similar to: ARULES --> Filtering Rules by RHS

Dear Collegues, it seems like there is a problem with the image()-method in the package arules. Using an ordninary matrix works fine: image(matrix(rnorm(200), 10, 20), axes = FALSE, col=brewer.pal(9, "Blues") ) delivers an image with blue colors and no axes. Using an object of the class "associations" (arules package) does not work: image(items(ta.eclat), axes = FALSE,

Dear Colleagues, does anybody know how to aggregate a data.frame using different functions for different columns? Sincerely ___________________ Markus Preisetanz Consultant Client Vela GmbH Albert-Roßhaupter-Str. 32 81369 München fon: +49 (0) 89 742 17-113 fax: +49 (0) 89 742 17-150 mailto:markus.preisetanz@clientvela.com

Dear Colleagues: I have 3 numeric variables (say x, y, z) in a data.frame and want to draw a 2D-scatterplot with the 3rd dimension as color, if possible without having to convert the whole thing to an appropiate matrix for image() manually. Can e.g. scatterplot3d do something like this? There's a function xyz.convert, but I couldn't find the way to use it properly. Sincerly,

Dear Colleagues, I've been looking for a function that can perform a tree analysis, similar to CHAID or QUEST. The key point is that in this case the variables are not binary but nominal (10 different values), so "tree" (from the tree package) won't work. Does anybody know help? Sincerely, ___________________ Markus Preisetanz Consultant Client Vela GmbH

Dear Colleagues, does anybody know how to add dimnames to an image. Right now I'm using image(as.matrix(df3), col=brewer.pal(9,"Blues")) where df3 is a data.frame. dimnames(as.matrix(df3)) delivers [[1]] [1] "RFM_A1" "RFM_A2" "RFM_A4" "RFM_A5" "RFM_A7" "RFM_B3" "RFM_B6" "RFM_B7"

Dear R Specialists, when trying to cluster a data.frame with about 80.000 rows and 25 columns I get the above error message. I tried hclust (using dist), agnes (entering the data.frame directly) and pam (entering the data.frame directly). What I actually do not want to do is generate a random sample from the data. The machine I run R on is a Windows 2000 Server (Pentium 4) with 2 GB of

Dear Collegues, when using sqlQuery from the package RODBC I always get a data frame with automatically generated rownames, even if: * the first column of the query is called rownames using "Select ... AS rownames, ... From ..." * and: the values from this column are unique * and: the values are inevitably forced to character data with e.g. " 'rn_' + CAST(xy AS

Dear Collegues, does anybody know how I can place a legend at a sensible position in a star diagram automatically? The legend should tell the name of the variable (from colnames) for every color used. Sincerely, Markus ___________________ Markus Preisetanz Consultant Client Vela GmbH Albert-Roßhaupter-Str. 32 81369 München fon: +49 (0) 89 742 17-113 fax:

Ein eingebundener Text mit undefiniertem Zeichensatz wurde abgetrennt. Name: nicht verf?gbar URL: https://stat.ethz.ch/pipermail/r-help/attachments/20060807/7f387274/attachment.pl

Hi group, My case has N physicians with each seeing M patients. One physician could have seen a group of patients, or, a patient could have been seen by multiple number of physicians. In order words, there are overlaps. Now, I have the following NxM matrix Patient#1 Patient#2 Patient#3 ....... Patient#m Physician#1 1 0 1 ....... 0 Physician#2

I am new to R( but quickly being awed by the range of this it can accomplish, you have one more convert to the useR universe). I have successfully implemented the apriori function and are getting great results. My question concerns how to export these results. I have read lots about write.csv functions and exporting data frames and other standard objects. Im having difficulty working with these S4

Buenas tardes, Necesito ayuda con la función inspect() del paquete "arules". Mis comandos son: r1 <- apriori(tran, parameter=list(support=0.012, confidence=0.7)) r1 summary(r1) #todo bien, tengo 5 reglas y todo claro en el resume #pero al pedir inspect(r1) inspect(sort(r1, by = "confidence")) me arroja el error: Error en UseMethod("inspect", x) : no

Hello, I was fiddling with TableGen (for a use that has nothing to do with a compiler but it's doesn't matter) and TableGen triggers an assertion failure on this code (I reduced the case to the minimum, it's a parsing bug): class Bli<string _t> { string t = _t; } class Bla<list<Bli> _bli> : Bli<!car(_bli).t> { } #0 0x00007ffff6ebda75 in *__GI_raise

Hello R-help subscribers, I am analyzing a data set using a mixed logit model, and I have recently discovered some curious behavior. I am hoping you all can help. I first ran the following model in December 2012. lmer(Response.binary ~ ItemType.c * Block + (1 | Subject) + (1 | Word), data=lexdec, family="binomial") I then took a break from the data for the holidays. I returned to

On Sep 1, 2010, at 4:35 AM, Amaury Pouly wrote: > Hello, > I was fiddling with TableGen (for a use that has nothing to do with a compiler but it's doesn't matter) and TableGen triggers an assertion failure on this code (I reduced the case to the minimum, it's a parsing bug): David, can you take a look? This is related to your lisp interpreter :) -Chris > > class

HI all, Somebody had tried to do a rebuild of RedHat Storage Server 2.0 and RHEV 3.2 hypervisor with CentOS? Mock is an option to accomplish this? Thanks.

Dear all, I was wondering if it is possible in TableGen to either: 1. Selectively define an instruction depending on an SDNode's properties, e.g. if the SDNode is not commutative. 2. Override/ignore the TableGen error given when a commutative node has an immediate on the LHS. My case comes from trying to define a generic ALU operation multiclass for my target, which includes a

Paul.White@dsto.defence.gov.au wrote: > > > Hello bug people, > > > > Version: > > platform = i686-pc-linux-gnu > > arch = i686 > > os = linux-gnu > > system = i686, linux-gnu > > status = > > major = 1 > > minor = 3.1 > > year = 2001 > > month = 08 > > day = 31 > > language = R > > > >

(1) There are no lists here! You have numeric vectors, not lists. (2) The normal vector-recycling rules apply. It does 1 == 4, 2 == 5, 3 == 4, 4 == 5, 5 == 4, .... Try > 1:10 == 5:4 [1] FALSE FALSE FALSE TRUE TRUE FALSE FALSE FALSE FALSE FALSE (3) For what you appear to want > x %in% 4:5 [1] FALSE FALSE FALSE TRUE TRUE FALSE FALSE FALSE FALSE FALSE is the way to get it.

Feature request: I want to use update.formula to subtract an intercept (or other) term from a formula with a dot on the RHS. However, as this causes an error, I propose a patch below. Thus, I want: > update.formula(y ~ ., ~ . -1) [1] y ~ . - 1 Instead I get this error: Error in terms.formula(tmp, simplify = TRUE) : '.' in formula and no 'data' argument While the error