similar to: Repeat dataframe

Hi R users: Thank you very much for you help, you are very kind. I am again asking for your help to make a function that returns the numbers of elements of each category given in another vector. I mean, I have a vector "x" with several elements (most of them more that once) and other vector "y" with the elements that I want to count in the first vector (is not a exhaustive

Doctor in veterinary medecine I have a degree in veterinary epidemiology I would ask if someone can perform Monte Carlo simulation with R. Thanks in advance. Dr Kane Ismaila i_kane at hotmail.com -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info",

Is names(model1$coef) what you're looking for? -----Original Message----- From: Kenneth Cabrera [mailto:krcabrer at epm.net.co] Sent: 29 November 2002 10:36 Cc: R-help at stat.math.ethz.ch Subject: [R] Obtaining the variable names of a glm object Hi, R users! Suppose I make a model like this:

Hi R users: I want to know how can I easily sort in descending order a whole data frame by one or several variables. Thank you very much for your help. Kenneth Cabrera krcabrer at perseus.unalmed.edu.co krcabrer at epm.net.co Universidad Nacional de Colombia, Sede Medell?n -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read

Hello, I am new to using R and I am having problems get boot() to work properly. Here is what I am trying to do: I have statistic called "cs". cs takes a data matrix (154 x 5) and calculates 12 different scores for me. cs outputs the data as a vector (12 x 1). cs doesn't really use weights, per se, however I have included this as one of the 2 arguments cs can take. I try

Maybe this is dumb, but I seem to be having problems reading a file saved in R v. 0.99 into R 0.90.1 (in a different machine). I did >save(test1, file="test1.RData") then I tried to read that data file in R 0.90.1: >load("test1.RData") Error in load("test1.RData") : restore file corrupted -- no data loaded More info: - both machines are running Linux;

Hi R users: What is the difference between in the computation of the diag of the "hat" matrix in: "lm.influence" and the matrix operations with "solve()" and "t()"? I mean, this is my X matrix x1 x2 x3 x4 x5 [1,] 0.297 0.310 0.290 0.220 0.1560 [2,] 0.360 0.390 0.369 0.297 0.2050 [3,] 0.075 0.058 0.047 0.034 0.0230 [4,] 0.114 0.100

Hi, Maybe somebody could help me with my problem installing R on my PowerBook G3/292 with MkLinux DR3 installed on the internal HD: When installing R with rpm -Uhv R-base-0.63-3.ppc.rpm I got the following message: /var/tmp/rpm-tmp.47537: [: !=: unary operator expected /var/tmp/rpm-tmp.47537: /bin/R: no such file or directory execution of script failed error:

Hello everybody: Does any one has a function to build Chernoff faces? Thank you very much Kenneth Roy Cabrera Torres krcabrer at epm.net.co -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not

Hi R users: I will like to know if somebody works on insurance statistics (actuarial problems) and had use TRICAST, and can tell me if with all the R tools it can be build a solution like TRICAST or similar. In a word: Do you think that R has all the statistical tools (I mean modeling tools) to make a job similar to TRICAST? Does TRICAST has modeling tools that are not implemented on R yet?

Hello Dear R Developers and Users: I'm trying to compile R with all the tools of the CRAN page. I compile the R-1.2.2 version without problem. But when I try to compile the development version 1.3.0 it doesn't work when I write the command: make BUILD=MINGW32 First it shows me something like this (I think without problems): As I make when I compile succesfuly the R-1.2.2 version:

Hello Dear R Developers and Users: I'm trying to compile R with all the tools of the CRAN page. I compile the R-1.2.2 version without problem. But when I try to compile the development version 1.3.0 it doesn't work when I write the command: make BUILD=MINGW32 First it shows me something like this (I think without problems): As I make when I compile succesfuly the R-1.2.2 version:

Hello All: I am trying to replicate the results of an example found in Alan Agresti's "Categorical Data Analysis" on pages 267-269. The example is one of a 2 x 2 cross-classification table of ordinal counts: job satisfaction and income. I am able to get Agresti's results for the independence model (G^2 = 12.03 with df = 9) assuming as he does that the data is nominal, but

Hi R users: I will like to have a legend with math symbols and also with the value of a variable. But I cannot obtain both at the same time (symbol + value of a variable): Here is a reproducible example: m1<-5 m2<-12 plot(1:5,1:5,type="n") legend("topleft",legend=c(paste(expression(mu),"=",m1),expression(paste(mu,"=",m2))),lty=1:2) Thank you for

Hi R users: I will like to have a legend with math symbols and also with the value of a variable. But I cannot obtain both at the same time (symbol + value of a variable): Here is a reproducible example: m1<-5 m2<-12 plot(1:5,1:5,type="n") legend("topleft",legend=c(paste(expression(mu),"=",m1),expression(paste(mu,"=",m2))),lty=1:2) Thank you for

Hello R users, I am doing some work with a large data set but am running out of memory. I understand that R dynamically loads memory as it needs it, but for some reason it cannot seem to find my virtual memory. It's limit is about 256M (my hard memory) regardless of the amount of virtual memory. I'm running R 1.30 on Windows NT. Am I missing an easy fix here? Many thanks in advance,

Hi R users: I got an error that "l1" is not found. This is a sample code: f1<-function(i,l1){ print(l1[[i]]) l1[[i+1]]<<-i return(i) } z1<-list(x=100,NULL,a=c(1,1)) lapply(1:3,f1,l1=z1) My final goal is to update the value of each list component to use it in the following step. I see that print function founds l1[[1]], but the assign instruction not. Thank you

Hallo all Suppose I have a summary amount of various colours used in different areas colour plastic paint black 15.5 173.8 brown 6.0 523.2 green 2.5 6.4 red 77.1 237.4 yellow 144.6 77.3 It seems that there are some preferable colours in these two areas (yellow in plastic, brown an red in paint). The problem seems to me similar to chi square test but it is intended for testing counts or

Hi R users: I got this code to generate a graphic for each member of a lists. list1<-list(A=data.frame(x=c(1,2),y=c(5,6)),B=data.frame(x=c(8,9),y=c(12,6))) names1<-names(list1) sapply(1:length(list1),function(i) with(list1[[i]],plot(x,y,type="l",main=paste("Graphic of",names1[i])))) Is there a more elegant solution for not to use two separate lists? I would like to