering while trying to create a tiff plot with two subplots. If I run just the following bit of code through the R GUI the result is what I'd like to have appear in the saved tiff image: x<-seq(0:20) y<-c(1,1,2,2,3,4,5,4,3,6,7,1,1,2,2,3,4,5,4,3,6) plot(x,y,type="l",las=1,ylim=c(0,12))

I am very much a novice with regular expressions and I have spent a decent amount of time trying to do the following and I can't get it. i have variables that are of type character but they have number characters at the end. for example : "AAL123" "XELB245" "A247" I want a command that gives me just gives me the letter characters for each one. the letter

If I have the string below. does someone know a regular expression to just get the "BLC.NYSE". I bought the O'Reilley book and read it when I can and I study the solutions on the list but I'm still not self sufficient with these things. Thanks. stock<-"/opt/limsrv/mark/research/equity/projects/testDL/stock_data/fhdb/US/BLC.NYSE"

I have a question related to scoping. Suppose we have 2 functions: f1 = function(i){i = 1} f2 = function(n){ i = length(n) f1(i) } In other words, I would like i=1 regardless of n. Is this possible without having f1 in the body of f2? Thanks in advance!

Dear all, I'm trying to process a log file which logs the date, the username and the computer number accessed. The table looks like this: >table.users          Date UserName Machine 1  2008-11-25     John     641 2  2008-11-25    Clive     611 3  2008-11-25   Jeremy     641 4  2008-11-25     Walt     722 5  2008-11-25     Tony     645 6  2008-11-26     Tony     645 7  2008-11-26    

I have a file that I thought would be fairly simple to read in using read.table but I am having problems ( as usual ). each line of the file is of the form ( just 20 lines or so ) financials XXX, YYY, ZZZ automobiles RTR, ABC, TGH so the first field in the line is the industry and the other fields ( seperated by commas ) in the line are stock identifiers of stocks in that industry. note that

----- Original Message ----- From: MARK LEEDS To: r-help-request@stat.math.ethz.ch Sent: Sunday, May 14, 2006 9:49 PM Subject: simple .bat question but i can't find out where to post. my apologiesfor posting a non R question I have what I think is a simple .bat question but i can't figure out where to post it ( i spent 6 hours looking through tutorials on batch commands but i

>From: markleeds at verizon.net >Date: Thu Jul 06 13:16:42 CDT 2006 >To: markleeds at verizon.net >Subject: as.data.frame question >hi all : as a result of an lapply command, >i get the following output. > > >$AAA > 000106 000107 000108 > 5.5 6.5 3.0 > >$BBB > 000106 000107 000108 > 4 5 6 > >$CCC

--- the forwarded message follows --- -------------- next part -------------- An embedded message was scrubbed... From: "Cecilia Carmo" <cecilia.carmo at ua.pt> Subject: Re: [R] subset dataframe/list Date: Mon, 01 Jun 2009 21:33:15 +0100 Size: 3657 URL: <https://stat.ethz.ch/pipermail/r-help/attachments/20090601/921f7638/attachment-0002.mht>

Hello, I'm trying to superimpose a line plot onto a histogram but I'm not having any luck. I've attached the dataset. What I did was: > hist(data,freq=F) Now I'm trying to superimpose the following points with a line connecting them onto the histogram: x y 100 0.535665393824959 200 0.212744329736556 300 0.0844933242968584 400 0.0335572838043417 500

Hi : I am using R 2.20 on windows XP and I have a REALLY long read.table statement because the col.names argument has 440 character strings in it. ( I use python to write R code ). When I run the read.table statement inside an R program ( the R program only consists of the read.table statement ) using the source command in an interactive R session, everything works fine. But, if I take the same