similar to: Function as.Date leading to error implying that strptime requires 3 arguments

On Thu, 11 Jan 2001 stephen@anc.ed.ac.uk wrote: > Hi, > > The help file for strptime has the following code which doesn't work > for me: > > ## read in date info in format `ddmmmyyyy' > x <- c("1jan1960", "2jan1960", "31mar1960", "30jul1960") > z <- strptime(x, "%d%b%Y") > > z > [1]

Hello, strptime is still not working correctly in my computer (Windows 98 and R Version 1.3.1) From x <- c("1jan1960", "2jan1960", "31mar1960", "30jul1960") strptime(x, "%d%b%Y") I obtain [1] "NA" "NA" "NA" "NA" while x <- c("01011960", "02011960", "3131960",

Hi everybody When I try example of strptime x <- c("1jan1960", "2jan1960", "31mar1960", "30jul1960") z <- strptime(x, "%d%b%Y") The result is; > z [1] NA NA NA NA I have got the same result with complete form of month but not with numeric form. Any idea? [[alternative HTML version deleted]]

Hi everyone, I have been trying to compute numbers of days between two dates as follows: > x <- c("1jan1960", "2jan1960", "31mar1960", "30jul1960") > z <- format(x, "%d%b%Y") > ex <- c("1jan1961", "15jan1960", "21mar1975", "10jul1981") > ez <- format(ex, "%d%b%Y") > ez-z

Full_Name: Bill Hutchison Version: 2.2.1 OS: Windows XP Submission from: (NULL) (69.158.121.13) example(strptime) produces the following error: Error in strptime(x, "%d%b%Y") : 2 arguments passed to 'strptime' which requires 3 This error occurs wherever strptime is used. It does not occur in 2.2.0

Hello, How do you change the language of the labels in a graph. In this example, I want to get French labels by changing Sys.putenv. I should get "Mai" instead of "May". Sys.putenv(LANGUAGE="fr") x <- as.Date(c("1jan1960", "2jan1960", "31mar1960", "30jul1960"), "%d%b%Y") y <-1:4 plot(x,y) Regards, Pierre

Dear friends. Library Date was updated recently. I do not remember having seen the error below until now ? The plot title is made appropriately but the error message may be annoying, right ? I use version 1.1 on windows 98. library(date) tt <- as.date(c("1jan1960", "2jan1960", "31mar1960", "30jul1960")) plot(tt,c(1:4),main="How's that ?")

Dear friends. Library Date was updated recently. I do not remember having seen the error below until now ? The plot title is made appropriately but the error message may be annoying, right ? I use version 1.1 on windows 98. library(date) tt <- as.date(c("1jan1960", "2jan1960", "31mar1960", "30jul1960")) plot(tt,c(1:4),main="How's that ?")

Hi, The help file for strptime has the following code which doesn't work for me: ## read in date info in format `ddmmmyyyy' x <- c("1jan1960", "2jan1960", "31mar1960", "30jul1960") z <- strptime(x, "%d%b%Y") > z [1] "NA" "NA" "NA" "NA" Do these work for other people?

Hi. I'm sure this is a complete green-horn question. I apologize. I'm trying to use as.Date *exactly* as shown on p. 194 of the manual (code fragment and error message pasted below). Is there some kind of "include" or "import" statement that I need to issue? Thank you very much for saving what remains of my hair. > x <- c("1jan1960",

Hi, I'm experiencing a problem with strptime. (R 1.9.1 on a Win2000 machine) I have a large list containing 6 columns and 161800 rows. One column contains dates that I want to convert in order to compare the different dates. Some dates work just fine while others become NA. I don't see any difference between the dates. I've attached an example from my code. Hope this explains my

I'm trying to add a set of reference lines to a multipanel xyplot xyplot(y ~ x | Visit, panel = function(x, y, ...){ panel.xyplot(x, y, ...) abline(v = c(0.5, 1)) }) However, the reference lines are different for different visits. For example, for the first 2 visits, I'd like vertical lines at x = 0.5 and 1. For visits 3 and four, I'd like vertical lines at x = 1 and 1.5. I can

This is definitely obscure but we had a unit test that called .Internal(strptime, "1942/01/01", %Y/%m/%d") with timezone (TZ) set to CET. In R-3.1.3 that returned "1942-01-01 CEST" which, paradoxically, is correct as they evidently did strange things in Germany during the war period. Java also returns the same. However, R-3.2.4 returns "1942-01-01 CET".

On 3/12/16 12:33 AM, peter dalgaard wrote: >> On 12 Mar 2016, at 00:05 , Mick Jordan <mick.jordan at oracle.com> wrote: >> >> This is definitely obscure but we had a unit test that called .Internal(strptime, "1942/01/01", %Y/%m/%d") with timezone (TZ) set to CET. > Umm, that doesn't even parse. And fixing the typo, it doesn't run: > >>

>>>>> peter dalgaard <pdalgd at gmail.com> >>>>> on Sat, 12 Mar 2016 19:11:40 +0100 writes: > OK, .Internal is not necessary to reproduce oddity in this area. I also see things like (notice 1980) >> strptime(paste0(sample(1900:1999,80,replace=TRUE),"/01/01"), "%Y/%m/%d", tz="CET") ............... >

Hi, I am having trouble extracting just the year or the month or the day from a date such as 5/7/2007 which is May 7th 2007. Is there any particular function to extract just the year from this format? When I am reading this data from a text file it is reading it correctly in the same format but does not acknowlede it as date but as a factor. If I try as.date(5/7/2007) then it is converting it to

Hi This code should explain what I'm trying to do > strptime("30-Jan-08", "%d-%b-%y") [1] "2008-01-30" > > format(strptime("30-Jan-08", "%d-%b-%y") , "%b-%y") [1] "Jan-08" > > strptime(format(strptime("30-Jan-08", "%d-%b-%y") , "%b-%y") , "%b-%y") [1] NA I have a

Hi All In trying to correlate some tide gauge data I need to deal with varying timezones. From the documentation on strptime, it seemed that the tz variable might have some effect on the conversion, but I'm not seeing an effect. > strptime("20061201 1:02 PST",format="%Y%m%d %H:%M",tz="PST")+0 [1] "2006-12-01 01:02:00 EST" >

Hi, I am having a trouble parsing dates using strptime() that I get in the format of year and week number. The data looks like this "201127" which means year 2011 and week 27. I would like to graph this using ggplot but then I get a gap between 201054 and 201101 so I thought I would just easily convert it. I tried to use strptime and as.Date and the format string of %Y%W but it seems

I never understood that why is the value returned by as.date function in the library(survival) never matches with the description given in the help file: Following is the extract from ?as.date Description: Converts any of the following character forms to a Julian date: 8/31/56, 8-31-1956, 31 8 56, 083156, 31Aug56, or August 31 1956. Usage: as.date(x, order = "mdy", ...)