similar to: inserting one backslash

Hello, it is likely that I will have to analyze a rather sizeable dataset: 60000 records, 10 to 15 variables. I will have to make descriptive statistics, and estimate linear models, glm's and maybe Cox proportional hazard model with time varying covariates. In theory, this is possible in R, but I would like to get some feedback on the equipment I should get for this. At this moment, I have a

R Version 1.9.1 (2004-06-21) Mac OS X.3.5 Dual 2GHz PowerPC G5 GUI = "AQUA" I have a data.frame comprising percentiles with the column headings containing % characters, e.g. > (pp <- colnames(temp2)) [1] "5%" "10%" "25%" "50%" "75%" "90%" "95%" I use xtable to convert the data.frame to Latex but I want to

Hello everybody, this might be a trivial question, but I have been unable to find this using Google. I am trying to replace double backslashes with single backslashes using gsub. There seems to be some unexpected behaviour with regards to the replacement string "\\". The following example uses the string C:\\ which should be converted to C:\ . > gsub("\\\\",

The following code works, to gsub single quotes to double quotes: line <- gsub("'", '"', line) (that's a single quote within doubles then a double within singles if your viewer's font is not good). But The R Language Manual tells me that Quotes and other special characters within strings are specified using escape sequences: \' single quote \"

I want to replace \\ with \ in: str <- "C:\\DOKUME~1\\u0327336\\LOKALE~1\\Temp\\RtmpQ5NJ8X\\TIRIS_PICS\\1_Img.jpg" and tried: gsub("\\\\", "\\", str) but this removes the \\ without replacing them by \ Any help much appreciated, Kay ----- ------------------------ Kay Cichini Postgraduate student Institute of Botany Univ. of Innsbruck ------------------------

Hello, Can anyone help on gsub() in R? I have a string like something below, and wanted to delete all the strings with leading backslash, including "\xa0On", "\023, "\xab", and many others. How should I write a regular expression pattern in gsub()? I don't care how many characters following backslash. txt <- "Is This Thing\xa0On? http://bit.ly/jAbKem

Greeting R Community, I am a windows user so this problem may be specific to windows. I often want to source files from within R such as: C:\Users\Rinker\Desktop\Research & Law\Data\School Data 09-10. To source this file I need to go through the path and replace all the backslashes (\) with forward slashes (/). I usually do this in MS Word using the replace option, however, I'd like

How can I get a single backslash in a character string? My goal is to escape dots in a string that will be used as a regular expression. I thought I could do it this way: gsub(".", "\\.", x) Unfortunately, "\\" does not represent a literal backslash as I expected, but rather a pair of backslashes: > "\\." [1] "\\." > "\\" [1]

Hello, I am afraid I do not fully understand all intricacies of programming in lattice plots. In the code below I try to plot an ROC curve, following R-news 4(1). When I condition on the variable 'group' I get the error message below, when I plot the curve for all data (i.e., y ~ pred.prob), I get the plot I want. Can someone point out why conditioning gives that message? Thanks, Ruud

How to use sub, gsub, etc. to replace "\" in a string to "/"? For example,convert "C:\foo\bar" to "C:/foo/bar". Thanks, Shengqiao Li

Full_Name: FAN Version: 2.4.0 OS: Windows Submission from: (NULL) (159.50.101.9) These are expected: > grep("[\-|c]", c("a-a","b")) [1] 1 > gsub("[\-|c]", "&", c("a-a","b")) [1] "a&a" "b" but these are strange: > grep("[d|\-|c]", c("a-a","b")) integer(0)

I am trying to check for backslashes in data, then remove them when I find them, but am having a difficult time figuring out the best way to do it. I know the backslash is the escape character in R, and I should be able to use 'gsub' to accomplish this, but I all I seem to be getting are errors. For example: If entry is: "Hello\World" I want: "HelloWorld"

I'm trying to use the regexpr function to locate the decimal in a character string. Regardless of the position of the decimal, the function returns 1. For example, > regexpr(".", "Female.Alabama") [1] 1 attr(,"match.length") [1] 1 In trying to figure out what was going on here, I tried the below command: > gsub(".", ",",

Dear developeRs, I thought that backslashes can be escaped in the usual way (and I think I did this before) but I can't see why R> gsub("\\", "x", "\alpha") Error in gsub(pattern, replacement, x, ignore.case, extended, fixed, useBytes) : invalid regular expression '\' gives an error. Or am I just blind? Best, Torsten R> version

Hello, I am about to order a new workstation at my university that will be used for R (and other research related tasks). I would appreciate any feedback on the specifications of a very fast machine. The machine should run windows (XP probably better than vista). Which chip, memory size and specification, etc should I be looking for? Thanks, Ruud [[alternative HTML version deleted]]

Dear helpers, I'm trying to replace a character with a unicode code inside a data frame using gsub(), but unsuccessfully. > data.frame(animals=c("dog","wolf","cat"))->my.data > gsub("o","\u0254",my.data$animals)->my.data$animals > my.data$animals [1] "d??g" "w??lf" "cat" It's not that a data

Hello Everyone, I am an avid Sweave user and I am trying to pretty print floating point numbers for latex output. For example in my document, I would like: 4.2\cdot 10^-{8} Instead of: 4.2e-08 The Hmisc package has a nice function for doing this- but Hmisc has a ton of dependencies and has proved very unportable to the various machines I work on. So, I set out to write my own function that

Hello, I have estimated a survival model with six strata: >model.b <- survfit(Surv(time=start.tijd,time2=eind.tijd2,event=va)~strata(product.code) , data=wu.wide) I would like to save the output of >print(model.b,print.n="records",show.rmean=FALSE) in a dataframe so that I can export it later. How do I do this? Note that summary(model.b) gives an error: Error in

I noticed this issue in stringr::str_replace, but it also affects sub() in base R. If the pattern in a call to one of these needs to be a regular expression, then backslashes in the replacement text are treated specially. For example, gsub("a|b", "\\", "abcdef") gives "def", not "\\\\def" as I wanted. To get the latter, I need to escape

I have a path: path = "/nfs/users/nfs_n/ns9/ Phenotype Analysis/Results/Run_AmplRatio_neg BinaryAll trained without akapn+tnik.csv" I wish to replace the spaces with "\ " so that it can be read by a system call to unix. Using gsub I try: > gsub(" ","\\ ",path) [1] "/nfs/users/nfs_n/ns9/Phenotype Analysis/Results/Run_AmplRatio_neg BinaryAll